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Groups > sci.physics.relativity > #372539 > unrolled thread
| Started by | Alan Folmsbee <omnilobe@gmail.com> |
|---|---|
| First post | 2015-12-22 08:00 -0800 |
| Last post | 2016-01-02 23:48 +0100 |
| Articles | 20 on this page of 25 — 11 participants |
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The Inverse Square Law explained Alan Folmsbee <omnilobe@gmail.com> - 2015-12-22 08:00 -0800
Re: The Inverse Square Law explained David Fuller <fuller.david@hotmail.com> - 2015-12-22 10:13 -0800
Re: The Inverse Square Law explained David Fuller <fuller.david@hotmail.com> - 2015-12-22 10:17 -0800
Re: The Inverse Square Law explained David Fuller <fuller.david@hotmail.com> - 2015-12-22 10:19 -0800
Re: The Inverse Square Law explained Tom Roberts <tjroberts137@sbcglobal.net> - 2015-12-22 12:50 -0600
Re: The Inverse Square Law explained alsor@interia.pl - 2015-12-22 12:14 -0800
Re: The Inverse Square Law explained JanPB <filmart@gmail.com> - 2015-12-28 21:11 -0800
Re: The Inverse Square Law explained alsor@interia.pl - 2015-12-29 09:18 -0800
Re: The Inverse Square Law explained Odd Bodkin <bodkinodd@gmail.com> - 2015-12-22 16:06 -0600
Re: The Inverse Square Law explained Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2015-12-27 00:42 +0100
Re: The Inverse Square Law explained alsor@interia.pl - 2015-12-27 07:50 -0800
Re: The Inverse Square Law explained Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2015-12-27 20:12 +0100
Re: The Inverse Square Law explained alsor@interia.pl - 2015-12-27 14:30 -0800
Re: The Inverse Square Law explained Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2015-12-28 00:23 +0100
Re: The Inverse Square Law explained alsor@interia.pl - 2015-12-27 15:58 -0800
Re: The Inverse Square Law explained Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2015-12-28 11:59 +0100
Re: The Inverse Square Law explained Waye Kitchens <wscom@complang.net> - 2015-12-28 11:18 +0000
Re: The Inverse Square Law explained The Starmaker <starmaker@ix.netcom.com> - 2015-12-29 10:11 -0800
Re: The Inverse Square Law explained Gary Harnagel <hitlong@yahoo.com> - 2015-12-29 13:08 -0800
Re: The Inverse Square Law explained alsor@interia.pl - 2015-12-29 15:19 -0800
Re: The Inverse Square Law explained David Fuller <fuller.david@hotmail.com> - 2015-12-29 17:13 -0800
Re: The Inverse Square Law explained David Fuller <fuller.david@hotmail.com> - 2015-12-29 17:16 -0800
Re: The Inverse Square Law explained alsor@interia.pl - 2015-12-31 05:31 -0800
Re: The Inverse Square Law explained John Gogo <jfgogo22@yahoo.com> - 2016-01-01 18:28 -0800
Re: The Inverse Square Law explained Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2016-01-02 23:48 +0100
Page 1 of 2 [1] 2 Next page →
| From | Alan Folmsbee <omnilobe@gmail.com> |
|---|---|
| Date | 2015-12-22 08:00 -0800 |
| Subject | The Inverse Square Law explained |
| Message-ID | <df089806-c698-4fb8-97a7-d8d58ed3df7b@googlegroups.com> |
Inverse Square Law Revealed "Where does the 1/R^2 come from for the inverse square laws of force and acceleration?" The answer... There are two steps to get the inverse square law. First write a momentum equation for the Law. Second, use the area of a sphere, which is 4 pi R^2 in the momentum equation. Solving for acceleration moves the R^2 into the denominator on the other side of the equation. Example: p1 = p2 for momentum conservation For example, in a gravity theory, one momentum is in the protons and neutrons: p2 = NV/tau where N is number of baryons in planet V is proton volume tau = 5.13ns The second momentum is for falling space during gravity: p2 = zA z = height fallen in 1 second A = Area of planet = 4 pi R^2 z = 1/2 a t^2 P1 = 1/2 a t^2 * 4 pi R^2 There is the R^2 p1 = p2 (1/2 a (1 second)^2 * 4 pi R^2 ) = NV/tau for Earth gravity 1/2 a = 4.9 meters (4.9 meters (1 second)^2 * 4 pi R^2 ) = NV/tau take time derivative of both sides 2a pi R^2 = MV / mC Solve for a a = MV / (2 pi R^2 m (tau*second)) The R^2 is inverted, finishing this essay. a is proportional to 1/R^2 The inverse square law is understood for gravity. Take a momentum equation and solve for a, acceleration and that R^2 is always a multiplier of a. The R2 for area multiplies a height fallen, z. That area times z is a volume for a momentum on one side of the equation. After a derivative, the z/(1 second) becomes z/(second^2). So the acceleration and R^2 are always multiplied on one side of an equation, so when solving for a, the R^2 must divide both sides. That isolates the desired "a" on the left while sending 1/R^2 to the other side. That is why the inverse square law happens: spherical geometry and a momentum conservation theory where the volume of baryons equals a volume of a fallen shell. Each of those volumes are divided by a time to get momentum. Momentum is now including volume per time in addition to the mass times velocity as momentum. The conservation of continuum is conservation of momentum. 4z pi R^2 per second = NV/tau p1 = p2 momentum http://fcgravity.blogspot.com/p/factoring-force-of-gravuty.html Alan Folmsbee, December 22, 2015, Wailuku
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| From | David Fuller <fuller.david@hotmail.com> |
|---|---|
| Date | 2015-12-22 10:13 -0800 |
| Message-ID | <18a55b76-e6f3-450a-a698-cec6f974ed42@googlegroups.com> |
| In reply to | #372539 |
On Tuesday, December 22, 2015 at 10:00:58 AM UTC-6, Alan Folmsbee wrote: > Inverse Square Law Revealed > > "Where does the 1/R^2 come from for the inverse square laws of force and acceleration?" > > The answer... > > There are two steps to get the inverse square law. First write a momentum equation for the Law. Second, use the area of a sphere, which is 4 pi R^2 in the momentum equation. Solving for acceleration moves the R^2 into the denominator on the other side of the equation. > > Example: > > p1 = p2 for momentum conservation > > For example, in a gravity theory, one momentum is in the protons and neutrons: > > p2 = NV/tau > > where > > N is number of baryons in planet > > V is proton volume > > tau = 5.13ns > > The second momentum is for falling space during gravity: > > p2 = zA > > z = height fallen in 1 second > > A = Area of planet = 4 pi R^2 > > z = 1/2 a t^2 > > P1 = 1/2 a t^2 * 4 pi R^2 > > There is the R^2 > > p1 = p2 > > (1/2 a (1 second)^2 * 4 pi R^2 ) = NV/tau > > for Earth gravity 1/2 a = 4.9 meters > > (4.9 meters (1 second)^2 * 4 pi R^2 ) = NV/tau > > take time derivative of both sides > > 2a pi R^2 = MV / mC > > Solve for a > > a = MV / (2 pi R^2 m (tau*second)) > > The R^2 is inverted, finishing this essay. > > a is proportional to 1/R^2 > > The inverse square law is understood for gravity. > > Take a momentum equation and solve for a, acceleration and that R^2 is always a multiplier of a. The R2 for area multiplies a height fallen, z. That area times z is a volume for a momentum on one side of the equation. After a derivative, the z/(1 second) becomes z/(second^2). So the acceleration and R^2 are always multiplied on one side of an equation, so when solving for a, the R^2 must divide both sides. That isolates the desired "a" on the left while sending 1/R^2 to the other side. That is why the inverse square law happens: spherical geometry and a momentum conservation theory where the volume of baryons equals a volume of a fallen shell. Each of those volumes are divided by a time to get momentum. Momentum is now including volume per time in addition to the mass times velocity as momentum. The conservation of continuum is conservation of momentum. > > 4z pi R^2 per second = NV/tau > > p1 = p2 momentum > > http://fcgravity.blogspot.com/p/factoring-force-of-gravuty.html > > Alan Folmsbee, December 22, 2015, Wailuku http://i59.tinypic.com/2lauf5i.jpg http://i57.tinypic.com/10p6pva.jpg http://i64.tinypic.com/14dlx6t.jpg
