Groups > sci.physics.relativity > #368580

Something related to the Collision of Protons

From	Bobby Sifuentes <bobsif@academicinstitute.org>
Newsgroups	sci.physics.relativity, sci.physics
Subject	Something related to the Collision of Protons
Date	2015-10-30 17:44 +0000
Organization	Local Focus Inc
Message-ID	<n10aa4$cfk$1@speranza.aioe.org> (permalink)
References	<5cf2af61-4464-4be0-b3a0-65878fdd881c@googlegroups.com> <be20fd36-5c65-4bcd-a0fe-2fb48a3eee46@googlegroups.com> <8c29812f-4705-4a7f-be4c-3b58280f4b28@googlegroups.com> <e2a78e57-a4c3-4e58-837e-29f59b31b7ff@googlegroups.com> <2895113.jQvESdZhOY@PointedEars.de>

Cross-posted to 2 groups.

Show all headers | View raw

Thomas 'PointedEars' Lahn wrote:

>> The energy of a proton is 7 TeV.
> 
> No, it is not.  That is the *collision* energy coming from at least
> *two* colliding protons.

Well, would be quite impossible to collide a proton alone. What is the
cross-section of a proton?

Thread

(((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-26 20:34 -0700
  Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-27 08:33 -0700
    Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-27 08:44 -0700
      Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-27 08:46 -0700
      Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-27 08:53 -0700
        Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 07:34 -0700
          Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 07:46 -0700
            Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 09:42 -0700
              Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 10:17 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 10:25 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 10:51 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 10:54 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 19:29 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 19:59 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-29 10:43 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-29 10:44 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-29 11:03 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 kefischer <emoneyjoe@iglou.com> - 2015-10-28 17:29 -0400
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 15:37 -0700
            Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-28 09:51 -0700
        Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2015-10-30 18:31 +0100
          Something related to the Collision of Protons Bobby Sifuentes <bobsif@academicinstitute.org> - 2015-10-30 17:44 +0000
            Re: Something related to the Collision of Protons Odd Bodkin <bodkinodd@gmail.com> - 2015-10-30 14:11 -0500
              Re: Something related to the Collision of Protons Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2015-10-30 21:06 +0100
                Re: Something related to the Collision of Protons Bobby Sifuentes <bobsif@academicinstitute.org> - 2015-10-30 20:47 +0000
                Re: Something related to the Collision of Protons Bobby Sifuentes <bobsif@academicinstitute.org> - 2015-10-30 20:49 +0000
                Re: Something related to the Collision of Protons Bobby Sifuentes <bobsif@academicinstitute.org> - 2015-10-30 20:54 +0000
                Re: Something related to the Collision of Protons Bobby Sifuentes <bobsif@academicinstitute.org> - 2015-10-30 21:52 +0000
                Re: Something related to the Collision of Protons Bobby Sifuentes <bobsif@academicinstitute.org> - 2015-10-30 21:59 +0000
                Re: Something related to the Collision of Protons fuller.david@hotmail.com - 2015-10-30 22:20 -0700
          Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 John Heath <heathjohn2@gmail.com> - 2015-10-30 16:10 -0700
            Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-30 21:34 -0700
          Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-30 21:32 -0700
            Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2015-10-31 06:50 +0100
              Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Jack Weidner <jackwd@webportal.au> - 2015-10-31 11:20 +0000
              Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-31 05:48 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2015-10-31 16:16 +0100
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-31 08:32 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-31 08:35 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2015-10-31 17:18 +0100
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Hyperbolic.cc@outlook.com - 2015-10-31 09:30 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Hyperbolic.cc@outlook.com - 2015-10-31 09:38 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 kefischer <emoneyjoe@iglou.com> - 2015-10-31 13:42 -0400
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Hyperbolic.cc@outlook.com - 2015-10-31 09:58 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-31 12:15 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-11-04 07:58 -0800
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Hyperbolic.cc@outlook.com - 2015-11-05 08:49 -0800
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 kefischer <emoneyjoe@iglou.com> - 2015-11-05 12:08 -0500
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Poutnik <Poutnik4NNTP@gmail.com> - 2015-11-05 19:23 +0100
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 fuller.david@hotmail.com - 2015-10-31 12:11 -0700
                Re: (((4 * pi * (10^(-7)))^2) / 2)^pi = 9.5176229e-39 Hyperbolic.cc@outlook.com - 2015-10-31 09:59 -0700

csiph-web