Groups > comp.sys.acorn.programmer > #5779

Re: Specific numbers but in a random sequence

Subject	Re: Specific numbers but in a random sequence
Newsgroups	comp.sys.acorn.programmer
From	Julian Fry <JulianFry@compuserve.com>
Date	2019-06-22 18:05 +0100
Message-ID	<17dc36c857.Root@julianfry.orpheusnet.co.uk> (permalink)
References	<57c7c5d6c0basura@invalid.addr.uk> <qeji40$7ca$1@dont-email.me> <qel12p$ibq$1@dont-email.me> <57c82fa1bdbasura@invalid.addr.uk>
Organization	Orpheus Internet Services

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On 22 Jun 2019 Richard Ashbery  wrote:

> In article <qel12p$ibq$1@dont-email.me>,
>    druck <news@druck.org.uk> wrote:
>> On 21/06/2019 22:27, Gavin Crawford wrote:
>>> Richard Ashbery <basura@invalid.addr.uk> Wrote in message:

> [snip]

> 3,4,5,6,8,9,10,12,15,18,20,24,30,36,45,60,90,120I would like to be
> able to use these variables in a random sequence.

>>> Why not put them into an array and use a random number to choose
>>>   the array index.

>> Yes, and make sure you seed the random number generator, or it may
>> always go through the same pseudo random sequence each time its run.

>> IIRC to seed do RND(-TIME) before any other call to RND.

> Not quite there yet - if I use the following...

> DIM array%(18)
> array%() = 3,4,5,6,8,9,10,12,15,18,20,24,30,36,45,60,90,120
> y = RND(-TIME)
> FOR loop = 1 TO 5
> FOR I% = 0 TO 18
> PRINT array%(RND(I%))
> NEXT I%
> NEXT loop

RND(N) where N>1 (N being an integer) returns a number between 1 and N 
so you are resetting the range every call.
Try RND(18)

-- 
Best wishes

Julian

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