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| From | David Fuller <fuller.david@hotmail.com> |
|---|---|
| Date | 2015-12-22 10:17 -0800 |
| Message-ID | <b5688a5e-a556-452a-a74e-5dd0b1f04ba9@googlegroups.com> |
| In reply to | #372548 |
On Tuesday, December 22, 2015 at 12:13:28 PM UTC-6, David Fuller wrote: > On Tuesday, December 22, 2015 at 10:00:58 AM UTC-6, Alan Folmsbee wrote: > > Inverse Square Law Revealed > > > > "Where does the 1/R^2 come from for the inverse square laws of force and acceleration?" > > > > The answer... > > > > There are two steps to get the inverse square law. First write a momentum equation for the Law. Second, use the area of a sphere, which is 4 pi R^2 in the momentum equation. Solving for acceleration moves the R^2 into the denominator on the other side of the equation. > > > > Example: > > > > p1 = p2 for momentum conservation > > > > For example, in a gravity theory, one momentum is in the protons and neutrons: > > > > p2 = NV/tau > > > > where > > > > N is number of baryons in planet > > > > V is proton volume > > > > tau = 5.13ns > > > > The second momentum is for falling space during gravity: > > > > p2 = zA > > > > z = height fallen in 1 second > > > > A = Area of planet = 4 pi R^2 > > > > z = 1/2 a t^2 > > > > P1 = 1/2 a t^2 * 4 pi R^2 > > > > There is the R^2 > > > > p1 = p2 > > > > (1/2 a (1 second)^2 * 4 pi R^2 ) = NV/tau > > > > for Earth gravity 1/2 a = 4.9 meters > > > > (4.9 meters (1 second)^2 * 4 pi R^2 ) = NV/tau > > > > take time derivative of both sides > > > > 2a pi R^2 = MV / mC > > > > Solve for a > > > > a = MV / (2 pi R^2 m (tau*second)) > > > > The R^2 is inverted, finishing this essay. > > > > a is proportional to 1/R^2 > > > > The inverse square law is understood for gravity. > > > > Take a momentum equation and solve for a, acceleration and that R^2 is always a multiplier of a. The R2 for area multiplies a height fallen, z. That area times z is a volume for a momentum on one side of the equation. After a derivative, the z/(1 second) becomes z/(second^2). So the acceleration and R^2 are always multiplied on one side of an equation, so when solving for a, the R^2 must divide both sides. That isolates the desired "a" on the left while sending 1/R^2 to the other side. That is why the inverse square law happens: spherical geometry and a momentum conservation theory where the volume of baryons equals a volume of a fallen shell. Each of those volumes are divided by a time to get momentum. Momentum is now including volume per time in addition to the mass times velocity as momentum. The conservation of continuum is conservation of momentum. > > > > 4z pi R^2 per second = NV/tau > > > > p1 = p2 momentum > > > > http://fcgravity.blogspot.com/p/factoring-force-of-gravuty.html > > > > Alan Folmsbee, December 22, 2015, Wailuku > > http://i59.tinypic.com/2lauf5i.jpg > > http://i57.tinypic.com/10p6pva.jpg > > http://i64.tinypic.com/14dlx6t.jpg http://oi62.tinypic.com/2ag3f47.jpg
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| From | David Fuller <fuller.david@hotmail.com> |
|---|---|
| Date | 2015-12-22 10:19 -0800 |
| Message-ID | <2c167956-6b13-4c44-8f40-6f6036ed7d2c@googlegroups.com> |
| In reply to | #372548 |
