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Groups > comp.lang.python > #31941

Re: get each pair from a string.

References <CALyJZZURWQxgPTQcQo8kOdHkaOYbB6YE=U=vi6VrX9FoDH1gAQ@mail.gmail.com> <mailman.2594.1350845107.27098.python-list@python.org> <1a8e1d4b-dddc-48c6-aec8-8041bb559a30@u4g2000pbo.googlegroups.com> <177aa300-9863-44f3-94da-7bc11bff2eda@i7g2000pbf.googlegroups.com> <7fdadf96-2ec2-43c7-a5e2-74228c06faca@googlegroups.com>
From Ian Kelly <ian.g.kelly@gmail.com>
Date 2012-10-23 10:41 -0600
Subject Re: get each pair from a string.
Newsgroups comp.lang.python
Message-ID <mailman.2674.1351010504.27098.python-list@python.org> (permalink)

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On Tue, Oct 23, 2012 at 12:47 AM,  <wxjmfauth@gmail.com> wrote:
> The latest Python version is systematically slower
> than the previous ones as soon as one uses non "ascii
> strings".

No, it isn't.  You've previously demonstrated a *microbenchmark* where
3.3 is slower than 3.2.  This is a far cry from demonstrating that 3.3
is "systematically slower", and that larger claim is simply false.

In any case, have you been following the progress of issue 16061?
There is a patch for the str.replace regression that you identified,
which results in better performance across the board than 3.2.  So
although 3.3 is slower than 3.2 on this one microbenchmark, 3.4 will
not be.

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Re: get each pair from a string. rusi <rustompmody@gmail.com> - 2012-10-22 09:19 -0700
  Re: get each pair from a string. rusi <rustompmody@gmail.com> - 2012-10-22 21:59 -0700
    Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-22 23:47 -0700
      Re: get each pair from a string. Neil Cerutti <neilc@norwich.edu> - 2012-10-23 12:30 +0000
      Re: get each pair from a string. Mark Lawrence <breamoreboy@yahoo.co.uk> - 2012-10-23 13:44 +0100
      Re: get each pair from a string. Ian Kelly <ian.g.kelly@gmail.com> - 2012-10-23 10:41 -0600
        Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-24 02:32 -0700
          Re: get each pair from a string. Mark Lawrence <breamoreboy@yahoo.co.uk> - 2012-10-24 13:14 +0100
        Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-24 02:32 -0700

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