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Groups > sci.physics.relativity > #390720 > unrolled thread
| Started by | Peter Riedt <riedt1@yahoo.co.uk> |
|---|---|
| First post | 2016-08-23 23:24 -0700 |
| Last post | 2016-08-27 08:12 -0700 |
| Articles | 20 on this page of 103 — 12 participants |
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The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-23 23:24 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Poutnik <poutnik4nntp@gmail.com> - 2016-08-24 08:31 +0200
Re: The trajectory parameters a, t and v of some of Jupiter's moons Sylvia Else <sylvia@not.at.this.address> - 2016-08-24 16:38 +1000
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-23 23:43 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Sylvia Else <sylvia@not.at.this.address> - 2016-08-24 16:47 +1000
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-24 00:54 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Sylvia Else <sylvia@not.at.this.address> - 2016-08-24 18:25 +1000
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-24 01:34 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Sylvia Else <sylvia@not.at.this.address> - 2016-08-24 20:18 +1000
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-24 20:53 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Sylvia Else <sylvia@not.at.this.address> - 2016-08-25 16:08 +1000
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-25 01:11 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-26 19:35 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Sylvia Else <sylvia@not.at.this.address> - 2016-08-27 13:40 +1000
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-26 21:48 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Gary Harnagel <hitlong@yahoo.com> - 2016-08-27 05:19 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-09-06 08:34 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Prokaryotic Caspase Homolog <prokaryotic.caspase.homolog@gmail.com> - 2016-08-24 07:53 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Gary Harnagel <hitlong@yahoo.com> - 2016-08-24 09:42 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-24 18:18 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Sylvia Else <sylvia@not.at.this.address> - 2016-08-25 11:53 +1000
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-24 21:01 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Sylvia Else <sylvia@not.at.this.address> - 2016-08-25 16:11 +1000
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-08-25 08:44 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-25 01:19 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Prokaryotic Caspase Homolog <prokaryotic.caspase.homolog@gmail.com> - 2016-08-25 06:18 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-25 22:14 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-08-25 08:36 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-25 17:58 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons "Dono," <sa_ge@comcast.net> - 2016-08-25 18:47 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-25 19:36 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons "Dono," <sa_ge@comcast.net> - 2016-08-25 20:20 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-08-26 15:14 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-26 20:44 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-09-06 08:33 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Poutnik <poutnik4nntp@gmail.com> - 2016-08-24 11:08 +0200
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-08-24 07:48 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-24 17:54 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons "Dono," <sa_ge@comcast.net> - 2016-08-24 18:00 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-08-25 08:34 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons mlwozniak@wp.pl - 2016-08-25 02:46 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons "Dono," <sa_ge@comcast.net> - 2016-08-24 07:22 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-24 17:56 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons "Dono," <sa_ge@comcast.net> - 2016-08-24 18:02 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Tom Roberts <tjroberts137@sbcglobal.net> - 2016-08-24 11:36 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-24 18:03 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons mlwozniak@wp.pl - 2016-08-25 02:50 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Poutnik <poutnik4nntp@gmail.com> - 2016-08-24 11:07 +0200
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-24 17:38 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Prokaryotic Caspase Homolog <prokaryotic.caspase.homolog@gmail.com> - 2016-08-24 20:40 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Prokaryotic Caspase Homolog <prokaryotic.caspase.homolog@gmail.com> - 2016-08-26 04:01 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-26 19:54 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-08-25 08:32 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-08-24 07:46 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Prokaryotic Caspase Homolog <prokaryotic.caspase.homolog@gmail.com> - 2016-08-24 07:52 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-27 09:20 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Prokaryotic Caspase Homolog <prokaryotic.caspase.homolog@gmail.com> - 2016-08-27 10:59 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Prokaryotic