http://i59.tinypic.com/2lauf5i.jpg http://i57.tinypic.com/10p6pva.jpg http://i64.tinypic.com/14dlx6t.jpg http://i60.tinypic.com/okmna0.jpg
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| From | Tom Roberts <tjroberts137@sbcglobal.net> |
|---|---|
| Date | 2015-12-22 12:50 -0600 |
| Message-ID | <vIudnbJNMcLoBuTLnZ2dnUU7_82dnZ2d@giganews.com> |
| In reply to | #372539 |
On 12/22/15 12/22/15 - 10:00 AM, Alan Folmsbee wrote: > Inverse Square Law Revealed > "Where does the 1/R^2 come from for the inverse square laws of force and acceleration?" > The answer... [lots of undefined nonsense] How silly. In theories based on Euclidean geometry, 1/r^2 comes from the GEOMETRY, plus the assumption that the force is generated by a conserved (divergence-free) flux. In theories without Euclidean geometry, such as GR, there is no 1/r^2. Only in regions where gravity is weak and Euclidean geometry applies APPROXIMATELY, is there an APPROXIMATE 1/r^2 dependence; such as in the solar system. It is HOPELESS to assume that approximate properties are exact, and then basing an entire "theory" on that assumption. Tom Roberts
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| From | alsor@interia.pl |
|---|---|
| Date | 2015-12-22 12:14 -0800 |
| Message-ID | <507093b3-6176-4d7d-a68f-246d9bf0ddb5@googlegroups.com> |
| In reply to | #372552 |
W dniu wtorek, 22 grudnia 2015 19:50:33 UTC+1 użytkownik tjrob137 napisał: > In theories based on Euclidean geometry, 1/r^2 comes from the GEOMETRY, plus the > assumption that the force is generated by a conserved (divergence-free) flux. > > In theories without Euclidean geometry, such as GR, there is no 1/r^2. Only in > regions where gravity is weak and Euclidean geometry applies APPROXIMATELY, is > there an APPROXIMATE 1/r^2 dependence; such as in the solar system. > > It is HOPELESS to assume that approximate properties are exact, and then basing > an entire "theory" on that assumption. > > Tom Roberts You just use the curved coordinates in the GR, therefore the result must be other than the 1/r^2, because adequate to the used coordinates. :)
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| From | JanPB <filmart@gmail.com> |
|---|---|
| Date | 2015-12-28 21:11 -0800 |
| Message-ID | <77a22755-28b8-484f-9944-c16c18e1dcca@googlegroups.com> |
| In reply to | #372557 |
On Tuesday, December 22, 2015 at 12:14:36 PM UTC-8, al...@interia.pl wrote: > W dniu wtorek, 22 grudnia 2015 19:50:33 UTC+1 użytkownik tjrob137 napisał: > > > In theories based on Euclidean geometry, 1/r^2 comes from the GEOMETRY, plus the > > assumption that the force is generated by a conserved (divergence-free) flux. > > > > In theories without Euclidean geometry, such as GR, there is no 1/r^2. Only in > > regions where gravity is weak and Euclidean geometry applies APPROXIMATELY, is > > there an APPROXIMATE 1/r^2 dependence; such as in the solar system. > > > > It is HOPELESS to assume that approximate properties are exact, and then basing > > an entire "theory" on that assumption. > > > > Tom Roberts > > You just use the curved coordinates in the GR, > therefore the result must be other than the 1/r^2, > because adequate to the used coordinates. :) No, that's not how it works. You confuse coordinate distances with arc length. -- Jan
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| From | alsor@interia.pl |
|---|---|
| Date | 2015-12-29 09:18 -0800 |
| Message-ID | <338b1576-82ee-4b2f-9568-66492b978f5e@googlegroups.com> |
| In reply to | #372874 |
