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Groups > sci.physics.relativity > #389430 > unrolled thread

Zero Gravity

Started byPeter Riedt <riedt1@yahoo.co.uk>
First post2016-08-07 23:45 -0700
Last post2016-08-09 07:39 +0200
Articles 20 on this page of 28 — 8 participants

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Contents

  Zero Gravity Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-07 23:45 -0700
    Re: Zero Gravity Poutnik <poutnik4nntp@gmail.com> - 2016-08-08 09:06 +0200
      Re: Zero Gravity Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-08 00:25 -0700
    Re: Zero Gravity Sylvia Else <sylvia@not.at.this.address> - 2016-08-08 22:27 +1000
      Re: Zero Gravity Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-08 21:57 -0700
        Re: Zero Gravity Poutnik <poutnik4nntp@gmail.com> - 2016-08-09 07:47 +0200
          Re: Zero Gravity Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-09 03:14 -0700
            Re: Zero Gravity "Dono," <sa_ge@comcast.net> - 2016-08-09 09:48 -0700
        Re: Zero Gravity Sylvia Else <sylvia@not.at.this.address> - 2016-08-09 16:38 +1000
          Re: Zero Gravity "Paul B. Andersen" <relativity@paulba.no> - 2016-08-09 22:57 +0200
            Re: Zero Gravity Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-09 19:11 -0700
          Re: Zero Gravity Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-09 17:20 -0700
            Re: Zero Gravity "Dono," <sa_ge@comcast.net> - 2016-08-09 17:59 -0700
              Re: Zero Gravity Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-09 18:42 -0700
                Re: Zero Gravity "Dono," <sa_ge@comcast.net> - 2016-08-09 20:10 -0700
                Re: Zero Gravity Odd Bodkin <bodkinodd@gmail.com> - 2016-08-10 08:36 -0500
            Re: Zero Gravity Sylvia Else <sylvia@not.at.this.address> - 2016-08-10 13:12 +1000
              Re: Zero Gravity Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-10 00:56 -0700
              Re: Zero Gravity Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-10 01:02 -0700
                Re: Zero Gravity Mikko <mikko.levanto@outlook.com> - 2016-08-10 11:35 +0300
                  Re: Zero Gravity Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-10 02:30 -0700
                Re: Zero Gravity Odd Bodkin <bodkinodd@gmail.com> - 2016-08-10 08:53 -0500
            Re: Zero Gravity Odd Bodkin <bodkinodd@gmail.com> - 2016-08-10 08:35 -0500
        Re: Zero Gravity Odd Bodkin <bodkinodd@gmail.com> - 2016-08-09 07:07 -0500
          Re: Zero Gravity Peter Riedt <riedt1@yahoo.co.uk> - 2016-08-10 02:41 -0700
            Re: Zero Gravity Gary Harnagel <hitlong@yahoo.com> - 2016-08-10 04:12 -0700
            Re: Zero Gravity Odd Bodkin <bodkinodd@gmail.com> - 2016-08-10 08:55 -0500
      Re: Zero Gravity Poutnik <poutnik4nntp@gmail.com> - 2016-08-09 07:39 +0200

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#389430 — Zero Gravity

FromPeter Riedt <riedt1@yahoo.co.uk>
Date2016-08-07 23:45 -0700
SubjectZero Gravity
Message-ID<c8f3786f-4a2a-4555-861a-901f677e8bcd@googlegroups.com>
Zero Gravity

The gravitational force applied by the sun on each planet decreases with distance. It is 3.95750392900614E-02m/sec2 (small g) at the distance of Mercury and diminishes by a factor of 1000 with every assumed increase of distance of 10m and a corresponding decrease of orbital velocity by 10m (gsunatpl = vm^2/rm).

