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| From | Neil Cerutti <neilc@norwich.edu> |
| Newsgroups | comp.lang.python |
| Subject | Re: get each pair from a string. |
| Date | 23 Oct 2012 12:30:51 GMT |
| Organization | Norwich University |
| Lines | 12 |
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On 2012-10-23, wxjmfauth@gmail.com <wxjmfauth@gmail.com> wrote: > Why bother with speeed? Because the differences between O(N), O(log(N)) and O(N ** 2) operations are often relevant. A Python string replace function experiencing a slow-down from previous versions doesn't absolve me from making informed choices of algorithm and implentation. -- Neil Cerutti
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Re: get each pair from a string. rusi <rustompmody@gmail.com> - 2012-10-22 09:19 -0700
Re: get each pair from a string. rusi <rustompmody@gmail.com> - 2012-10-22 21:59 -0700
Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-22 23:47 -0700
Re: get each pair from a string. Neil Cerutti <neilc@norwich.edu> - 2012-10-23 12:30 +0000
Re: get each pair from a string. Mark Lawrence <breamoreboy@yahoo.co.uk> - 2012-10-23 13:44 +0100
Re: get each pair from a string. Ian Kelly <ian.g.kelly@gmail.com> - 2012-10-23 10:41 -0600
Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-24 02:32 -0700
Re: get each pair from a string. Mark Lawrence <breamoreboy@yahoo.co.uk> - 2012-10-24 13:14 +0100
Re: get each pair from a string. wxjmfauth@gmail.com - 2012-10-24 02:32 -0700
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