W dniu wtorek, 29 grudnia 2015 06:11:14 UTC+1 użytkownik JanPB napisał: > On Tuesday, December 22, 2015 at 12:14:36 PM UTC-8, al...@interia.pl wrote: > > W dniu wtorek, 22 grudnia 2015 19:50:33 UTC+1 użytkownik tjrob137 napisał: > > > > > In theories based on Euclidean geometry, 1/r^2 comes from the GEOMETRY, plus the > > > assumption that the force is generated by a conserved (divergence-free) flux. > > > > > > In theories without Euclidean geometry, such as GR, there is no 1/r^2. Only in > > > regions where gravity is weak and Euclidean geometry applies APPROXIMATELY, is > > > there an APPROXIMATE 1/r^2 dependence; such as in the solar system. > > > > > > It is HOPELESS to assume that approximate properties are exact, and then basing > > > an entire "theory" on that assumption. > > > > > > Tom Roberts > > > > You just use the curved coordinates in the GR, > > therefore the result must be other than the 1/r^2, > > because adequate to the used coordinates. :) > > No, that's not how it works. You confuse coordinate distances with arc length. > > -- > Jan GR is just about coordinates fallacy. simply: in that model has been assumed - in the fly, at hoc!, some special coordinates, which reproduce the same motion, namely the newton's: g = m/r^2, ect., but in the other space: the GR-space... therefore there are curved everything, without any force - the gravity... hihi! Further: the same fallacy has been applied in the cosmology, hance the claim about the escapement of distant galaxies without any motion.. it's just idiocy because there the coord. change in time.. so, the galaxies can still stay in place, and the result is... similar to like they really escape... but the whole idea is still the same: totally unrealistic, fantastic - idiotic!
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| From | Odd Bodkin <bodkinodd@gmail.com> |
|---|---|
| Date | 2015-12-22 16:06 -0600 |
| Message-ID | <n5chhj$to5$1@speranza.aioe.org> |
| In reply to | #372539 |
On 12/22/2015 10:00 AM, Alan Folmsbee wrote: > Inverse Square Law Revealed > > "Where does the 1/R^2 come from for the inverse square laws of force and acceleration?" > > The answer... > Doesn't this come directly from Gauss' law? That's covered in calculus-based intro physics books for scientists and engineers, if I recall correctly. -- Odd Bodkin --- maker of fine toys, tools, tables
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| From | Thomas 'PointedEars' Lahn <PointedEars@web.de> |
|---|---|
| Date | 2015-12-27 00:42 +0100 |
| Message-ID | <1637288.fnPO6jQxUB@PointedEars.de> |
| In reply to | #372562 |
Odd Bodkin wrote:
> On 12/22/2015 10:00 AM, Alan Folmsbee wrote:
>> Inverse Square Law Revealed
>>
>> "Where does the 1/R^2 come from for the inverse square laws of force and
>> acceleration?"
>>
>> The answer...
>
> Doesn't this come directly from Gauss' law?
It does not, indeed ;-)
<https://en.wikipedia.org/wiki/Gauss%27s_law>
Gauss’s law *for gravity* can be derived from Newton’s law instead.
However, it can be shown that Newton’s law follows from Gauss’s *theorem*,
also known as [1] <https://en.wikipedia.org/wiki/Divergence_theorem> when
*also* applying Gauss’s law to gravity.
Conversely, Newton’s law can be derived, *indirectly*, from Gauss’s law
*for gravity* *with additional assumptions*, using Gauss’s/the divergence
*theorem*:
<https://en.wikipedia.org/wiki/Gauss%27s_law_for_gravity#Deriving_Newton.27s_law_from_Gauss.27s_law_and_irrotationality>
But, of course, “[Gauss’s/the divergence] theorem was first discovered by
Lagrange in 1762,[9] then later independently rediscovered by Gauss in 1813,
[…]” [↑1]. Newton posited his law of universal gravitation *about 100 years
earlier*, in Book 1, «De motu corporum» (“On the motions of bodies”), of
the «Philosophiæ Naturalis Principia Mathematica» («Principia») of 1678:
<https://en.wikipedia.org/wiki/Philosophi%C3%A6_Naturalis_Principia_Mathematica>
So neither Gauss’s theorem nor law could have been Newton’s foundation.