When is it zero?

         rm	                      vm	            gsunatpl 
5.79092310294605E+10	4.78723311866901E+04	3.95750392900614E-02
5.79092310294605E+11	4.78723311866901E+03	3.95750392900614E-05
5.79092310294605E+12	4.78723311866901E+02	3.95750392900614E-08
5.79092310294605E+13	4.78723311866901E+01	3.95750392900614E-11
5.79092310294605E+14	4.78723311866901E+00	3.95750392900614E-14
5.79092310294605E+15	4.78723311866901E-01	3.95750392900614E-17
5.79092310294605E+16	4.78723311866901E-02	3.95750392900614E-20
5.79092310294605E+17	4.78723311866901E-03	3.95750392900614E-23
5.79092310294605E+18	4.78723311866901E-04	3.95750392900614E-26
5.79092310294605E+19	4.78723311866901E-05	3.95750392900614E-29
5.79092310294605E+20	4.78723311866901E-06	3.95750392900614E-32
5.79092310294605E+21	4.78723311866901E-07	3.95750392900614E-35

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#389431

FromPoutnik <poutnik4nntp@gmail.com>
Date2016-08-08 09:06 +0200
Message-ID<no9b22$3j3$1@dont-email.me>
In reply to#389430
Dne 08/08/2016 v 08:45 Peter Riedt napsal(a):
> Zero Gravity
> 
> The gravitational force applied by the sun on each planet decreases with distance. It is 3.95750392900614E-02m/sec2 (small g) at the distance of Mercury and diminishes by a factor of 1000 with every assumed increase of distance of 10m and a corresponding decrease of orbital velocity by 10m (gsunatpl = vm^2/rm).
> 
> When is it zero?
> 
....

When is function y = const / x^2 equal to zero ?
Never for any real x, as infinity is not a real number.

We can just say for x going toward +infinity
y goes toward zero.

lim y( x -> +inf) = 0

-- 
Poutnik ( The Pilgrim, Der Wanderer )
Knowledge makes great men humble, but small men arrogant.

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#389432

FromPeter Riedt <riedt1@yahoo.co.uk>
Date2016-08-08 00:25 -0700
Message-ID<c4b04cf3-91da-4485-907d-bc81a72b2d36@googlegroups.com>
In reply to#389431
On Monday, August 8, 2016 at 3:06:43 PM UTC+8, Poutnik wrote:
> Dne 08/08/2016 v 08:45 Peter Riedt napsal(a):
> > Zero Gravity
> > 
> > The gravitational force applied by the sun on each planet decreases with distance. It is 3.95750392900614E-02m/sec2 (small g) at the distance of Mercury and diminishes by a factor of 1000 with every assumed increase of distance of 10m and a corresponding decrease of orbital velocity by 10m (gsunatpl = vm^2/rm).
> > 
> > When is it zero?
> > 
> ....
> 
> When is function y = const / x^2 equal to zero ?
> Never for any real x, as infinity is not a real number.
> 
> We can just say for x going toward +infinity
> y goes toward zero.
> 
> lim y( x -> +inf) = 0
> 
> -- 
> Poutnik ( The Pilgrim, Der Wanderer )
> Knowledge makes great men humble, but small men arrogant.

Good answer.

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#389439

FromSylvia Else <sylvia@not.at.this.address>
Date2016-08-08 22:27 +1000
Message-ID<e0rc6aFl2tgU1@mid.individual.net>
In reply to#389430
On 8/08/2016 4:45 PM, Peter Riedt wrote:
> Zero Gravity
>
> The gravitational force applied by the sun on each planet decreases with distance. It is 3.95750392900614E-02m/sec2 (small g) at the distance of Mercury and diminishes by a factor of 1000 with every assumed increase of distance of 10m and a corresponding decrease of orbital velocity by 10m (gsunatpl = vm^2/rm).
>
> When is it zero?
>
>           rm	                      vm	            gsunatpl
> 5.79092310294605E+10	4.78723311866901E+04	3.95750392900614E-02
> 5.79092310294605E+11	4.78723311866901E+03	3.95750392900614E-05
> 5.79092310294605E+12	4.78723311866901E+02	3.95750392900614E-08
> 5.79092310294605E+13	4.78723311866901E+01	3.95750392900614E-11
> 5.79092310294605E+14	4.78723311866901E+00	3.95750392900614E-14
> 5.79092310294605E+15	4.78723311866901E-01	3.95750392900614E-17
> 5.79092310294605E+16	4.78723311866901E-02	3.95750392900614E-20
> 5.79092310294605E+17	4.78723311866901E-03	3.95750392900614E-23
> 5.79092310294605E+18	4.78723311866901E-04	3.95750392900614E-26
> 5.79092310294605E+19	4.78723311866901E-05	3.95750392900614E-29
> 5.79092310294605E+20	4.78723311866901E-06	3.95750392900614E-32
> 5.79092310294605E+21	4.78723311866901E-07	3.95750392900614E-35
>

