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Groups > comp.lang.python > #31929

Re: get each pair from a string.

From Mark Lawrence <breamoreboy@yahoo.co.uk>
Subject Re: get each pair from a string.
Date 2012-10-23 13:44 +0100
References <CALyJZZURWQxgPTQcQo8kOdHkaOYbB6YE=U=vi6VrX9FoDH1gAQ@mail.gmail.com> <mailman.2594.1350845107.27098.python-list@python.org> <1a8e1d4b-dddc-48c6-aec8-8041bb559a30@u4g2000pbo.googlegroups.com> <177aa300-9863-44f3-94da-7bc11bff2eda@i7g2000pbf.googlegroups.com> <7fdadf96-2ec2-43c7-a5e2-74228c06faca@googlegroups.com>
Newsgroups comp.lang.python
Message-ID <mailman.2662.1350996101.27098.python-list@python.org> (permalink)

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On 23/10/2012 07:47, wxjmfauth@gmail.com wrote:
>
> Why bother with speeed?
>
> The latest Python version is systematically slower
> than the previous ones as soon as one uses non "ascii
> strings".
>
> Python users are discussing "code optimizations" without
> realizing the tool they are using, has killed itself its
> own performances.
>
> (Replace 'apple' with 'ap需')
>
> jmf
>

Please stop giving blatant lies on this list about Python speed.

-- 
Cheers.

Mark Lawrence.

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Thread

Re: get each pair from a string. rusi <rustompmody@gmail.com> - 2012-10-22 09:19 -0700
  Re: get each pair from a string. rusi <rustompmody@gmail.com> - 2012-10-22 21:59 -0700
    Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-22 23:47 -0700
      Re: get each pair from a string. Neil Cerutti <neilc@norwich.edu> - 2012-10-23 12:30 +0000
      Re: get each pair from a string. Mark Lawrence <breamoreboy@yahoo.co.uk> - 2012-10-23 13:44 +0100
      Re: get each pair from a string. Ian Kelly <ian.g.kelly@gmail.com> - 2012-10-23 10:41 -0600
        Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-24 02:32 -0700
          Re: get each pair from a string. Mark Lawrence <breamoreboy@yahoo.co.uk> - 2012-10-24 13:14 +0100
        Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-24 02:32 -0700

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