Caspase Homolog <prokaryotic.caspase.homolog@gmail.com> - 2016-08-27 16:30 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-27 18:38 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Prokaryotic Caspase Homolog <prokaryotic.caspase.homolog@gmail.com> - 2016-08-27 20:45 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-27 22:06 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Prokaryotic Caspase Homolog <prokaryotic.caspase.homolog@gmail.com> - 2016-08-28 00:01 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-28 21:26 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Prokaryotic Caspase Homolog <prokaryotic.caspase.homolog@gmail.com> - 2016-08-29 04:55 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-29 19:20 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Prokaryotic Caspase Homolog <prokaryotic.caspase.homolog@gmail.com> - 2016-08-29 19:33 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Prokaryotic Caspase Homolog <prokaryotic.caspase.homolog@gmail.com> - 2016-08-29 20:00 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-09-06 11:34 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Prokaryotic Caspase Homolog <prokaryotic.caspase.homolog@gmail.com> - 2016-09-06 09:56 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-09-06 18:54 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Prokaryotic Caspase Homolog <prokaryotic.caspase.homolog@gmail.com> - 2016-09-06 19:59 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons John Gogo <jfgogo22@yahoo.com> - 2016-09-06 20:07 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-09-06 21:47 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Python <python@org.invalid> - 2016-09-07 10:41 +0200
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-09-07 07:45 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-09-10 19:07 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-09-11 17:49 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-09-11 18:02 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-09-11 20:08 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-09-12 00:48 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-09-12 07:34 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons John Gogo <jfgogo22@yahoo.com> - 2016-09-06 19:40 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-09-06 19:21 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-09-07 07:32 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-09-07 19:38 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-09-08 11:20 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-09-08 11:10 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-09-06 11:27 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-27 23:57 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-23 23:39 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Poutnik <poutnik4nntp@gmail.com> - 2016-08-24 11:12 +0200
Re: The trajectory parameters a, t and v of some of Jupiter's moons mlwozniak@wp.pl - 2016-08-24 02:41 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-08-24 07:50 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons mlwozniak@wp.pl - 2016-08-25 02:48 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-24 17:40 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-08-25 08:33 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-09-02 19:00 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Odd Bodkin <bodkinodd@gmail.com> - 2016-08-24 07:45 -0500
Re: The trajectory parameters a, t and v of some of Jupiter's moons Prokaryotic Caspase Homolog <prokaryotic.caspase.homolog@gmail.com> - 2016-08-24 07:43 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-24 17:59 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons astrofoton@interia.pl - 2016-08-26 10:30 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-26 20:37 -0700
Re: The trajectory parameters a, t and v of some of Jupiter's moons astrofoton@interia.pl - 2016-08-27 08:12 -0700
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| From | Peter Riedt <riedt1@yahoo.co.uk> |
|---|---|
| Date | 2016-08-23 23:24 -0700 |
| Subject | The trajectory parameters a, t and v of some of Jupiter's moons |
| Message-ID | <16888046-ab03-49fe-913b-4b50d92b6a31@googlegroups.com> |
The trajectory parameters a, t and v of some of Jupiter's moons as calculated by my gravity theory are: calc a calc days calc v IO 421821 1.80 17.0460 EUROPA 663385 3.61 13.3579 GANYMEDE 1057997 7.27 10.5759 CALLISTO 1861735 16.97 7.9781 METIS 124895 0.30 ANDRASTEA 127750 0.30 AMALTHEA 179581 0.51 THEBE 224739 0.69 compared to the official values: observed a observed days observed v IO 421800 1.80 17.340 EUROPA 671100 3.55 13.740 GANYMEDE 1070400 7.15 10.880 CALLISTO 1882700 16.69 8.204 METIS 128000 0.29 ANDRASTEA 129000 0.30 AMALTHEA 181400 0.50 THEBE 221900 0.70 GR cannot predict/calculate these values and therefore is not a gravity theory.
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| From | Poutnik <poutnik4nntp@gmail.com> |
|---|---|
| Date | 2016-08-24 08:31 +0200 |
| Message-ID | <npjev8$a57$1@dont-email.me> |
| In reply to | #390720 |
Dne 24/08/2016 v 08:24 Peter Riedt napsal(a): > The trajectory parameters a, t and v of some of Jupiter's moons > > as calculated by my gravity theory are: > ... > > GR cannot predict/calculate these values and therefore is not a gravity theory. > Do not fool yourself. -- Poutnik ( The Pilgrim, Der Wanderer ) Knowledge makes great men humble, but small men arrogant.