It is not known how Newton got the idea of the inverse square law, but the
arguments in the «Principia» (Book Ⅰ, Section Ⅱ), suggest that it were
Kepler’s laws of planetary motion (in «Epitome astronomiae Copernicanae»
„Epitome of Copernican Astronomy”, 1617–1621) – this would not be too
surprising given Newton’s interest in astronomical matters, and that it was
Edmond Halley, later Astronomer Royal, whom he discussed his work with, and
who funded the publication of the «Principia».
Susskind (see below) argues:
“The acceleration of circular motion is described by ω² R, where ω is the
angular period of going round in an orbit of radius R. Suppose Newton set
that equal to some unknown force law [that depends on the radius, F(R)],
ω² R = F(R),
and divided by R:
ω² = F(R)∕R.
For the real case, inverse square law,
ω² = F(R)∕R = (X∕R²)∕R = X∕R³
and in that form it is Kepler’s third law: ‘The square of the orbital
period of a planet is directly proportional to the cube of the semi-major
axis of its orbit.’”
> That's covered in calculus-based intro physics books for scientists and
> engineers, if I recall correctly.
It is also covered in physics lectures, such as lecture 1 of the series
“Einstein’s General Theory of Relativity” as taught by Leonard Susskind,
Ph.D., at Stanford University in 2008, from where I took most of the
equations and the argument above. Highly recommended:
<http://www.youtube.com/watch?v=hbmf0bB38h0>
PointedEars
--
Q: What did the female magnet say to the male magnet?
A: From the back, I found you repulsive, but from the front
I find myself very attracted to you.
(from: WolframAlpha)
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| From | alsor@interia.pl |
|---|---|
| Date | 2015-12-27 07:50 -0800 |
| Message-ID | <5ff87992-a8d8-4a71-9e98-61116ea6ba10@googlegroups.com> |
| In reply to | #372806 |
W dniu niedziela, 27 grudnia 2015 00:42:11 UTC+1 użytkownik Thomas > So neither Gauss’s theorem nor law could have been Newton’s foundation. > It is not known how Newton got the idea of the inverse square law You talk nonsense... after all it's just a surface of a sphere... S = 4pir^2. thus the force must be in the form: f = k/S. actualy it's: f = GM/r^2; so, the G const is incorrectly choosen.. it should be rather: G' = G/4pi = 5.3e-12 ...
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| From | Thomas 'PointedEars' Lahn <PointedEars@web.de> |
|---|---|
| Date | 2015-12-27 20:12 +0100 |
| Message-ID | <17702871.7RnZnggNuE@PointedEars.de> |
| In reply to | #372812 |
alsor@interia.pl wrote: > W dniu niedziela, 27 grudnia 2015 00:42:11 UTC+1 użytkownik Thomas >> So neither Gauss’s theorem nor law could have been Newton’s foundation. >> It is not known how Newton got the idea of the inverse square law > > You talk nonsense... > after all it's just a surface of a sphere... S = 4pir^2. > thus the force must be in the form: f = k/S. > > actualy it's: f = GM/r^2; > so, the G const is incorrectly choosen.. > it should be rather: G' = G/4pi = 5.3e-12 ... As usual, utter nonsense from you. PointedEars -- Q: What did the nuclear physicist order for lunch? A: Fission chips. (from: WolframAlpha)
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| From | alsor@interia.pl |
|---|---|
| Date | 2015-12-27 14:30 -0800 |
| Message-ID | <c6212721-c902-422c-a05b-a68ac616088a@googlegroups.com> |
| In reply to | #372818 |
W dniu niedziela, 27 grudnia 2015 20:12:35 UTC+1 użytkownik Thomas 'PointedEars' Lahn napisał: > alsor@interia.pl wrote: > > > W dniu niedziela, 27 grudnia 2015 00:42:11 UTC+1 użytkownik Thomas > >> So neither Gauss’s theorem nor law could have been Newton’s foundation. > >> It is not known how Newton got the idea of the inverse square law > > > > You talk nonsense... > > after all it's just a surface of a sphere... S = 4pir^2. > > thus the force must be in the form: f = k/S. > > > > actualy it's: f = GM/r^2; > > so, the G const is incorrectly choosen.. > > it should be rather: G' = G/4pi = 5.3e-12 ... > > As usual, utter nonsense from you. another orangutan which pretend to be.. See the Coulomb relation: f = q1q2/4pieps0r^2 so, there is the 4pi explicitly!
