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Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here

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On 9/18/2016 5:07 PM, Archimedes Plutonium wrote:
>
> Voltage is the (1) Electric Potential, the (2) Potential Difference
> and (3) Electromotive Force and all with the Units of W/A =
> kg*m^2/A*s^3
>
> Voltage in Revised Maxwell theory is the Electric Field, for there is
> no electric field apart from voltage. When you speak of Voltage, you
> are speaking of Electric Field.

nope.
Electric field is a vector field.
Voltage is a scalar number.

Electric Field units are V/m
   Voltage units are V

you have apples and oranges, mixed up.

>
> Capacitance = farad = C/V = A^2*s^4 / kg*m^2
>
> Electrical Resistance = ohm = kg*m^2 /A^2*s^3
>
> Conductance = A/V = A^2*s^3 / kg*m^2
>
> Magnetic Flux = V*s = kg*m^2 /A*s^2
>
> Magnetic Field = tesla = kg /A*s^2
>
> Inductance =  kg*m^2 /A^2*s^2
>
> In Old Physics, the Faraday law is - curlxE = dB

nope, Maxwell-Faraday equation is  =>  ∇ × E = -dB/dt


> And one can immediately sense how wrong that is because it does not
> even give a opposing Magnetic Field to the changing magnetic field,
> as if a negative sign is sufficient to cover Lenz law.

no, that is the negative sign in Faraday's law of induction.

Volt generated = -N (d BA)/dt    see? no curl.



> So let us check this out in Units.
>
> In differental Calculus we have a Thrusting Bar Magnet. The Magnetic
> Field is
>
> kg /A*s^2
>
> To get Current you need V=iR, you need i = V/R
>
> So you need differention upon V and R^-1
>
> V is kg*m^2/A*s^3
>
> and R is kg*m^2 /A^2*s^3
>
> Notice that in all of these parameters listed that the Magnetic Field
> is a component thereof
>
> For example, in R, it can be broken down into kg/A*s^2 then factor of
> m^2/A*s
>
> V is kg/A*s^2 then factor of m^2/s

> So, as we differentiate VR^-1 we end up with at least two terms on
> the rightside of the equation for Faraday's law and thus, we have the
> Lenz's Opposing Magnetic Field.
>
> . \ .  . | .   /. . . \. . .|. . /. . ..\....|.../... ::\:::|::/::
> ---------------      ------------- --------------- (Y) -------------
>  ---------------      -------------- ::/:::|::\:: ../....|...\... . .
> /. . .|. . \. . . / .  . | .   \ .
>
>
> Research Disclaimer: Due to the unconventional and speculative nature
> of this posting and thread, it would be inadvisable for students to
> apply any of the contents to their school course work.
>
> http://www.iw.net/~a_plutonium/ 
whole entire Universe is just one
> big atom 
where dots of the electron-dot-cloud are galaxies
>
> I re-opened the old newsgroup PAU of 1990s and there one can read my
> recent posts without the hassle of spammers, off-topic-misfits,
> front-page-hogs, stalking mockers, suppression-bullies, and
> demonizers.
>
> https://groups.google.com/forum/?hl=en#!forum/plutonium-atom-universe
>  Archimedes Plutonium
>

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How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 15:07 -0700
  How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 17:25 -0700
  Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Serigo <invalid@invalid.com> - 2016-09-18 20:32 -0500
    Magnetic Field in most-everything Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 19:38 -0700
      Re: Magnetic Field in most-everything Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here moroney@world.std.spaamtrap.com (Michael Moroney) - 2016-09-19 15:51 +0000
        people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 13:07 -0700
          Re: people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors Serigo <invalid@invalid.com> - 2016-09-19 16:15 -0500
            Re: people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 14:29 -0700
              Re: people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors Serigo <invalid@invalid.com> - 2016-09-19 19:51 -0500
                Faraday law looks like (V*R^-1)' = A*R + B + constant; Ampere law looks like (A*R)' = B + V*A^-1 + constant Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 19:41 -0700
                Re: Faraday law looks like (V*R^-1)' = A*R + B + constant; Ampere law looks like (A*R)' = B + V*A^-1 + constant Serigo <invalid@invalid.com> - 2016-09-20 09:55 -0500
                Re: Faraday law looks like (V*R^-1)' = A*R + B + constant; Ampere law looks like (A*R)' = B + V*A^-1 + constant "hanson" <hanson@quick.net> - 2016-09-20 09:03 -0700
          Re: people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors moroney@world.std.spaamtrap.com (Michael Moroney) - 2016-09-19 22:26 +0000
            This moron thought a magnetic field is only a vector dependent on how it was derived Re: people that do not understand Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 19:23 -0700
              Re: This moron thought a magnetic field is only a vector dependent on how it was derived Re: people that do not understand Serigo <invalid@invalid.com> - 2016-09-19 21:41 -0500
                (A*R)' = A'*R  +  R'*A and derivative (V*R^-1)' = V'*R^-1  +  V*(R^-1)' Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 22:12 -0700
                derivative of magnetic field Re: (A*R)' = A'*R  +  R'*A and derivative (V*R^-1)' = V'*R^-1  +  V*(R^-1)' Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 23:45 -0700
                Re: (A*R)' = A'*R + R'*A and derivative (V*R^-1)' = V'*R^-1 + V*(R^-1)' Serigo <invalid@invalid.com> - 2016-09-20 10:09 -0500
              Re: This moron thought a magnetic field is only a vector dependent on how it was derived Re: people that do not understand moroney@world.std.spaamtrap.com (Michael Moroney) - 2016-09-20 04:08 +0000
                Re: This moron thought a magnetic field is only a vector dependent on how it was derived Re: people that do not understand Serigo <invalid@invalid.com> - 2016-09-20 10:28 -0500
                Re: This moron thought a magnetic field is only a vector dependent on how it was derived Re: people that do not understand moroney@world.std.spaamtrap.com (Michael Moroney) - 2016-09-20 16:40 +0000
    Someone in Old Physics trying to flesh out Faraday's law Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 20:03 -0700
      Re: Someone in Old Physics trying to flesh out Faraday's law Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Serigo <invalid@invalid.com> - 2016-09-18 22:31 -0500
        Old Physics Faraday law math does not match the experiment Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 20:51 -0700
          math that matches is the Product Rule in Differentiation that gives a Lenz law inside of Faraday law Re: Old Physics Faraday law math does not match the experiment Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 02:47 -0700
    trying to teach a brainwashed that velocity on Magnetic Field is just another Magnetic Field Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 20:20 -0700

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