When the planet is at the centre of the sun.

Sylvia.

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#389551

FromPeter Riedt <riedt1@yahoo.co.uk>
Date2016-08-08 21:57 -0700
Message-ID<c59a2c0a-ac06-4aaa-a3ce-87e361d24d76@googlegroups.com>
In reply to#389439
On Monday, August 8, 2016 at 8:27:57 PM UTC+8, Sylvia Else wrote:
> On 8/08/2016 4:45 PM, Peter Riedt wrote:
> > Zero Gravity
> >
> > The gravitational force applied by the sun on each planet decreases with distance. It is 3.95750392900614E-02m/sec2 (small g) at the distance of Mercury and diminishes by a factor of 1000 with every assumed increase of distance of 10m and a corresponding decrease of orbital velocity by 10m (gsunatpl = vm^2/rm).
> >
> > When is it zero?
> >
> >           rm	                      vm	            gsunatpl
> > 5.79092310294605E+10	4.78723311866901E+04	3.95750392900614E-02
> > 5.79092310294605E+11	4.78723311866901E+03	3.95750392900614E-05
> > 5.79092310294605E+12	4.78723311866901E+02	3.95750392900614E-08
> > 5.79092310294605E+13	4.78723311866901E+01	3.95750392900614E-11
> > 5.79092310294605E+14	4.78723311866901E+00	3.95750392900614E-14
> > 5.79092310294605E+15	4.78723311866901E-01	3.95750392900614E-17
> > 5.79092310294605E+16	4.78723311866901E-02	3.95750392900614E-20
> > 5.79092310294605E+17	4.78723311866901E-03	3.95750392900614E-23
> > 5.79092310294605E+18	4.78723311866901E-04	3.95750392900614E-26
> > 5.79092310294605E+19	4.78723311866901E-05	3.95750392900614E-29
> > 5.79092310294605E+20	4.78723311866901E-06	3.95750392900614E-32
> > 5.79092310294605E+21	4.78723311866901E-07	3.95750392900614E-35
> >
> 
> When the planet is at the centre of the sun.
> 
> Sylvia.

Incorrect. Gravity is at maximum at the centre of the sun. At the distance of the surface of the planet from the centre it is less but not zero.

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#389554

FromPoutnik <poutnik4nntp@gmail.com>
Date2016-08-09 07:47 +0200
Message-ID<nobqpm$qto$1@dont-email.me>
In reply to#389551
Dne 09/08/2016 v 06:57 Peter Riedt napsal(a):

> 
> Incorrect. Gravity is at maximum at the centre of the sun. At the distance of the surface of the planet from the centre it is less but not zero.

Gravity decreases toward zero when approaching the Sun centre,
when significant Sun mass is out of your radius to the centre.

For spherically symmetric object,
the gravity at distance R to the centre
equals to gravity of a partial object
with radius R.

In reality, some residual gravity would ramain,
due variations from perfect symmetry.

-- 
Poutnik ( The Pilgrim, Der Wanderer )
Knowledge makes great men humble, but small men arrogant.