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| From | Thomas 'PointedEars' Lahn <PointedEars@web.de> |
|---|---|
| Date | 2015-12-28 00:23 +0100 |
| Message-ID | <7118782.6mxME6tmbB@PointedEars.de> |
| In reply to | #372822 |
alsor@interia.pl wrote: > W dniu niedziela, 27 grudnia 2015 20:12:35 UTC+1 użytkownik Thomas > 'PointedEars' Lahn napisał: >> alsor@interia.pl wrote: >> > W dniu niedziela, 27 grudnia 2015 00:42:11 UTC+1 użytkownik Thomas >> >> So neither Gauss’s theorem nor law could have been Newton’s >> >> foundation. It is not known how Newton got the idea of the inverse >> >> square law >> > You talk nonsense... >> > after all it's just a surface of a sphere... S = 4pir^2. >> > thus the force must be in the form: f = k/S. >> > >> > actualy it's: f = GM/r^2; >> > so, the G const is incorrectly choosen.. >> > it should be rather: G' = G/4pi = 5.3e-12 ... >> As usual, utter nonsense from you. > > another orangutan which pretend to be.. No, it’s the same fool who is still thinks they speak English… > See the Coulomb relation: > f = q1q2/4pieps0r^2 > > so, there is the 4pi explicitly! That there is a factor of 4π with the surface of a sphere was never doubted since the surface of the sphere is 4πr² if r is the sphere’s radius. That has very little to do with the fact that the gravitational acceleration falls off with the square of the distance, and does not prove in the slightest any of your nonsensical layman assertions above, especially not that “the G const is incorrectly chosen”. Coulomb’s law (1784), that which you call “Coulomb relation”, to which Gauss’s law (1836) is essentially equivalent, was not known when Newton published the «Principia» (1678). So that, too, could not have been Newton’s foundation. It is a historian’s fallacy to assume otherwise. PointedEars -- Q: Where are offenders sentenced for light crimes? A: To a prism. (from: WolframAlpha)
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| From | alsor@interia.pl |
|---|---|
| Date | 2015-12-27 15:58 -0800 |
| Message-ID | <f660ec2f-98b9-4045-a917-b6f0f2063e05@googlegroups.com> |
| In reply to | #372826 |
W dniu poniedziałek, 28 grudnia 2015 00:23:10 UTC+1 użytkownik Thomas 'PointedEars' Lahn napisał: > alsor@interia.pl wrote: > > > W dniu niedziela, 27 grudnia 2015 20:12:35 UTC+1 użytkownik Thomas > > 'PointedEars' Lahn napisał: > >> alsor@interia.pl wrote: > >> > W dniu niedziela, 27 grudnia 2015 00:42:11 UTC+1 użytkownik Thomas > >> >> So neither Gauss’s theorem nor law could have been Newton’s > >> >> foundation. It is not known how Newton got the idea of the inverse > >> >> square law > >> > You talk nonsense... > >> > after all it's just a surface of a sphere... S = 4pir^2. > >> > thus the force must be in the form: f = k/S. > >> > > >> > actualy it's: f = GM/r^2; > >> > so, the G const is incorrectly choosen.. > >> > it should be rather: G' = G/4pi = 5.3e-12 ... > >> As usual, utter nonsense from you. > > > > another orangutan which pretend to be.. > > No, it’s the same fool who is still thinks they speak English… > > > See the Coulomb relation: > > f = q1q2/4pieps0r^2 > > > > so, there is the 4pi explicitly! > > That there is a factor of 4π with the surface of a sphere was never doubted > since the surface of the sphere is 4πr² if r is the sphere’s radius. > > That has very little to do with the fact that the gravitational acceleration > falls off with the square of the distance, and does not