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Groups > comp.lang.php > #8996

Re: comparing arrays

From bill <william@TechServSys.com>
Newsgroups comp.lang.php
Subject Re: comparing arrays
Date 2013-04-07 11:34 -0400
Organization Aioe.org NNTP Server
Message-ID <kjs3lm$gmi$1@speranza.aioe.org> (permalink)
References <kjrlk6$8es$1@speranza.aioe.org> <kjrp0m$ote$1@dont-email.me> <kjru58$19d$1@speranza.aioe.org> <kjrv05$5lq$2@inn-newsserver.rz.tu-ilmenau.de>

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On 4/7/2013 10:14 AM, Frank Steinmetzger wrote:
> bill wrote:
>
>> On 4/7/2013 8:34 AM, Jerry Stuckle wrote:
>>> On 4/7/2013 7:34 AM, bill wrote:
>>>> I need to see if a patient has appointments with a psychotherapist
>>>> and a physician on the same day.
>>>>
>>>> I request the schedule of each therapist and each physician as
>>>> arrays of arrays:
>>>> time, patient_number, duration (note, the therapist/physician
>>>> id is not in the array)
>>>> They are non-associative arrays (numeric keys)
>>>> I might have 1..n physicians and 1..n therapists
>>>> I can generate arrays of physicians and arrays of therapists
>>>> […]
>>>>
>>> Does the information come from a SQL database?  If so, I'd do it
>>> in SQL.
>>>
>>
>> Yes it does, 3 tables: users (therapist/physician), pt_info,
>> schedule.
>>
>> A little more of a hint please.
>
> You select two different appointments that have the same date:
>
> SELECT s1.patient_number AS pn, s1.time AS t1, s2.time AS t2,
> 	s1.duration AS d1, s2.duration AS d2
> FROM schedule s1, schedule s2
> WHERE s1.time=s2.time AND s1.time=<today's date>
> 	AND s1.patient_number=s2.patient_number
> 	AND s1.patient_number=<ID of patient of interest>
> 	AND s1.id!=s2.id
> 	AND s1.doctor_number!=s2.doctor_number
>
> Of course, those times don't work that way, b/c they have date *and* time,
> and you want to deal with date only. I'm not into advanced SQL, perhaps there
> is an SQL function to only extract and use the date part.

there is
>
> You then would need to PHP-fiddle the time and duration together for only
> those appointments that are today in a nested for-loop.
select s1.user as s1user,
  s2.user as s2user,
  s1.apptTime as s1apptTime,
  s2.apptTime as s2pptTime,
users.physician,
users.user_id
from schedule as s1 join schedule as s2 join users
on  (s1.patient_number = s2.patient_number
and users.user_id = s2.user)

where s1.patient_number = s2.patient_number
  and s1.appt_status = 'a'
  and s2.appt_status = 'a'
and s1.patient_number = '5214'
and s1.schedule_id != s2.schedule_id
and physician = '1'
and date(s1.apptTime) = date(s2.apptTime)
and date(s1.apptTime) = '2013-04-03'

did the job

Thanks for the great suggestion.

bill

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Thread

comparing arrays bill <william@TechServSys.com> - 2013-04-07 07:34 -0400
  Re: comparing arrays Jerry Stuckle <jstucklex@attglobal.net> - 2013-04-07 08:34 -0400
    Re: comparing arrays bill <william@TechServSys.com> - 2013-04-07 10:00 -0400
      Re: comparing arrays Frank Steinmetzger <frank.steinmetzger@stud.tu-ilmenau.de> - 2013-04-07 16:14 +0200
        Re: comparing arrays Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2013-04-07 17:13 +0200
        Re: comparing arrays bill <william@TechServSys.com> - 2013-04-07 11:34 -0400
          Re: comparing arrays Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2013-04-07 21:33 +0200
      Re: comparing arrays The Natural Philosopher <tnp@invalid.invalid> - 2013-04-07 16:01 +0100
        Re: comparing arrays Frank Steinmetzger <frank.steinmetzger@stud.tu-ilmenau.de> - 2013-04-07 20:22 +0200
      Re: comparing arrays Jerry Stuckle <jstucklex@attglobal.net> - 2013-04-07 14:18 -0400
  Re: comparing arrays Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2013-04-07 15:37 +0200
    Re: comparing arrays bill <william@TechServSys.com> - 2013-04-07 09:59 -0400
      Re: comparing arrays Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2013-04-07 17:14 +0200
  Re: comparing arrays The Natural Philosopher <tnp@invalid.invalid> - 2013-04-07 15:59 +0100

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