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Groups > comp.lang.c > #76042

Re: how to do this?

From James Kuyper <jameskuyper@verizon.net>
Newsgroups comp.lang.c
Subject Re: how to do this?
Date 2015-11-14 18:17 -0500
Organization Self
Message-ID <5647C100.40005@verizon.net> (permalink)
References <n2849g$a6p$1@dont-email.me> <dapqp9Fi0ttU9@mid.individual.net> <n28emj$nl3$1@dont-email.me>

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On 11/14/2015 06:07 PM, bilsch01 wrote:
> On 11/14/2015 02:26 PM, Ian Collins wrote:
>> bilsch01 wrote:
>>
>> One I missed earlier:
>>
>>> char mk1[9] = "**  1  **", mk2[9] = "**  2  **", mk3[9] = "**  3  **";
>>
>> These aren't null terminated strings.
>>
>>>
>>>             if (strcmp(vec2, vec1) == 0)
>>>                     strcpy(vec2, mk1);
>>
>> So this copy could go horribly wrong.
>>
> why isn't "**  1  **" a null terminated string?  How should I declare it 
> to make it null terminated?
> 
> char "**  1  **",0
> 
> I thought when you declare an array of type char it gets null terminated 
> if "" are used.

Only if it's big enough to store the terminating null character. For
example, It requires 6 char objects to store 'h', 'e', 'l', 'l', 'o' and
the terminating '\0' character.

    char unterminated[5] = "hello";
    char terminated1[6] = "hello";

If you don't specify the length, it's automatically set big enough to
include the terminating null character:

    char terminated2[] = "hello";

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Thread

how to do this? bilsch01 <king621@comcast.net> - 2015-11-14 12:09 -0800
  Re: how to do this? Rosario19 <Ros@invalid.invalid> - 2015-11-14 21:49 +0100
  Re: how to do this? Ian Collins <ian-news@hotmail.com> - 2015-11-15 10:02 +1300
    Re: how to do this? Ian Collins <ian-news@hotmail.com> - 2015-11-15 10:17 +1300
    Re: how to do this? bilsch01 <king621@comcast.net> - 2015-11-14 15:16 -0800
      Re: how to do this? James Kuyper <jameskuyper@verizon.net> - 2015-11-14 18:24 -0500
        Re: how to do this? bilsch01 <king621@comcast.net> - 2015-11-14 15:30 -0800
          Re: how to do this? Lew Pitcher <lew.pitcher@digitalfreehold.ca> - 2015-11-14 19:01 -0500
          Re: how to do this? James Kuyper <jameskuyper@verizon.net> - 2015-11-14 19:07 -0500
  Re: how to do this? Ian Collins <ian-news@hotmail.com> - 2015-11-15 11:26 +1300
    Re: how to do this? bilsch01 <king621@comcast.net> - 2015-11-14 15:07 -0800
      Re: how to do this? James Kuyper <jameskuyper@verizon.net> - 2015-11-14 18:17 -0500
      Re: how to do this? bilsch01 <king621@comcast.net> - 2015-11-14 15:25 -0800
        Re: how to do this? Ian Collins <ian-news@hotmail.com> - 2015-11-15 13:10 +1300
          Re: how to do this? James Kuyper <jameskuyper@verizon.net> - 2015-11-14 19:21 -0500
            Re: how to do this? Ian Collins <ian-news@hotmail.com> - 2015-11-15 13:24 +1300
        Re: how to do this? James Kuyper <jameskuyper@verizon.net> - 2015-11-14 19:12 -0500
          Re: how to do this? Ian Collins <ian-news@hotmail.com> - 2015-11-15 13:18 +1300
            Re: how to do this? James Kuyper <jameskuyper@verizon.net> - 2015-11-14 19:23 -0500
  Re: how to do this? bilsch01 <king621@comcast.net> - 2015-11-14 15:18 -0800

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