Groups > comp.lang.python > #32024

Re: get each pair from a string.

Newsgroups	comp.lang.python
Date	2012-10-24 02:32 -0700
References	(1 earlier) <mailman.2594.1350845107.27098.python-list@python.org> <1a8e1d4b-dddc-48c6-aec8-8041bb559a30@u4g2000pbo.googlegroups.com> <177aa300-9863-44f3-94da-7bc11bff2eda@i7g2000pbf.googlegroups.com> <7fdadf96-2ec2-43c7-a5e2-74228c06faca@googlegroups.com> <mailman.2674.1351010504.27098.python-list@python.org>
Subject	Re: get each pair from a string.
From	wxjmfauth@gmail.com
Message-ID	<mailman.2744.1351071141.27098.python-list@python.org> (permalink)

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Le mardi 23 octobre 2012 18:41:45 UTC+2, Ian a écrit :
> On Tue, Oct 23, 2012 at 12:47 AM,  <wxjmfauth@gmail.com> wrote:
> 
> 
> 
> In any case, have you been following the progress of issue 16061?
> 
> There is a patch for the str.replace regression that you identified,
> 
> which results in better performance across the board than 3.2.  So
> 
> although 3.3 is slower than 3.2 on this one microbenchmark, 3.4 will
> 
> not be.

Yes.
A workaround to solve one of the corner cases of something
which is wrong by design.

jmf

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Re: get each pair from a string. rusi <rustompmody@gmail.com> - 2012-10-22 09:19 -0700
  Re: get each pair from a string. rusi <rustompmody@gmail.com> - 2012-10-22 21:59 -0700
    Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-22 23:47 -0700
      Re: get each pair from a string. Neil Cerutti <neilc@norwich.edu> - 2012-10-23 12:30 +0000
      Re: get each pair from a string. Mark Lawrence <breamoreboy@yahoo.co.uk> - 2012-10-23 13:44 +0100
      Re: get each pair from a string. Ian Kelly <ian.g.kelly@gmail.com> - 2012-10-23 10:41 -0600
        Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-24 02:32 -0700
          Re: get each pair from a string. Mark Lawrence <breamoreboy@yahoo.co.uk> - 2012-10-24 13:14 +0100
        Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-24 02:32 -0700

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