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| From | Mark Lawrence <breamoreboy@yahoo.co.uk> |
| Subject | Re: get each pair from a string. |
| Date | Wed, 24 Oct 2012 13:14:48 +0100 |
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On 24/10/2012 10:32, wxjmfauth@gmail.com wrote: > Le mardi 23 octobre 2012 18:41:45 UTC+2, Ian a écrit : >> On Tue, Oct 23, 2012 at 12:47 AM, <wxjmfauth@gmail.com> wrote: >> >> >> >> In any case, have you been following the progress of issue 16061? >> >> There is a patch for the str.replace regression that you identified, >> >> which results in better performance across the board than 3.2. So >> >> although 3.3 is slower than 3.2 on this one microbenchmark, 3.4 will >> >> not be. > > Yes. > A workaround to solve one of the corner cases of something > which is wrong by design. > > jmf > Do you get paid money for acting as a complete moron or do you do it for free? -- Cheers. Mark Lawrence.
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Re: get each pair from a string. rusi <rustompmody@gmail.com> - 2012-10-22 09:19 -0700
Re: get each pair from a string. rusi <rustompmody@gmail.com> - 2012-10-22 21:59 -0700
Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-22 23:47 -0700
Re: get each pair from a string. Neil Cerutti <neilc@norwich.edu> - 2012-10-23 12:30 +0000
Re: get each pair from a string. Mark Lawrence <breamoreboy@yahoo.co.uk> - 2012-10-23 13:44 +0100
Re: get each pair from a string. Ian Kelly <ian.g.kelly@gmail.com> - 2012-10-23 10:41 -0600
Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-24 02:32 -0700
Re: get each pair from a string. Mark Lawrence <breamoreboy@yahoo.co.uk> - 2012-10-24 13:14 +0100
Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-24 02:32 -0700
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