prove in the > slightest any of your nonsensical layman assertions above, especially not > that “the G const is incorrectly chosen”. > > Coulomb’s law (1784), that which you call “Coulomb relation”, to which > Gauss’s law (1836) is essentially equivalent, was not known when Newton > published the «Principia» (1678). So that, too, could not have been > Newton’s foundation. It is a historian’s fallacy to assume otherwise. Very impressive... unusually! My congratulations - you are now the leader on my list of idiots. :)
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| From | Thomas 'PointedEars' Lahn <PointedEars@web.de> |
|---|---|
| Date | 2015-12-28 11:59 +0100 |
| Message-ID | <6154357.zACPRpkuFq@PointedEars.de> |
| In reply to | #372827 |
alsor@interia.pl wrote: > My congratulations - you are now the leader on my list of idiots. :) Thank you. It is an honor to be on a “list of idiots” compiled by an idiot. PointedEars -- A neutron walks into a bar and inquires how much a drink costs. The bartender replies, "For you? No charge." (from: WolframAlpha)
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| From | Waye Kitchens <wscom@complang.net> |
|---|---|
| Date | 2015-12-28 11:18 +0000 |
| Message-ID | <n5r5qb$rhb$1@speranza.aioe.org> |
| In reply to | #372836 |
Thomas 'PointedEars' Lahn wrote: > alsor@interia.pl wrote: > >> My congratulations - you are now the leader on my list of idiots. :) > > Thank you. It is an honor to be on a “list of idiots” compiled by an > idiot. Enjoyable to see both of you being correct.
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| From | The Starmaker <starmaker@ix.netcom.com> |
|---|---|
| Date | 2015-12-29 10:11 -0800 |
| Message-ID | <5682CCEB.C14@ix.netcom.com> |
| In reply to | #372837 |
yous people are missing a dimension here somewhere..
it is not a " Inverse Square Law "...
it is a cube, that means a square that has 3 dimensions...
isn't about time yous start calling it a
Inverse Cube Law ?
The Starmaker
Get with the program!
i don't have time to be conducting physics classes here...
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| From | Gary Harnagel <hitlong@yahoo.com> |
|---|---|
| Date | 2015-12-29 13:08 -0800 |
| Message-ID | <931282fb-54a4-4f4c-8694-7db580a6f204@googlegroups.com> |
| In reply to | #372891 |
On Tuesday, December 29, 2015 at 11:11:51 AM UTC-7, The Starmaker wrote: > > yous people are missing a dimension here somewhere.. > > it is not a " Inverse Square Law "... > > it is a cube, that means a square that has 3 dimensions... > > isn't about time yous start calling it a > > > Inverse Cube Law ? :-)))) > The Starmaker > > > > > Get with the program! > > > i don't have time to be conducting physics classes here... And we're all certainly thankful for that! :-) Gary
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| From | alsor@interia.pl |
|---|---|
| Date | 2015-12-29 15:19 -0800 |
| Message-ID | <19577a1a-15fb-459b-960d-97884f85ba18@googlegroups.com> |
| In reply to | #372891 |
W dniu wtorek, 29 grudnia 2015 19:11:51 UTC+1 użytkownik The Starmaker napisał: > yous people are missing a dimension here somewhere.. > > it is not a " Inverse Square Law "... > > it is a cube, that means a square that has 3 dimensions... > > isn't about time yous start calling it a > > > Inverse Cube Law ? there is an example of the inverse cube law: a = h^2/r^3 - k/r^2; :)
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