Re: Nuclei actually have near zero velocity when fusion occurs during beam fusion...

From	Odd Bodkin <bodkinodd@gmail.com>
Newsgroups	sci.physics
Subject	Re: Nuclei actually have near zero velocity when fusion occurs during beam fusion...
Date	2016-08-21 18:10 -0500
Organization	Aioe.org NNTP Server
Message-ID	<npdcc9$1cd8$1@gioia.aioe.org> (permalink)
References	(2 earlier) <ef840208-eb9c-4ad3-bd00-0e787c569343@googlegroups.com> <np501e$1if2$1@gioia.aioe.org> <133dbd33-c875-484b-a0b2-580cb87ed58f@googlegroups.com> <np7skv$1uis$1@gioia.aioe.org> <77b93c3e-ab5a-4e9f-807a-8b488dd9505b@googlegroups.com>

Show all headers | View raw

On 8/20/2016 11:56 AM, Sven Andersson wrote:
>>> > > Yes, I saw your arguments and they are not convincing. When you irradiate, say a solid lithium
>>> > > target with protons of high energy there is a lot of radiation flying around, some of it
>>> > > bremsstrahlung (from protons that make near misses) and some of it from fusion. Meaning, that
>>> > > the important radiation that I claim exists, will be missed by scientists. Remember; only one
>>> > > nucleus in a million is on a trajectory that leads exactly towards a target nucleus. Very precise
>>> > > measurements may be able to detect that radiation though.
>> >
>> > I'm talking about collider experiments, not fixed target experiments. In
>> > a collider experiment you are directly looking at nucleon-nucleon
>> > interactions.
> The interaction of the charged particles, the nuclei, leads to kinetic energy being transformed into EM
> energy. Depending on the trajectory of the particles there will be created, sequentially EM quanta with
> increasing energy. Sometimes (one in a million) all of the kinetic energy, or almost all will go into EM
> energy. In that case the last EM quantum is probably a gamma ray photon. It will be missed, most likely,
> by investigators because there is so much other radiation.
>

I really think you should take a look at the instrumentation of a 
collider detector. The entire interaction region is surrounded by EM 
calorimetry, whose sole function is to NOT miss EM energy (usually in 
the form of gammas and X-rays), except for a tiny aperture where the 
beams pass through.

The fact is, this bremsstrahlung radiation that you claim is associated 
with the slowdown of the interacting hadrons would be easily observed in 
the surrounding detector if it were there. But it is not seen, which you 
will see if you actually looked at some experimental papers in the 
field. This lack of evidence of something you definitively predict is 
sufficient to rule out your theory.

On a basic note, you should be concerned if you are presenting a theory 
which has an explanation with observable outcomes, but the only way you 
can maintain your hope in the theory is by claiming that the observable 
outcome is not really observable. If the theory is not TESTABLE through 
observations, then it isn't really a viable theory in the first place.

-- 
Odd Bodkin --- maker of fine toys, tools, tables

Thread

csiph-web