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50- Unification of Periodic Table of Chemical Elements with Table of Elementary Physics Particles is a Faraday Law unification// TRUE CHEMISTRY textbook

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50- Unification of Periodic Table of Chemical Elements with Table of Elementary Physics Particles is a Faraday Law unification// TRUE CHEMISTRY textbook

So we have using Sigma Error (see previous chapter- 49) that the exact number for Electron = muon = 105 MeV, exact proton = 840MeV, exact neutron = 945 MeV, then what is the exact Dirac Magnetic Monopole? Is it .5MeV exactly? And why?

Well, we have something in mathematics and physics that is rather strange. For we want to assign numbers to building the atoms, their structure. We have orbitals of s, p, d, f in chemistry and we have Quantum Numbers that are assigned. So we have angular momentum and spin and we need numbers to assign to these N, L, M_L, M_s

To make our assignment of numbers to concepts of Physics, we use both negative and positive whole numbers.

. . ,-2, -1, 0, 1, 2, . .

Turns out, in math and physics, there is no escaping the use of negative with positive whole numbers in order to solve N, L, M_L, M_s

It is as if Physics and Chemistry want a Balancing Concept of numbers, where we balance one end with the other end and the midpoint is 0. A balancing beam sits in the heart of physics and chemistry, and the math numbers are 0 flanked by positive integers on one side and negative integers on the other side. This solves N thru M_L, but when we reach M_s, we run out of math numbers as a Balancing Beam, except, of course, .5 or the number 1/2 with 

. . ,-1/2, 0, +1/2, . .

And we have where 1/2 + 1/2 makes a full 1.

The 1/2 is of course, .5. So the question is, is the Dirac Magnetic Monopole exactly .5MeV or is it .511MeV as listed in Halliday, Resnick.

Can sigma error solve this question once and for always in physics?

Well, if we assume .5 is the true exact Dirac Magnetic Monopole implies that the monopole is the M_s, the spin in the fourth quantum number. That a photon is also geometrically spin.

But, can Sigma Error solve the question also? So we have exact muon is 105 divided by .5 would be 210, proton is 840 divided by .5 is 1680, the Omega particle is 1673 which decays to a Lambda and Kaon, and Lambda decays to a proton and pion.

So if we had magnetic monopole at .511MeV and proton in Old Physics of 938MeV we would have proton at 938 divided by .511 is 1835.61 and nowhere near Omega at 1673MeV.

Now, we have a good idea why the .5MeV particle exists and why the 840 MeV proton exists and why the electron = muon = 105 MeV particle exists and why the 945MeV neutron exists, but we have no clue as to why a tau particle exists and its function. It is 1784 MeV. So, can we shed light as to why such a particle exists?

AP

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50- Unification of Periodic Table of Chemical Elements with Table of Elementary Physics Particles is a Faraday Law unification// TRUE CHEMISTRY textbook Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2018-06-07 14:52 -0700
  is the magnetic monopole at .5MeV a unique particle in all of physics with its charge energy // TRUE CHEMISTRY textbook Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2018-06-07 17:50 -0700
    is the magnetic monopole at .5MeV a unique particle in all of physics with its charge energy // TRUE CHEMISTRY textbook Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2018-06-07 19:32 -0700
      Re: is the magnetic monopole at .5MeV a unique particle in all of physics with its charge energy // TRUE CHEMISTRY textbook poraty149@gmail.com - 2018-06-07 20:49 -0700

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