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Treating a multi-dimensional array as one-dimensional

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I need to define a function which can handle two-dimensional array 
parameters of any size (both dimensions). The code below illustrates my 
current approach.

	#include <stdio.h>
	
	#define LEN(arr) (sizeof (arr) / sizeof (arr)[0])
	
	static void Print(const int *A, int m, int n)
	{
	    int i, j;
	
	    for (i = 0; i < m; i++) {
	        for (j = 0; j < n; j++) {
	            printf("%d ", A[i * n + j]);
	        }
	        putchar('\n');
	    }
	}
	
	int main(void)
	{
	    int A[2][3] = {{1, 2, 3}, {4, 5, 6}};
	
	    Print((int *) A, LEN(A), LEN(A[0]));
	    return 0;
	}

I posted this question on StackOverflow(*) and it was suggested that It 
violates the strict aliasing rule. Is there a different way to solve 
this problem?


*https://stackoverflow.com/questions/48491951/can-i-treat-a-multi-dimensional-array-as-a-one-dimensional-array


-- August

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Treating a multi-dimensional array as one-dimensional August Karlstrom <fusionfile@gmail.com> - 2018-01-29 10:40 +0100
  Re: Treating a multi-dimensional array as one-dimensional Ben Bacarisse <ben.usenet@bsb.me.uk> - 2018-01-29 11:00 +0000
    Re: Treating a multi-dimensional array as one-dimensional supercat@casperkitty.com - 2018-01-29 07:58 -0800
    Re: Treating a multi-dimensional array as one-dimensional Nick Bowler <nbowler@draconx.ca> - 2018-01-29 22:38 +0000
      Re: Treating a multi-dimensional array as one-dimensional Ben Bacarisse <ben.usenet@bsb.me.uk> - 2018-01-29 23:07 +0000
  Re: Treating a multi-dimensional array as one-dimensional Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2018-01-29 03:29 -0800
    Re: Treating a multi-dimensional array as one-dimensional August Karlstrom <fusionfile@gmail.com> - 2018-01-29 21:35 +0100

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