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| From | Sylvia Else <sylvia@not.at.this.address> |
|---|---|
| Date | 2016-08-24 16:38 +1000 |
| Message-ID | <e24tmkFjm47U1@mid.individual.net> |
| In reply to | #390720 |
On 24/08/2016 4:24 PM, Peter Riedt wrote: > The trajectory parameters a, t and v of some of Jupiter's moons > > as calculated by my gravity theory are: > > calc a calc days calc v > IO 421821 1.80 17.0460 > EUROPA 663385 3.61 13.3579 > GANYMEDE 1057997 7.27 10.5759 > CALLISTO 1861735 16.97 7.9781 > METIS 124895 0.30 > ANDRASTEA 127750 0.30 > AMALTHEA 179581 0.51 > THEBE 224739 0.69 > > compared to the official values: > > observed a observed days observed v > IO 421800 1.80 17.340 > EUROPA 671100 3.55 13.740 > GANYMEDE 1070400 7.15 10.880 > CALLISTO 1882700 16.69 8.204 > METIS 128000 0.29 > ANDRASTEA 129000 0.30 > AMALTHEA 181400 0.50 > THEBE 221900 0.70 > OK, I'm just going to come right out and accuse your faking these results, because your gravity theory, being independent of mass, is incapable of producing them. It's time to put up or shut up. Sylvia
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| From | Peter Riedt <riedt1@yahoo.co.uk> |
|---|---|
| Date | 2016-08-23 23:43 -0700 |
| Message-ID | <4956d139-3282-47fc-89b0-37820fd761b4@googlegroups.com> |
| In reply to | #390723 |
On Wednesday, August 24, 2016 at 2:38:15 PM UTC+8, Sylvia Else wrote: > On 24/08/2016 4:24 PM, Peter Riedt wrote: > > The trajectory parameters a, t and v of some of Jupiter's moons > > > > as calculated by my gravity theory are: > > > > calc a calc days calc v > > IO 421821 1.80 17.0460 > > EUROPA 663385 3.61 13.3579 > > GANYMEDE 1057997 7.27 10.5759 > > CALLISTO 1861735 16.97 7.9781 > > METIS 124895 0.30 > > ANDRASTEA 127750 0.30 > > AMALTHEA 179581 0.51 > > THEBE 224739 0.69 > > > > compared to the official values: > > > > observed a observed days observed v > > IO 421800 1.80 17.340 > > EUROPA 671100 3.55 13.740 > > GANYMEDE 1070400 7.15 10.880 > > CALLISTO 1882700 16.69 8.204 > > METIS 128000 0.29 > > ANDRASTEA 129000 0.30 > > AMALTHEA 181400 0.50 > > THEBE 221900 0.70 > > > > OK, I'm just going to come right out and accuse your faking these > results, because your gravity theory, being independent of mass, is > incapable of producing them. > > It's time to put up or shut up. > > Sylvia Irrespective of my theory being a fake, is GR a fake? I cannot calculate anything.
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| From | Sylvia Else <sylvia@not.at.this.address> |
|---|---|
| Date | 2016-08-24 16:47 +1000 |
| Message-ID | <e24u7cFjppjU1@mid.individual.net> |
| In reply to | #390725 |
On 24/08/2016 4:43 PM, Peter Riedt wrote: > On Wednesday, August 24, 2016 at 2:38:15 PM UTC+8, Sylvia Else wrote: >> On 24/08/2016 4:24 PM, Peter Riedt wrote: >>> The trajectory parameters a, t and v of some of Jupiter's moons >>> >>> as calculated by my gravity theory are: >>> >>> calc a calc days calc v >>> IO 421821 1.80 17.0460 >>> EUROPA 663385 3.61 13.3579 >>> GANYMEDE 1057997 7.27 10.5759 >>> CALLISTO 1861735 16.97 7.9781 >>> METIS 124895 0.30 >>> ANDRASTEA 127750 0.30 >>> AMALTHEA 179581 0.51 >>> THEBE 224739 0.69 >>> >>> compared to the official values: >>> >>> observed a observed days observed v >>> IO 421800 1.80 17.340 >>> EUROPA 671100 3.55 13.740 >>> GANYMEDE 1070400 7.15 10.880 >>> CALLISTO 1882700 16.69 8.204 >>> METIS 128000 0.29 >>> ANDRASTEA 129000 0.30 >>> AMALTHEA 181400 0.50 >>> THEBE 221900 0.70 >>> >> >> OK, I'm just going to come right out and accuse your faking these >> results, because your gravity theory, being independent of mass, is >> incapable of producing them. >> >> It's time to put up or shut up. >> >> Sylvia > > Irrespective of my theory being a fake, is GR a fake? I cannot calculate anything. > No, GR is the real thing, but it's complicated. Since you appear not to have the math skills, and since you won't accept that it reduces to Kepler's 3rd law for practical Solar System orbital mechanics purposes (Mercury excepted), there is no way that you can be convinced that it does the job. Sylvia.
