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Re: people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors

From Serigo <invalid@invalid.com>
Newsgroups sci.physics
Subject Re: people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors
Date 2016-09-19 16:15 -0500
Organization Aioe.org NNTP Server
Message-ID <nrpki7$mbs$1@gioia.aioe.org> (permalink)
References <34f08e43-b8ca-46f8-8673-828eb384691a@googlegroups.com> <nrnf87$rc0$1@gioia.aioe.org> <207e1f0a-f452-484b-b2e0-982711b337e3@googlegroups.com> <nrp1i3$vv9$3@pcls7.std.com> <19906c3f-010e-4a2b-b30c-41e847e19aae@googlegroups.com>

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On 9/19/2016 3:07 PM, Archimedes Plutonium wrote:
> On Monday, September 19, 2016 at 10:52:42 AM UTC-5, Michael Moroney
> wrote:
>> Archimedes Plutonium <plutonium.archimedes@gmail.com> writes:
>>
>>> On Sunday, September 18, 2016 at 8:33:03 PM UTC-5, Serigo wrote:
>>
>>>> nope. Electric field is a vector field. Voltage is a scalar
>>>> number.
>>
>>> Wrong again. The Magnetic Field is a vector Space: kg /A*s^2 And
>>> since that vector space is in all the below listed parameters,
>>> some of them inverted, means all of them are vectors.
>>

>>
>>> All of the above are multiples of the vector space Magnetic
>>> Field, hence, all are vectors.
>>
>> No, whether a derived unit is a vector or a scalar depends on how
>> it is derived. If the dot product is taken between two vectors, you
>> get a scalar.  The cross product of two vectors is another vector.
>> For example, voltage is the dot product of the distance vector and
>> the electric field vector, thus it is a scalar.  A (3D) vector has
>> a direction, while a scalar is just a value.
>>
>>> You got bamboozled by Old Physics
>>
>>> AP
>
> The Magnetic Field is always a vector, regardless of any operation
> placed upon it.

for our readers;

  dot product and cross product are operations used in Vector Analysis 
(vector calculus), which are in quite a few branches of science.

there are also the differential operators or del operator of
	grad
	curl
	div
	vector laplician
	Laplician
	
There is also Tensor Calculus, more difficult, it extends vector 
calculus to tensor fields, which can very over time, manifolds

most physicist and EEs should have some of these courses,


wiki has a lot on the math of Maxwell
https://en.wikipedia.org/wiki/Maxwell%27s_equations

and free book;

https://en.wikipedia.org/wiki/Book:Maxwell%27s_equations

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Thread

How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 15:07 -0700
  How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 17:25 -0700
  Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Serigo <invalid@invalid.com> - 2016-09-18 20:32 -0500
    Magnetic Field in most-everything Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 19:38 -0700
      Re: Magnetic Field in most-everything Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here moroney@world.std.spaamtrap.com (Michael Moroney) - 2016-09-19 15:51 +0000
        people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 13:07 -0700
          Re: people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors Serigo <invalid@invalid.com> - 2016-09-19 16:15 -0500
            Re: people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 14:29 -0700
              Re: people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors Serigo <invalid@invalid.com> - 2016-09-19 19:51 -0500
                Faraday law looks like (V*R^-1)' = A*R + B + constant; Ampere law looks like (A*R)' = B + V*A^-1 + constant Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 19:41 -0700
                Re: Faraday law looks like (V*R^-1)' = A*R + B + constant; Ampere law looks like (A*R)' = B + V*A^-1 + constant Serigo <invalid@invalid.com> - 2016-09-20 09:55 -0500
                Re: Faraday law looks like (V*R^-1)' = A*R + B + constant; Ampere law looks like (A*R)' = B + V*A^-1 + constant "hanson" <hanson@quick.net> - 2016-09-20 09:03 -0700
          Re: people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors moroney@world.std.spaamtrap.com (Michael Moroney) - 2016-09-19 22:26 +0000
            This moron thought a magnetic field is only a vector dependent on how it was derived Re: people that do not understand Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 19:23 -0700
              Re: This moron thought a magnetic field is only a vector dependent on how it was derived Re: people that do not understand Serigo <invalid@invalid.com> - 2016-09-19 21:41 -0500
                (A*R)' = A'*R  +  R'*A and derivative (V*R^-1)' = V'*R^-1  +  V*(R^-1)' Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 22:12 -0700
                derivative of magnetic field Re: (A*R)' = A'*R  +  R'*A and derivative (V*R^-1)' = V'*R^-1  +  V*(R^-1)' Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 23:45 -0700
                Re: (A*R)' = A'*R + R'*A and derivative (V*R^-1)' = V'*R^-1 + V*(R^-1)' Serigo <invalid@invalid.com> - 2016-09-20 10:09 -0500
              Re: This moron thought a magnetic field is only a vector dependent on how it was derived Re: people that do not understand moroney@world.std.spaamtrap.com (Michael Moroney) - 2016-09-20 04:08 +0000
                Re: This moron thought a magnetic field is only a vector dependent on how it was derived Re: people that do not understand Serigo <invalid@invalid.com> - 2016-09-20 10:28 -0500
                Re: This moron thought a magnetic field is only a vector dependent on how it was derived Re: people that do not understand moroney@world.std.spaamtrap.com (Michael Moroney) - 2016-09-20 16:40 +0000
    Someone in Old Physics trying to flesh out Faraday's law Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 20:03 -0700
      Re: Someone in Old Physics trying to flesh out Faraday's law Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Serigo <invalid@invalid.com> - 2016-09-18 22:31 -0500
        Old Physics Faraday law math does not match the experiment Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 20:51 -0700
          math that matches is the Product Rule in Differentiation that gives a Lenz law inside of Faraday law Re: Old Physics Faraday law math does not match the experiment Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 02:47 -0700
    trying to teach a brainwashed that velocity on Magnetic Field is just another Magnetic Field Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 20:20 -0700

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