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#389561

FromPeter Riedt <riedt1@yahoo.co.uk>
Date2016-08-09 03:14 -0700
Message-ID<f062bdb0-78c8-4a09-a32c-f9c9e57b0fec@googlegroups.com>
In reply to#389554
On Tuesday, August 9, 2016 at 1:47:35 PM UTC+8, Poutnik wrote:
> Dne 09/08/2016 v 06:57 Peter Riedt napsal(a):
> 
> > 
> > Incorrect. Gravity is at maximum at the centre of the sun. At the distance of the surface of the planet from the centre it is less but not zero.
> 
> Gravity decreases toward zero when approaching the Sun centre,
> when significant Sun mass is out of your radius to the centre.
> 
Small g gravity is at a maximum at the centre of the sun. It decreases with distance. At the surface it is 273msec2, at the distance of Mercury it is 0.03957msec2 and at the distance of Pluto it is 0.000003804msec2.

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#389597

From"Dono," <sa_ge@comcast.net>
Date2016-08-09 09:48 -0700
Message-ID<0c82f1b7-e69a-470b-bae9-cc00e2e7f067@googlegroups.com>
In reply to#389561
On Tuesday, August 9, 2016 at 3:15:02 AM UTC-7, Peter Riedt wrote:
> On Tuesday, August 9, 2016 at 1:47:35 PM UTC+8, Poutnik wrote:
> > Dne 09/08/2016 v 06:57 Peter Riedt napsal(a):
> > 
> > > 
> > > Incorrect. Gravity is at maximum at the centre of the sun. At the distance of the surface of the planet from the centre it is less but not zero.
> > 
> > Gravity decreases toward zero when approaching the Sun centre,
> > when significant Sun mass is out of your radius to the centre.
> > 
> Small g gravity is at a maximum at the centre of the sun. It decreases with distance. At the surface it is 273msec2, at the distance of Mercury it is 0.03957msec2 and at the distance of Pluto it is 0.000003804msec2.

Gauss theorem says that you are a cretin. Your post history PROVES that you are a cretin.

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#389558

FromSylvia Else <sylvia@not.at.this.address>
Date2016-08-09 16:38 +1000
Message-ID<e0tc2bF59e6U1@mid.individual.net>
In reply to#389551
On 9/08/2016 2:57 PM, Peter Riedt wrote:
> On Monday, August 8, 2016 at 8:27:57 PM UTC+8, Sylvia Else wrote:
>> On 8/08/2016 4:45 PM, Peter Riedt wrote:
>>> Zero Gravity
>>>
>>> The gravitational force applied by the sun on each planet decreases with distance. It is 3.95750392900614E-02m/sec2 (small g) at the distance of Mercury and diminishes by a factor of 1000 with every assumed increase of distance of 10m and a corresponding decrease of orbital velocity by 10m (gsunatpl = vm^2/rm).
>>>
>>> When is it zero?
>>>
>>>            rm	                      vm	            gsunatpl
>>> 5.79092310294605E+10	4.78723311866901E+04	3.95750392900614E-02
>>> 5.79092310294605E+11	4.78723311866901E+03	3.95750392900614E-05
>>> 5.79092310294605E+12	4.78723311866901E+02	3.95750392900614E-08
>>> 5.79092310294605E+13	4.78723311866901E+01	3.95750392900614E-11
>>> 5.79092310294605E+14	4.78723311866901E+00	3.95750392900614E-14
>>> 5.79092310294605E+15	4.78723311866901E-01	3.95750392900614E-17
>>> 5.79092310294605E+16	4.78723311866901E-02	3.95750392900614E-20
>>> 5.79092310294605E+17	4.78723311866901E-03	3.95750392900614E-23
>>> 5.79092310294605E+18	4.78723311866901E-04	3.95750392900614E-26
>>> 5.79092310294605E+19	4.78723311866901E-05	3.95750392900614E-29
>>> 5.79092310294605E+20	4.78723311866901E-06	3.95750392900614E-32
>>> 5.79092310294605E+21	4.78723311866901E-07	3.95750392900614E-35
>>>
>>
>> When the planet is at the centre of the sun.
>>
>> Sylvia.
>
> Incorrect. Gravity is at maximum at the centre of the sun. At the distance of the surface of the planet from the centre it is less but not zero.
>

I encountered a physics student who made that claim.

It should be obvious that it cannot possibly be true - what would the 
direction of the force be?

