Groups > sci.physics.relativity > #460497

Re: Why does gravity have to be transmitted through particles when gravity isn't a force in general relativity?

From	Odd Bodkin <bodkinodd@gmail.com>
Newsgroups	sci.physics.relativity
Subject	Re: Why does gravity have to be transmitted through particles when gravity isn't a force in general relativity?
Date	2018-06-06 12:27 +0000
Organization	Aioe.org NNTP Server
Message-ID	<pf8jvb$24c$1@gioia.aioe.org> (permalink)
References	(14 earlier) <7c1af5ec-efa2-43b2-8faf-d14b0c8420ad@googlegroups.com> <pf6gsf$o3a$1@gioia.aioe.org> <371607f4-19a0-40ea-8974-0ea022eff376@googlegroups.com> <pf72ft$1n5j$1@gioia.aioe.org> <7bc92476-2da8-4064-9cf4-386638f30b6c@googlegroups.com>

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kenseto <setoken@att.net> wrote:
> On Tuesday, June 5, 2018 at 6:22:57 PM UTC-4, Odd Bodkin wrote:
>> kenseto <setoken@att.net> wrote:
>>> On Tuesday, June 5, 2018 at 1:22:27 PM UTC-4, Odd Bodkin wrote:
>>>> Edward Prochak <edprochak@gmail.com> wrote:
>>>>> On Tuesday, June 5, 2018 at 10:25:06 AM UTC-4, kenseto wrote:
>>>>>> On Tuesday, June 5, 2018 at 9:05:21 AM UTC-4, Edward Prochak wrote:
>>>>>>> On Monday, June 4, 2018 at 7:50:48 PM UTC-4, kenseto wrote:
>>>>>>>> On Monday, June 4, 2018 at 6:30:20 PM UTC-4, Edward Prochak wrote:
>>>>>>>>> On Monday, June 4, 2018 at 5:15:04 PM UTC-4, kenseto wrote:
>>>>>>>>>> On Monday, June 4, 2018 at 10:54:00 AM UTC-4, Odd Bodkin wrote:
>>>>>>>>> 
>>>>>>>>>>> So you can’t find what you claimed to have read? How frustrating for you. 
>>>>>>>>>> 
>>>>>>>>>> The video in the following link show how the orbital period is
>>>>>>>>>> calculated using the centrifugal force and Newton’s gravitational
>>>>>>>>>> equation:
>>>>>>>>>> "Shows how to calculate the orbital period of a Satellite.  The
>>>>>>>>>> equation for orbital period is derived from Newton's second law
>>>>>>>>>> and Newton's Law of universal gravitation.  You can see a listing
>>>>>>>>>> of all my videos at http://www.stepbystepscience.com "
>>>>>>>>> 
>>>>>>>>> Which one video?
>>>>>>>>> That site is so annoying, I did not bother to drill down very far.
>>>>>>>> 
>>>>>>>> Sigh....click on the link PHYSICS, then clock on the link calculating
>>>>>>>> the orbital period.
>>>>>>> 
>>>>>>> Sigh, You skipped a step, but at least you gave the name.
>>>>>>> Easier would have been:
>>>>>>> https://www.youtube.com/watch?v=aFrItoUDA4E
>>>>>>> 
>>>>>>> So note:
>>>>>>> There is no tangential force or tangential acceleration used or mentioned.
>>>>>>> There is no centrifugal force mentioned.
>>>>>>> He does put the Gravity force vector in the wrong place.
>>>>>>> He does the specific case of a circular orbit.
>>>>>>> 
>>>>>>> So I'm confused. How was this supposed to help
>>>>>>> your argument that Newtonian gravity is wrong?
>>>>>>> 
>>>>>>> Ed
>>>>>> 
>>>>>> Sigh....I never say that Newtonian gravity is wrong. I said that
>>>>>> Newtonian gravity is a composite force. It is composed of:
>>>>>> 1. An attractive EM force derived from that the moon and the earth are
>>>>>> expanding in the same direction in the E-Matrix.
>>>>>> 2. A repulsive effect exists between the earth and the moon because they
>>>>>> are confined to the divergent structure of the E-Matrix.
>>>>>> 3. Newtonian Gravity is the sum of the above opposing forces. These
>>>>>> opposing forces produce the needed  centripetal acceleration and the
>>>>>> tangential acceleration between the earth and the moon to maintain a stable orbit.
>>>>>> 4. Read my paper before you shoot off your mouth.
>>>>> 
>>>>> I wasted enough time reading that undergrad level draft
>>>>> of a grade D paper. I'll not waste time going through it again.
>>>>> 
>>>>> You make this claim which contradicts how Newton framed gravity.
>>>>> Newton needed no tangential factors (force, acceleration).
>>>>> 
>>>>> Again, I ask you simple to show how these forces work.
>>>>> Do the Math. Put it in a revised paper.
>>>>> 
>>>>> Sadly I know you won't do it.
>>>>> Oh well. your loss.
>>>>> 
>>>>> Ed
>>>>> 
>>>> 
>>>> Ken, can you calculate the tangential acceleration of the moon around the
>>>> earth? Looking for a number with units. I say it has an average value of 0
>>>> m/s^2.  What number do you calculate?
>>> 
>>> How could it has 0m/s^2 when it is continually go around the orbit in the
>>> tangential direction?
>>> 
>> 
>> You know the difference between speed and acceleration? 
> 
> You don’t know, that’s why you ask the question? I suggest that you look
> it up in your text book.
> 
>> 
>> You know that things can “go” without accelerating, right?
> 
> Idiot....not in a circular motion. Every point in orbit the object is
> experiencing instant acceleration. That’s why the object is constantly
> change direction. Gee you are stupid.
> 

Ken, back to basics. In 2D motion, you break down motions, accelerations,
and forces into orthogonal components. For example, if you throw a
baseball, it will have motion both horizontally and vertically. For the
vertical motion, there is a nonzero acceleration. That is due to the
vertical force of gravity near the surface of the earth. But horizontally,
even though there is motion, there is no force required to sustain the
horizontal motion, and indeed there is no horizontal acceleration. 

Likewise in a circular orbit, there are radial and tangential components of
the motion. The radial component has an acceleration toward the center just
by virtue of traveling in a circle. That is the centripetal acceleration
and there is a centripetal force that causes that. But tangentially there
is no force required to sustain that motion, and indeed there is no
tangential acceleration. 

High school physics, Ken. High school. 

-- 
Odd Bodkin — Maker of fine toys, tools, tables

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