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| From | Peter Riedt <riedt1@yahoo.co.uk> |
|---|---|
| Date | 2016-08-24 00:54 -0700 |
| Message-ID | <cbb1e62d-2fdd-4848-bbb7-4e3aeb3c0a9b@googlegroups.com> |
| In reply to | #390726 |
On Wednesday, August 24, 2016 at 2:47:11 PM UTC+8, Sylvia Else wrote: > No, GR is the real thing, but it's complicated. Since you appear not to > have the math skills, and since you won't accept that it reduces to > Kepler's 3rd law for practical Solar System orbital mechanics purposes > (Mercury excepted), there is no way that you can be convinced that it > does the job. > > Sylvia. I agree in principle. Wikipedia: "The Einstein field equations are nonlinear and very difficult to solve. Einstein used approximation methods in working out initial predictions of the theory. But as early as 1916, the astrophysicist Karl Schwarzschild found the first non-trivial exact solution to the Einstein field equations, the Schwarzschild metric". It is above my and everybody's ability but his theories are supported by the collusion of political correctness. On the other hand you have alluded a number of times to Kepler's 3rd. Kepler is the original source and if you are correct in that the problem of atv can be solved by his laws please attempt to do it.
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| From | Sylvia Else <sylvia@not.at.this.address> |
|---|---|
| Date | 2016-08-24 18:25 +1000 |
| Message-ID | <e253veFl5btU1@mid.individual.net> |
| In reply to | #390729 |
On 24/08/2016 5:54 PM, Peter Riedt wrote: > On Wednesday, August 24, 2016 at 2:47:11 PM UTC+8, Sylvia Else > wrote: > >> No, GR is the real thing, but it's complicated. Since you appear >> not to have the math skills, and since you won't accept that it >> reduces to Kepler's 3rd law for practical Solar System orbital >> mechanics purposes (Mercury excepted), there is no way that you can >> be convinced that it does the job. >> >> Sylvia. > > I agree in principle. Wikipedia: "The Einstein field equations are > nonlinear and very difficult to solve. Einstein used approximation > methods in working out initial predictions of the theory. But as > early as 1916, the astrophysicist Karl Schwarzschild found the first > non-trivial exact solution to the Einstein field equations, the > Schwarzschild metric". > > It is above my and everybody's ability but his theories are supported > by the collusion of political correctness. > > On the other hand you have alluded a number of times to Kepler's 3rd. > Kepler is the original source and if you are correct in that the > problem of atv can be solved by his laws please attempt to do it. > It requires knowledge of the central mass. You claim that your theory does not. Sylvia.
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| From | Peter Riedt <riedt1@yahoo.co.uk> |
|---|---|
| Date | 2016-08-24 01:34 -0700 |
| Message-ID | <10a59e80-0a8e-412e-8dc5-d019bfd9c2e9@googlegroups.com> |
| In reply to | #390730 |
On Wednesday, August 24, 2016 at 4:25:22 PM UTC+8, Sylvia Else wrote: > On 24/08/2016 5:54 PM, Peter Riedt wrote: > > On Wednesday, August 24, 2016 at 2:47:11 PM UTC+8, Sylvia Else > > wrote: > > > >> No, GR is the real thing, but it's complicated. Since you appear > >> not to have the math skills, and since you won't accept that it > >> reduces to Kepler's 3rd law for practical Solar System orbital > >> mechanics purposes (Mercury excepted), there is no way that you can > >> be convinced that it does the job. > >> > >> Sylvia. > > > > I agree in principle. Wikipedia: "The Einstein field equations are > > nonlinear and very difficult to solve. Einstein used approximation > > methods in working out initial predictions of the theory. But as > > early as 1916, the astrophysicist Karl Schwarzschild found the first > > non-trivial exact solution to the Einstein field equations, the > > Schwarzschild metric". > > > > It is above my and everybody's ability but his theories are supported > > by the collusion of political correctness. > > > > On the other hand you have alluded a number of times to Kepler's 3rd. > > Kepler is the original source and if you are correct in that the > > problem of atv can be solved by his laws please attempt to do it. > > > > It requires knowledge of the central mass. You claim that your theory > does not. > > Sylvia. The masses of the sun and Jupiter are well known. Perhaps you could do it to see if my calculations are similar. If they differ you may be right that I am wrong.