Sylvia.

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#389616

From"Paul B. Andersen" <relativity@paulba.no>
Date2016-08-09 22:57 +0200
Message-ID<nodg4a$rbk$1@news.albasani.net>
In reply to#389558
On 09.08.2016 08:38, Sylvia Else wrote:
> On 9/08/2016 2:57 PM, Peter Riedt wrote:
>> On Monday, August 8, 2016 at 8:27:57 PM UTC+8, Sylvia Else wrote:
>>> On 8/08/2016 4:45 PM, Peter Riedt wrote:
>>>> Zero Gravity
>>>>
>>>> The gravitational force applied by the sun on each planet decreases
>>>> with distance. It is 3.95750392900614E-02m/sec2 (small g) at the
>>>> distance of Mercury and diminishes by a factor of 1000 with every
>>>> assumed increase of distance of 10m and a corresponding decrease of
>>>> orbital velocity by 10m (gsunatpl = vm^2/rm).
>>>>
>>>> When is it zero?
>>>>
>>>>            rm                          vm                gsunatpl
>>>> 5.79092310294605E+10    4.78723311866901E+04    3.95750392900614E-02
>>>> 5.79092310294605E+11    4.78723311866901E+03    3.95750392900614E-05
>>>> 5.79092310294605E+12    4.78723311866901E+02    3.95750392900614E-08
>>>> 5.79092310294605E+13    4.78723311866901E+01    3.95750392900614E-11
>>>> 5.79092310294605E+14    4.78723311866901E+00    3.95750392900614E-14
>>>> 5.79092310294605E+15    4.78723311866901E-01    3.95750392900614E-17
>>>> 5.79092310294605E+16    4.78723311866901E-02    3.95750392900614E-20
>>>> 5.79092310294605E+17    4.78723311866901E-03    3.95750392900614E-23
>>>> 5.79092310294605E+18    4.78723311866901E-04    3.95750392900614E-26
>>>> 5.79092310294605E+19    4.78723311866901E-05    3.95750392900614E-29
>>>> 5.79092310294605E+20    4.78723311866901E-06    3.95750392900614E-32
>>>> 5.79092310294605E+21    4.78723311866901E-07    3.95750392900614E-35
>>>>
>>>
>>> When the planet is at the centre of the sun.
>>>
>>> Sylvia.
>>
>> Incorrect. Gravity is at maximum at the centre of the sun. At the
>> distance of the surface of the planet from the centre it is less but
>> not zero.
>>
>
> I encountered a physics student who made that claim.
>
> It should be obvious that it cannot possibly be true - what would the
> direction of the force be?
>
> Sylvia.

I must have plonked Peter Riedt since I don't see his postings.
Now I understand why! :-)

-- 
Paul

https://paulba.no/

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#389650

FromPeter Riedt <riedt1@yahoo.co.uk>
Date2016-08-09 19:11 -0700
Message-ID<5303ee24-d263-481f-b3f2-9af980f80602@googlegroups.com>
In reply to#389616
On Wednesday, August 10, 2016 at 4:57:47 AM UTC+8, Paul B. Andersen wrote:

> I must have plonked Peter Riedt since I don't see his postings.
> Now I understand why! :-)
> 
> -- 
> Paul
> 
Why are you into plonk? A man of your talents should be into physics and gravity.

