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Groups > comp.lang.python > #31928
| From | Neil Cerutti <neilc@norwich.edu> |
|---|---|
| Newsgroups | comp.lang.python |
| Subject | Re: get each pair from a string. |
| Date | 2012-10-23 12:30 +0000 |
| Organization | Norwich University |
| Message-ID | <aengvrFd3qdU1@mid.individual.net> (permalink) |
| References | <CALyJZZURWQxgPTQcQo8kOdHkaOYbB6YE=U=vi6VrX9FoDH1gAQ@mail.gmail.com> <mailman.2594.1350845107.27098.python-list@python.org> <1a8e1d4b-dddc-48c6-aec8-8041bb559a30@u4g2000pbo.googlegroups.com> <177aa300-9863-44f3-94da-7bc11bff2eda@i7g2000pbf.googlegroups.com> <7fdadf96-2ec2-43c7-a5e2-74228c06faca@googlegroups.com> |
On 2012-10-23, wxjmfauth@gmail.com <wxjmfauth@gmail.com> wrote: > Why bother with speeed? Because the differences between O(N), O(log(N)) and O(N ** 2) operations are often relevant. A Python string replace function experiencing a slow-down from previous versions doesn't absolve me from making informed choices of algorithm and implentation. -- Neil Cerutti
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Re: get each pair from a string. rusi <rustompmody@gmail.com> - 2012-10-22 09:19 -0700
Re: get each pair from a string. rusi <rustompmody@gmail.com> - 2012-10-22 21:59 -0700
Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-22 23:47 -0700
Re: get each pair from a string. Neil Cerutti <neilc@norwich.edu> - 2012-10-23 12:30 +0000
Re: get each pair from a string. Mark Lawrence <breamoreboy@yahoo.co.uk> - 2012-10-23 13:44 +0100
Re: get each pair from a string. Ian Kelly <ian.g.kelly@gmail.com> - 2012-10-23 10:41 -0600
Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-24 02:32 -0700
Re: get each pair from a string. Mark Lawrence <breamoreboy@yahoo.co.uk> - 2012-10-24 13:14 +0100
Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-24 02:32 -0700
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