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| From | Sylvia Else <sylvia@not.at.this.address> |
|---|---|
| Date | 2016-08-24 20:18 +1000 |
| Message-ID | <e25aisFmpenU1@mid.individual.net> |
| In reply to | #390731 |
On 24/08/2016 6:34 PM, Peter Riedt wrote: > On Wednesday, August 24, 2016 at 4:25:22 PM UTC+8, Sylvia Else > wrote: >> On 24/08/2016 5:54 PM, Peter Riedt wrote: >>> On Wednesday, August 24, 2016 at 2:47:11 PM UTC+8, Sylvia Else >>> wrote: >>> >>>> No, GR is the real thing, but it's complicated. Since you >>>> appear not to have the math skills, and since you won't accept >>>> that it reduces to Kepler's 3rd law for practical Solar System >>>> orbital mechanics purposes (Mercury excepted), there is no way >>>> that you can be convinced that it does the job. >>>> >>>> Sylvia. >>> > >>> I agree in principle. Wikipedia: "The Einstein field equations >>> are nonlinear and very difficult to solve. Einstein used >>> approximation methods in working out initial predictions of the >>> theory. But as early as 1916, the astrophysicist Karl >>> Schwarzschild found the first non-trivial exact solution to the >>> Einstein field equations, the Schwarzschild metric". >>> >>> It is above my and everybody's ability but his theories are >>> supported by the collusion of political correctness. >>> >>> On the other hand you have alluded a number of times to Kepler's >>> 3rd. Kepler is the original source and if you are correct in that >>> the problem of atv can be solved by his laws please attempt to do >>> it. >>> >> >> It requires knowledge of the central mass. You claim that your >> theory does not. >> >> Sylvia. > > The masses of the sun and Jupiter are well known. Perhaps you could > do it to see if my calculations are similar. If they differ you may > be right that I am wrong. > The constant of proportionality in Kepler's third law is 4 * Pi^2 / (G * M) So we have P^2 / a^3 = 4 * Pi^2 / (G * M) P = sqrt(Pi^2 * a ^ 3 / (G * M)) Where the central body is the sun, the product G * M is known more accurately than either of the factors, being 1.32712440018(9)×10^20 The semi-major axis of Earth is 149,598,023 km Plugging those numbers in gives a value for P of 31558244.21 seconds, which is 365.26 days to two decimal places. Since the Earth's orbit is not circular, the velocity varies around the orbit. It can be approximated by taking the semi-major axis as the radius of a circle, calculating the circumference of the circle, and then apply distance divided by time. Indeed, that's not the only circularity involved, since the mass of the Sun was calculated by applying this formula in reverse to get G * M, and then dividing by the value of G determined by laboratory measurements. Sylvia.
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| From | Peter Riedt <riedt1@yahoo.co.uk> |
|---|---|
| Date | 2016-08-24 20:53 -0700 |
| Message-ID | <63967e50-2d34-418a-b8af-3ea6202e1066@googlegroups.com> |
| In reply to | #390737 |
On Wednesday, August 24, 2016 at 6:18:07 PM UTC+8, Sylvia Else wrote: > The constant of proportionality in Kepler's third law is 4 * Pi^2 / (G * M) > > So we have P^2 / a^3 = 4 * Pi^2 / (G * M) > > P = sqrt(Pi^2 * a ^ 3 / (G * M)) > > Where the central body is the sun, the product G * M is known more > accurately than either of the factors, being 1.32712440018(9)×10^20 > > The semi-major axis of Earth is 149,598,023 km > > Plugging those numbers in gives a value for P of 31558244.21 seconds, > which is 365.26 days to two decimal places. > > Sylvia. Thanks for the info. I got this for P=sqrt(PI^2*a^3/GM): P=sqrt(9.86960437853402*149598023^3/132720000000000000000) =498.9654411 Where did I go wrong?
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| From | Sylvia Else <sylvia@not.at.this.address> |
|---|---|
| Date | 2016-08-25 16:08 +1000 |
| Message-ID | <e27gbrF8a7rU1@mid.individual.net> |
| In reply to | #390822 |
On 25/08/2016 1:53 PM, Peter Riedt wrote: > On Wednesday, August 24, 2016 at 6:18:07 PM UTC+8, Sylvia Else wrote: > >> The constant of proportionality in Kepler's third law is 4 * Pi^2 / (G * M) >> >> So we have P^2 / a^3 = 4 * Pi^2 / (G * M) >> >> P = sqrt(Pi^2 * a ^ 3 / (G * M)) >> >> Where the central body is the sun, the product G * M is known more >> accurately than either of the factors, being 1.32712440018(9)×10^20 >> >> The semi-major axis of Earth is 149,598,023 km >> >> Plugging those numbers in gives a value for P of 31558244.21 seconds, >> which is 365.26 days to two decimal places. >> > >> Sylvia. > > Thanks for the info. I got this for P=sqrt(PI^2*a^3/GM): > > P=sqrt(9.86960437853402*149598023^3/132720000000000000000) > =498.9654411 > > Where did I go wrong? > You need to express the semi-major axis in metres, not kilometers. Note that I lost the four when writing out the expression for P, so you need to put it back in. P = sqrt(4 * Pi^2 * a ^ 3 / (G * M)) Sylvia.