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#389637

FromPeter Riedt <riedt1@yahoo.co.uk>
Date2016-08-09 17:20 -0700
Message-ID<a7835ffa-dc52-4354-8a11-8feb8cb11e3c@googlegroups.com>
In reply to#389558
On Tuesday, August 9, 2016 at 2:38:06 PM UTC+8, Sylvia Else wrote:
> On 9/08/2016 2:57 PM, Peter Riedt wrote:
> > On Monday, August 8, 2016 at 8:27:57 PM UTC+8, Sylvia Else wrote:
> >> On 8/08/2016 4:45 PM, Peter Riedt wrote:
> >>> Zero Gravity
> >>>
> >>> The gravitational force applied by the sun on each planet decreases with distance. It is 3.95750392900614E-02m/sec2 (small g) at the distance of Mercury and diminishes by a factor of 1000 with every assumed increase of distance of 10m and a corresponding decrease of orbital velocity by 10m (gsunatpl = vm^2/rm).
> >>>
> >>> When is it zero?
> >>>
> >>>            rm	                      vm	            gsunatpl
> >>> 5.79092310294605E+10	4.78723311866901E+04	3.95750392900614E-02
> >>> 5.79092310294605E+11	4.78723311866901E+03	3.95750392900614E-05
> >>> 5.79092310294605E+12	4.78723311866901E+02	3.95750392900614E-08
> >>> 5.79092310294605E+13	4.78723311866901E+01	3.95750392900614E-11
> >>> 5.79092310294605E+14	4.78723311866901E+00	3.95750392900614E-14
> >>> 5.79092310294605E+15	4.78723311866901E-01	3.95750392900614E-17
> >>> 5.79092310294605E+16	4.78723311866901E-02	3.95750392900614E-20
> >>> 5.79092310294605E+17	4.78723311866901E-03	3.95750392900614E-23
> >>> 5.79092310294605E+18	4.78723311866901E-04	3.95750392900614E-26
> >>> 5.79092310294605E+19	4.78723311866901E-05	3.95750392900614E-29
> >>> 5.79092310294605E+20	4.78723311866901E-06	3.95750392900614E-32
> >>> 5.79092310294605E+21	4.78723311866901E-07	3.95750392900614E-35
> >>>
> >>
> >> When the planet is at the centre of the sun.
> >>
> >> Sylvia.
> >
> > Incorrect. Gravity is at maximum at the centre of the sun. At the distance of the surface of the planet from the centre it is less but not zero.
> >
> 
> I encountered a physics student who made that claim.
> 
> It should be obvious that it cannot possibly be true - what would the 
> direction of the force be?
> 
> Sylvia.

Please tell me why you think gravity is zero in the centre of the sun?

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#389641

From"Dono," <sa_ge@comcast.net>
Date2016-08-09 17:59 -0700
Message-ID<07b88191-b449-4c81-aca3-059244670a88@googlegroups.com>
In reply to#389637
On Tuesday, August 9, 2016 at 5:20:49 PM UTC-7, Peter Riedt wrote:
> On Tuesday, August 9, 2016 at 2:38:06 PM UTC+8, Sylvia Else wrote:
> > On 9/08/2016 2:57 PM, Peter Riedt wrote:
> > > On Monday, August 8, 2016 at 8:27:57 PM UTC+8, Sylvia Else wrote:
> > >> On 8/08/2016 4:45 PM, Peter Riedt wrote:
> > >>> Zero Gravity
> > >>>
> > >>> The gravitational force applied by the sun on each planet decreases with distance. It is 3.95750392900614E-02m/sec2 (small g) at the distance of Mercury and diminishes by a factor of 1000 with every assumed increase of distance of 10m and a corresponding decrease of orbital velocity by 10m (gsunatpl = vm^2/rm).
> > >>>
> > >>> When is it zero?
> > >>>
> > >>>            rm	                      vm	            gsunatpl
> > >>> 5.79092310294605E+10	4.78723311866901E+04	3.95750392900614E-02
> > >>> 5.79092310294605E+11	4.78723311866901E+03	3.95750392900614E-05
> > >>> 5.79092310294605E+12	4.78723311866901E+02	3.95750392900614E-08
> > >>> 5.79092310294605E+13	4.78723311866901E+01	3.95750392900614E-11
> > >>> 5.79092310294605E+14	4.78723311866901E+00	3.95750392900614E-14
> > >>> 5.79092310294605E+15	4.78723311866901E-01	3.95750392900614E-17
> > >>> 5.79092310294605E+16	4.78723311866901E-02	3.95750392900614E-20
> > >>> 5.79092310294605E+17	4.78723311866901E-03	3.95750392900614E-23
> > >>> 5.79092310294605E+18	4.78723311866901E-04	3.95750392900614E-26
> > >>> 5.79092310294605E+19	4.78723311866901E-05	3.95750392900614E-29
> > >>> 5.79092310294605E+20	4.78723311866901E-06	3.95750392900614E-32
> > >>> 5.79092310294605E+21	4.78723311866901E-07	3.95750392900614E-35
> > >>>
> > >>
> > >> When the planet is at the centre of the sun.
> > >>
> > >> Sylvia.
> > >
> > > Incorrect. Gravity is at maximum at the centre of the sun. At the distance of the surface of the planet from the centre it is less but not zero.
> > >
> > 
> > I encountered a physics student who made that claim.
> > 
> > It should be obvious that it cannot possibly be true - what would the 
> > direction of the force be?
> > 
> > Sylvia.
> 
> Please tell me why you think gravity is zero in the centre of the sun?

