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Groups > sci.physics.relativity > #585342
| From | Thomas Heger <ttt_heg@web.de> |
|---|---|
| Newsgroups | sci.physics.relativity |
| Subject | Re: Annotated version of SRT |
| Date | 2022-05-15 08:50 +0200 |
| Message-ID | <jebm5hF7rgiU1@mid.individual.net> (permalink) |
| References | (17 earlier) <52fe5433-4dcd-434c-905f-44e649e5b8f5n@googlegroups.com> <je11f5F6lumU1@mid.individual.net> <4e587415-9f7b-4ad9-b5ad-8a7b498ccef9n@googlegroups.com> <je55eoF9taU1@mid.individual.net> <0787f688-0032-4f81-ac37-398fb4bcd077n@googlegroups.com> |
Am 15.05.2022 um 04:29 schrieb JanPB: >> These two items move with constant distance along the x/xsi-axis into >> >the direction of higher xsi-values. >> > >> >This 'tandem' is observed from the zero spot of K, which moves with >> >velocity v relative to the system into the negative direction with -v*t. >> > >> >But none of Einstein's equations would fit to that setting. > Again, you are expressing the physical situation in mathematical > terms that do not represent the physical situation. WHAT? The situation is EXTREMELY simple: You have a coordinate system K and a copy of K set into motion along the x-axis of K with velocity v. Now both systems use the same unit vectors, which point into the same directions, but the zero spot of k is set into motion. It would be an addition of a displacement v*t to the positions of K, which would gain equivalent points in k and K (like the zero spot of k). Now the same points have coordinates in both system, too, but we need subtraction for a coordinate transform. So a point (a, b, c) in K has the coordinates (a- v*t, b, c) in k. This is totally simple and obvious for slow velocities v (what is the realm we could possibly measure). Now it gets tricky, if the velocity v is getting into the realm of the speed of light, but in the slow case the problem is trivial. >> >Instead of a coordinate transformation he developed an obscure partial >> >differential equation, which I think is faulty and which I'm unable to >> >associate with the setting from above. > It's a very simple equation. The coordinate transformation is > presumed linear, so the tau component of it is presumed > to look like this: > > tau(x', y, z, t) = Ax' + By + Cz + Dt But the actually meant Lorentz transform is not a linear function. Also: displacement of a coordinate system would make the transformation function non-linear, too. > > This means that dtau/dx' = A, dtau/dy = B, dtau/dz = C, dtau/dt = D. > >> >I have complained about this point several times, too. > Without merit. > >> >But apparently you know how to derive Einstein's equation. So, please >> >let me know, how that works. > It's written out in the paper. Given the equation (1/2)*(tau_0 + tau_2) = tau_1, > one differentiates it wrt x' and that yields the equation constraining the > A and D constants. In system k x' is a constant (the difference between emitter and mirror), what would forbid the operation you have mentioned, because you can differentiate wrt variables only. TH
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Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-07 07:19 +0200
Re: Annotated version of SRT JanPB <filmart@gmail.com> - 2022-05-07 00:38 -0700
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-08 08:22 +0200
Re: Annotated version of SRT JanPB <filmart@gmail.com> - 2022-05-08 12:33 -0700
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-10 07:12 +0200
Re: Annotated version of SRT JanPB <filmart@gmail.com> - 2022-05-10 00:19 -0700
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-11 07:55 +0200
Re: Annotated version of SRT Mikko <mikko.levanto@iki.fi> - 2022-05-11 11:25 +0300
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-12 07:39 +0200
Re: Annotated version of SRT Mikko <mikko.levanto@iki.fi> - 2022-05-12 10:31 +0300
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-12 21:05 +0200
Re: Annotated version of SRT Mikko <mikko.levanto@iki.fi> - 2022-05-15 11:26 +0300
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-18 07:38 +0200
Re: Annotated version of SRT Mikko <mikko.levanto@iki.fi> - 2022-05-18 16:42 +0300
Re: Annotated version of SRT JanPB <filmart@gmail.com> - 2022-05-12 11:33 -0700
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-12 21:28 +0200
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-13 08:41 +0200
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-14 06:43 +0200
Re: Annotated version of SRT JanPB <filmart@gmail.com> - 2022-05-14 19:49 -0700
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-15 08:34 +0200
Re: Annotated version of SRT JanPB <filmart@gmail.com> - 2022-05-15 12:53 -0700
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-18 08:01 +0200
Re: Annotated version of SRT JanPB <filmart@gmail.com> - 2022-05-18 10:02 -0700
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-20 09:32 +0200
Re: Annotated version of SRT JanPB <filmart@gmail.com> - 2022-05-14 19:29 -0700
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-15 08:50 +0200
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-19 08:39 +0200
Re: Annotated version of SRT Python <python@python.invalid> - 2022-05-19 11:03 +0200
Re: Annotated version of SRT Maciej Wozniak <maluwozniak@gmail.com> - 2022-05-19 06:56 -0700
Re: Annotated version of SRT JanPB <filmart@gmail.com> - 2022-05-19 02:05 -0700
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-20 09:17 +0200
Re: Annotated version of SRT JanPB <filmart@gmail.com> - 2022-05-20 15:10 -0700
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-21 08:38 +0200
Re: Annotated version of SRT Python <python@python.invalid> - 2022-05-21 18:41 +0200
Re: Annotated version of SRT Maciej Wozniak <maluwozniak@gmail.com> - 2022-05-21 11:51 -0700
Re: Annotated version of SRT Thomas Heger <ttt_heg@web.de> - 2022-05-22 07:29 +0200
Re: Annotated version of SRT Maciej Wozniak <maluwozniak@gmail.com> - 2022-05-21 23:10 -0700
Re: Annotated version of SRT "Paul B. Andersen" <paul.b.andersen@paulba.no> - 2022-05-19 20:00 +0200
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