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Groups > comp.lang.php > #8996
| From | bill <william@TechServSys.com> |
|---|---|
| Newsgroups | comp.lang.php |
| Subject | Re: comparing arrays |
| Date | 2013-04-07 11:34 -0400 |
| Organization | Aioe.org NNTP Server |
| Message-ID | <kjs3lm$gmi$1@speranza.aioe.org> (permalink) |
| References | <kjrlk6$8es$1@speranza.aioe.org> <kjrp0m$ote$1@dont-email.me> <kjru58$19d$1@speranza.aioe.org> <kjrv05$5lq$2@inn-newsserver.rz.tu-ilmenau.de> |
On 4/7/2013 10:14 AM, Frank Steinmetzger wrote: > bill wrote: > >> On 4/7/2013 8:34 AM, Jerry Stuckle wrote: >>> On 4/7/2013 7:34 AM, bill wrote: >>>> I need to see if a patient has appointments with a psychotherapist >>>> and a physician on the same day. >>>> >>>> I request the schedule of each therapist and each physician as >>>> arrays of arrays: >>>> time, patient_number, duration (note, the therapist/physician >>>> id is not in the array) >>>> They are non-associative arrays (numeric keys) >>>> I might have 1..n physicians and 1..n therapists >>>> I can generate arrays of physicians and arrays of therapists >>>> […] >>>> >>> Does the information come from a SQL database? If so, I'd do it >>> in SQL. >>> >> >> Yes it does, 3 tables: users (therapist/physician), pt_info, >> schedule. >> >> A little more of a hint please. > > You select two different appointments that have the same date: > > SELECT s1.patient_number AS pn, s1.time AS t1, s2.time AS t2, > s1.duration AS d1, s2.duration AS d2 > FROM schedule s1, schedule s2 > WHERE s1.time=s2.time AND s1.time=<today's date> > AND s1.patient_number=s2.patient_number > AND s1.patient_number=<ID of patient of interest> > AND s1.id!=s2.id > AND s1.doctor_number!=s2.doctor_number > > Of course, those times don't work that way, b/c they have date *and* time, > and you want to deal with date only. I'm not into advanced SQL, perhaps there > is an SQL function to only extract and use the date part. there is > > You then would need to PHP-fiddle the time and duration together for only > those appointments that are today in a nested for-loop. select s1.user as s1user, s2.user as s2user, s1.apptTime as s1apptTime, s2.apptTime as s2pptTime, users.physician, users.user_id from schedule as s1 join schedule as s2 join users on (s1.patient_number = s2.patient_number and users.user_id = s2.user) where s1.patient_number = s2.patient_number and s1.appt_status = 'a' and s2.appt_status = 'a' and s1.patient_number = '5214' and s1.schedule_id != s2.schedule_id and physician = '1' and date(s1.apptTime) = date(s2.apptTime) and date(s1.apptTime) = '2013-04-03' did the job Thanks for the great suggestion. bill
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comparing arrays bill <william@TechServSys.com> - 2013-04-07 07:34 -0400
Re: comparing arrays Jerry Stuckle <jstucklex@attglobal.net> - 2013-04-07 08:34 -0400
Re: comparing arrays bill <william@TechServSys.com> - 2013-04-07 10:00 -0400
Re: comparing arrays Frank Steinmetzger <frank.steinmetzger@stud.tu-ilmenau.de> - 2013-04-07 16:14 +0200
Re: comparing arrays Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2013-04-07 17:13 +0200
Re: comparing arrays bill <william@TechServSys.com> - 2013-04-07 11:34 -0400
Re: comparing arrays Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2013-04-07 21:33 +0200
Re: comparing arrays The Natural Philosopher <tnp@invalid.invalid> - 2013-04-07 16:01 +0100
Re: comparing arrays Frank Steinmetzger <frank.steinmetzger@stud.tu-ilmenau.de> - 2013-04-07 20:22 +0200
Re: comparing arrays Jerry Stuckle <jstucklex@attglobal.net> - 2013-04-07 14:18 -0400
Re: comparing arrays Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2013-04-07 15:37 +0200
Re: comparing arrays bill <william@TechServSys.com> - 2013-04-07 09:59 -0400
Re: comparing arrays Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2013-04-07 17:14 +0200
Re: comparing arrays The Natural Philosopher <tnp@invalid.invalid> - 2013-04-07 15:59 +0100
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