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| From | Peter Riedt <riedt1@yahoo.co.uk> |
|---|---|
| Date | 2016-08-25 01:11 -0700 |
| Message-ID | <159b7990-ed3a-4af4-b2c1-8e59cbac1081@googlegroups.com> |
| In reply to | #390826 |
On Thursday, August 25, 2016 at 2:09:01 PM UTC+8, Sylvia Else wrote: > On 25/08/2016 1:53 PM, Peter Riedt wrote: > > On Wednesday, August 24, 2016 at 6:18:07 PM UTC+8, Sylvia Else wrote: > > > >> The constant of proportionality in Kepler's third law is 4 * Pi^2 / (G * M) > >> > >> So we have P^2 / a^3 = 4 * Pi^2 / (G * M) > >> > >> P = sqrt(Pi^2 * a ^ 3 / (G * M)) > >> > >> Where the central body is the sun, the product G * M is known more > >> accurately than either of the factors, being 1.32712440018(9)×10^20 > >> > >> The semi-major axis of Earth is 149,598,023 km > >> > >> Plugging those numbers in gives a value for P of 31558244.21 seconds, > >> which is 365.26 days to two decimal places. > >> > > > >> Sylvia. > > > > Thanks for the info. I got this for P=sqrt(PI^2*a^3/GM): > > > > P=sqrt(9.86960437853402*149598023^3/132720000000000000000) > > =498.9654411 > > > > Where did I go wrong? > > > > You need to express the semi-major axis in metres, not kilometers. > > Note that I lost the four when writing out the expression for P, so you > need to put it back in. > > P = sqrt(4 * Pi^2 * a ^ 3 / (G * M)) > > Sylvia. Thanks.
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| From | Peter Riedt <riedt1@yahoo.co.uk> |
|---|---|
| Date | 2016-08-26 19:35 -0700 |
| Message-ID | <896ee86c-9d1f-495e-8755-e95001a4caa8@googlegroups.com> |
| In reply to | #390826 |
On Thursday, August 25, 2016 at 2:09:01 PM UTC+8, Sylvia Else wrote: > On 25/08/2016 1:53 PM, Peter Riedt wrote: > > On Wednesday, August 24, 2016 at 6:18:07 PM UTC+8, Sylvia Else wrote: > > > >> The constant of proportionality in Kepler's third law is 4 * Pi^2 / (G * M) > >> > >> So we have P^2 / a^3 = 4 * Pi^2 / (G * M) > >> > >> P = sqrt(Pi^2 * a ^ 3 / (G * M)) > >> > >> Where the central body is the sun, the product G * M is known more > >> accurately than either of the factors, being 1.32712440018(9)×10^20 > >> > >> The semi-major axis of Earth is 149,598,023 km > >> > >> Plugging those numbers in gives a value for P of 31558244.21 seconds, > >> which is 365.26 days to two decimal places. > >> > > > >> Sylvia. > > > > Thanks for the info. I got this for P=sqrt(PI^2*a^3/GM): > > > > P=sqrt(9.86960437853402*149598023^3/132720000000000000000) > > =498.9654411 > > > > Where did I go wrong? > > > > You need to express the semi-major axis in metres, not kilometers. > > Note that I lost the four when writing out the expression for P, so you > need to put it back in. > > P = sqrt(4 * Pi^2 * a ^ 3 / (G * M)) > > Sylvia. Your formula sqrt(4pi^2*am^3/GM) does produce the orbital times of the planets but it uses GM and it is based on Kepler not GR. How does GR predict/calculate t, a and v of the planets and the moons of Jupiter? My theory of Gravity can do it and do it without using G, M and GM. Can GR do it?
