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Re: Something related to the Collision of Protons

Cross-posted to 2 groups.

Followups directed to: sci.physics

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Odd Bodkin wrote:

> On 10/30/2015 12:44 PM, Bobby Sifuentes wrote:
>> Thomas 'PointedEars' Lahn wrote:
>>>> The energy of a proton is 7 TeV.
>>> No, it is not.  That is the *collision* energy coming from at least
>>> *two* colliding protons.
>> Well, would be quite impossible to collide a proton alone. What is the
>> cross-section of a proton?
> 
> Most of the time this is talked about as a "differential" cross section,
> where this means essentially the rate of scattering where the incoming
> particle is scattered by a particular angle.
> 
> This is a classical mechanics problem, and Rutherford worked it out when
> he was trying to figure out alpha-nucleus scattering.
> 
> https://en.wikipedia.org/wiki/Rutherford_scattering
> 
> The equation is the one directly *above* the section header "Details of
> calculating maximal nuclear size". For proton-proton scattering, Z=1.

Congratulations, you actually managed to top the stupidity of the question 
of the ’nym-shifting troll with a wrong answer that has nothing to do with 
it.


PointedEars
-- 
“Science is empirical: knowing the answer means nothing;
 testing your knowledge means everything.”
   —Dr. Lawrence M. Krauss, theoretical physicist,
    in “A Universe from Nothing” (2009)

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(((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-26 20:34 -0700
  Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-27 08:33 -0700
    Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-27 08:44 -0700
      Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-27 08:46 -0700
      Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-27 08:53 -0700
        Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 07:34 -0700
          Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 07:46 -0700
            Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 09:42 -0700
              Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 10:17 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 10:25 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 10:51 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 10:54 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 19:29 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 19:59 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-29 10:43 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-29 10:44 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-29 11:03 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 kefischer <emoneyjoe@iglou.com> - 2015-10-28 17:29 -0400
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 15:37 -0700
            Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 09:51 -0700
        Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2015-10-30 18:31 +0100
          Something related to the Collision of Protons Bobby Sifuentes <bobsif@academicinstitute.org> - 2015-10-30 17:44 +0000
            Re: Something related to the Collision of Protons Odd Bodkin <bodkinodd@gmail.com> - 2015-10-30 14:11 -0500
              Re: Something related to the Collision of Protons Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2015-10-30 21:06 +0100
                Re: Something related to the Collision of Protons Bobby Sifuentes <bobsif@academicinstitute.org> - 2015-10-30 20:47 +0000
                Re: Something related to the Collision of Protons Bobby Sifuentes <bobsif@academicinstitute.org> - 2015-10-30 20:49 +0000
                Re: Something related to the Collision of Protons Bobby Sifuentes <bobsif@academicinstitute.org> - 2015-10-30 20:54 +0000
                Re: Something related to the Collision of Protons Bobby Sifuentes <bobsif@academicinstitute.org> - 2015-10-30 21:52 +0000
                Re: Something related to the Collision of Protons Bobby Sifuentes <bobsif@academicinstitute.org> - 2015-10-30 21:59 +0000
                Re: Something related to the Collision of Protons fuller.david@hotmail.com - 2015-10-30 22:20 -0700
          Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 John Heath <heathjohn2@gmail.com> - 2015-10-30 16:10 -0700
            Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-30 21:34 -0700
          Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-30 21:32 -0700
            Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2015-10-31 06:50 +0100
              Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Jack Weidner <jackwd@webportal.au> - 2015-10-31 11:20 +0000
              Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-31 05:48 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2015-10-31 16:16 +0100
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-31 08:32 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-31 08:35 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2015-10-31 17:18 +0100
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Hyperbolic.cc@outlook.com - 2015-10-31 09:30 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Hyperbolic.cc@outlook.com - 2015-10-31 09:38 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 kefischer <emoneyjoe@iglou.com> - 2015-10-31 13:42 -0400
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Hyperbolic.cc@outlook.com - 2015-10-31 09:58 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-31 12:15 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-11-04 07:58 -0800
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Hyperbolic.cc@outlook.com - 2015-11-05 08:49 -0800
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 kefischer <emoneyjoe@iglou.com> - 2015-11-05 12:08 -0500
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Poutnik <Poutnik4NNTP@gmail.com> - 2015-11-05 19:23 +0100
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-31 12:11 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Hyperbolic.cc@outlook.com - 2015-10-31 09:59 -0700

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