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| From | Sylvia Else <sylvia@not.at.this.address> |
|---|---|
| Date | 2016-08-27 13:40 +1000 |
| Message-ID | <e2cgclFeq1vU1@mid.individual.net> |
| In reply to | #391020 |
On 27/08/2016 12:35 PM, Peter Riedt wrote: > On Thursday, August 25, 2016 at 2:09:01 PM UTC+8, Sylvia Else wrote: >> On 25/08/2016 1:53 PM, Peter Riedt wrote: >>> On Wednesday, August 24, 2016 at 6:18:07 PM UTC+8, Sylvia Else wrote: >>> >>>> The constant of proportionality in Kepler's third law is 4 * Pi^2 / (G * M) >>>> >>>> So we have P^2 / a^3 = 4 * Pi^2 / (G * M) >>>> >>>> P = sqrt(Pi^2 * a ^ 3 / (G * M)) >>>> >>>> Where the central body is the sun, the product G * M is known more >>>> accurately than either of the factors, being 1.32712440018(9)×10^20 >>>> >>>> The semi-major axis of Earth is 149,598,023 km >>>> >>>> Plugging those numbers in gives a value for P of 31558244.21 seconds, >>>> which is 365.26 days to two decimal places. >>>> >>> >>>> Sylvia. >>> >>> Thanks for the info. I got this for P=sqrt(PI^2*a^3/GM): >>> >>> P=sqrt(9.86960437853402*149598023^3/132720000000000000000) >>> =498.9654411 >>> >>> Where did I go wrong? >>> >> >> You need to express the semi-major axis in metres, not kilometers. >> >> Note that I lost the four when writing out the expression for P, so you >> need to put it back in. >> >> P = sqrt(4 * Pi^2 * a ^ 3 / (G * M)) >> >> Sylvia. > > Your formula sqrt(4pi^2*am^3/GM) does produce the orbital times of the planets but it uses GM and it is based on Kepler not GR. > > How does GR predict/calculate t, a and v of the planets and the moons of Jupiter? My theory of Gravity can do it and do it without using G, M and GM. Can GR do it? > As has been stated before, GR reduces to this formula in this situation. If you won't believe that, then I don't know how to convince you, because you don't have the mathematical abilities to follow the derivation. Yes, it uses GM because it has to depend on the central mass. Your unpublished, secret, and undescribed theory, either has to do so in some way, or it will be incapable of handling different central masses, and will inevitably produce the same (wrong except for some specific central mass) results, regardless of the central mass. Since I'm tired of repeating myself, I'm not going to respond further to you in this thread until you give details of your alleged theory. Sylvia.
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| From | Peter Riedt <riedt1@yahoo.co.uk> |
|---|---|
| Date | 2016-08-26 21:48 -0700 |
| Message-ID | <c2b9cc11-e4db-4c16-9592-e2d9355cd1c8@googlegroups.com> |
| In reply to | #391028 |
On Saturday, August 27, 2016 at 11:40:08 AM UTC+8, Sylvia Else wrote: > On 27/08/2016 12:35 PM, Peter Riedt wrote: > > On Thursday, August 25, 2016 at 2:09:01 PM UTC+8, Sylvia Else wrote: > >> On 25/08/2016 1:53 PM, Peter Riedt wrote: > >>> On Wednesday, August 24, 2016 at 6:18:07 PM UTC+8, Sylvia Else wrote: > >>> > >>>> The constant of proportionality in Kepler's third law is 4 * Pi^2 / (G * M) > >>>> > >>>> So we have P^2 / a^3 = 4 * Pi^2 / (G * M) > >>>> > >>>> P = sqrt(Pi^2 * a ^ 3 / (G * M)) > >>>> > >>>> Where the central body is the sun, the product G * M is known more > >>>> accurately than either of the factors, being 1.32712440018(9)×10^20 > >>>> > >>>> The semi-major axis of Earth is 149,598,023 km > >>>> > >>>> Plugging those numbers in gives a value for P of 31558244.21 seconds, > >>>> which is 365.26 days to two decimal places. > >>>> > >>> > >>>> Sylvia. > >>> > >>> Thanks for the info. I got this for P=sqrt(PI^2*a^3/GM): > >>> > >>> P=sqrt(9.86960437853402*149598023^3/132720000000000000000) > >>> =498.9654411 > >>> > >>> Where did I go wrong? > >>> > >> > >> You need to express the semi-major axis in metres, not kilometers. > >> > >> Note that I lost the four when writing out the expression for P, so you > >> need to put it back in. > >> > >> P = sqrt(4 * Pi^2 * a ^ 3 / (G * M)) > >> > >> Sylvia. > > > > Your formula sqrt(4pi^2*am^3/GM) does produce the orbital times of the planets but it uses GM and it is based on Kepler not GR. > > > > How does GR predict/calculate t, a and v of the planets and the moons of Jupiter? My theory of Gravity can do it and do it without using G, M and GM. Can GR do it? > > > > As has been stated before, GR reduces to this formula in this situation. > If you won't believe that, then I don't know how to convince you, > because you don't have the mathematical abilities to follow the derivation. > > Yes, it uses GM because it has to depend on the central mass. Your > unpublished, secret, and undescribed theory, either has to do so in some > way, or it will be incapable of handling different central masses, and > will inevitably produce the same (wrong except for some specific central > mass) results, regardless of the central mass. > > Since I'm tired of repeating myself, I'm not going to respond further to > you in this thread until you give details of your alleged theory. > > > Sylvia. I agree. GR must refer to Kepler because GR is not a gravity science. The sad thing is that GR is held to be the authority and Kepler is ignored. Reality is replaced by illusions. Credits are manufactured. The real scientists are Galileo, Kepler, Huygens, Hooke and Ismael Bullialdus.
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| From | Gary Harnagel <hitlong@yahoo.com> |
|---|---|
| Date | 2016-08-27 05:19 -0700 |
| Message-ID | <7906ef92-4c44-42a3-83e2-912e88e524be@googlegroups.com> |
| In reply to | #391031 |
On Friday, August 26, 2016 at 10:48:57 PM UTC-6, Peter Riedt wrote: > > Reality is replaced by illusions. This describes your nonsense perfectly. You are full of baloney.
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| From | Odd Bodkin <bodkinodd@gmail.com> |
|---|---|
| Date | 2016-09-06 08:34 -0500 |
| Message-ID | <nqmgl5$17pf$2@gioia.aioe.org> |
| In reply to | #391031 |
On 8/26/2016 11:48 PM, Peter Riedt wrote: > The sad thing is that GR is held to be the authority and Kepler is ignored. That's simply not true. When you open a freshman physics book, Peter, do you see Kepler's laws or do you see General Relativity? Where did you ever get the impression that Kepler is ignored? -- Odd Bodkin --- maker of fine toys, tools, tables
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| From | Prokaryotic Caspase Homolog <prokaryotic.caspase.homolog@gmail.com> |
|---|---|
| Date | 2016-08-24 07:53 -0700 |
| Message-ID | <fab828e0-c6bf-40ec-b5b6-52f9b6efaf84@googlegroups.com> |
| In reply to | #390731 |
On Wednesday, August 24, 2016 at 3:34:54 AM UTC-5, Peter Riedt wrote: > On Wednesday, August 24, 2016 at 4:25:22 PM UTC+8, Sylvia Else wrote: > > It requires knowledge of the central mass. You claim that your theory > > does not. > > > > Sylvia. > > The masses of the sun and Jupiter are well known. Perhaps you could do it to see if my calculations are similar. If they differ you may be right that I am wrong. But you claim not to need those masses to perform your calculations. SHOW YOUR WORK.
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| From | Gary Harnagel <hitlong@yahoo.com> |
|---|---|
| Date | 2016-08-24 09:42 -0700 |
| Message-ID | <82c3765d-d8e6-4eb0-a3bb-db15423dc592@googlegroups.com> |
| In reply to | #390754 |
On Wednesday, August 24, 2016 at 8:53:29 AM UTC-6, Prokaryotic Caspase Homolog wrote: > > On Wednesday, August 24, 2016 at 3:34:54 AM UTC-5, Peter Riedt wrote: > > > > On Wednesday, August 24, 2016 at 4:25:22 PM UTC+8, Sylvia Else wrote: > > > > > > It requires knowledge of the central mass. You claim that your theory > > > does not. > > > > > > Sylvia. > > > > The masses of the sun and Jupiter are well known. Perhaps you could do > > it to see if my calculations are similar. If they differ you may be > > right that I am wrong. > > But you claim not to need those masses to perform your calculations. > > SHOW YOUR WORK. I suspect that he calculates all the orbits from the period and radius of one orbiting body. This gives him the value of GM without realizing it, or if he does realize it, he is cheating, as you said.
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| From | Peter Riedt <riedt1@yahoo.co.uk> |
|---|---|
| Date | 2016-08-24 18:18 -0700 |
| Message-ID | <508e191f-56ce-4b0f-a9cc-1ae27815c05b@googlegroups.com> |
| In reply to | #390767 |
On Thursday, August 25, 2016 at 12:42:21 AM UTC+8, Gary Harnagel wrote: > On Wednesday, August 24, 2016 at 8:53:29 AM UTC-6, Prokaryotic Caspase Homolog wrote: > > > > On Wednesday, August 24, 2016 at 3:34:54 AM UTC-5, Peter Riedt wrote: > > > > > > On Wednesday, August 24, 2016 at 4:25:22 PM UTC+8, Sylvia Else wrote: > > > > > > > > It requires knowledge of the central mass. You claim that your theory > > > > does not. > > > > > > > > Sylvia. > > > > > > The masses of the sun and Jupiter are well known. Perhaps you could do > > > it to see if my calculations are similar. If they differ you may be > > > right that I am wrong. > > > > But you claim not to need those masses to perform your calculations. > > > > SHOW YOUR WORK. > > I suspect that he calculates all the orbits from the period and radius of > one orbiting body. This gives him the value of GM without realizing it, > or if he does realize it, he is cheating, as you said. I calculated a, t and v of all the planets and satellites in my examples separately by the same method using my gravity theory. I first derived all a's knowing only the individual t's, then derived all t's knowing only the individual a's, then derived the v's knowing the individual a's and t's. If no one can do it with the mathematics of GR, GR will be proved a hairy-fairy highfalutin nonsense.
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