Read. Gauss Theorem. Imbecile

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#389645

FromPeter Riedt <riedt1@yahoo.co.uk>
Date2016-08-09 18:42 -0700
Message-ID<96c0abf7-55f9-4e2c-9705-44d673d3eef5@googlegroups.com>
In reply to#389641
On Wednesday, August 10, 2016 at 8:59:30 AM UTC+8, Dono, wrote:
> 
> Read. Gauss Theorem. Imbecile

Does not apply.

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#389657

From"Dono," <sa_ge@comcast.net>
Date2016-08-09 20:10 -0700
Message-ID<13f37a48-028b-4788-b734-102490b93669@googlegroups.com>
In reply to#389645
On Tuesday, August 9, 2016 at 6:42:26 PM UTC-7, Peter Riedt wrote:
> On Wednesday, August 10, 2016 at 8:59:30 AM UTC+8, Dono, wrote:
> > 
> > Read. Gauss Theorem. Imbecile
> 
> Does not apply.

Cretin. Incurable.

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#389701

FromOdd Bodkin <bodkinodd@gmail.com>
Date2016-08-10 08:36 -0500
Message-ID<nofakp$1r87$5@gioia.aioe.org>
In reply to#389645
On 8/9/2016 8:42 PM, Peter Riedt wrote:
> On Wednesday, August 10, 2016 at 8:59:30 AM UTC+8, Dono, wrote:
>>
>> Read. Gauss Theorem. Imbecile
>
> Does not apply.
>

Yes, it does. It applies to ANY central force.

-- 
Odd Bodkin --- maker of fine toys, tools, tables

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#389658

FromSylvia Else <sylvia@not.at.this.address>
Date2016-08-10 13:12 +1000
Message-ID<e0vkdhFmb19U1@mid.individual.net>
In reply to#389637
On 10/08/2016 10:20 AM, Peter Riedt wrote:
> On Tuesday, August 9, 2016 at 2:38:06 PM UTC+8, Sylvia Else wrote:
>> On 9/08/2016 2:57 PM, Peter Riedt wrote:
>>> On Monday, August 8, 2016 at 8:27:57 PM UTC+8, Sylvia Else wrote:
>>>> On 8/08/2016 4:45 PM, Peter Riedt wrote:
>>>>> Zero Gravity
>>>>>
>>>>> The gravitational force applied by the sun on each planet decreases with distance. It is 3.95750392900614E-02m/sec2 (small g) at the distance of Mercury and diminishes by a factor of 1000 with every assumed increase of distance of 10m and a corresponding decrease of orbital velocity by 10m (gsunatpl = vm^2/rm).
>>>>>
>>>>> When is it zero?
>>>>>
>>>>>             rm	                      vm	            gsunatpl
>>>>> 5.79092310294605E+10	4.78723311866901E+04	3.95750392900614E-02
>>>>> 5.79092310294605E+11	4.78723311866901E+03	3.95750392900614E-05
>>>>> 5.79092310294605E+12	4.78723311866901E+02	3.95750392900614E-08
>>>>> 5.79092310294605E+13	4.78723311866901E+01	3.95750392900614E-11
>>>>> 5.79092310294605E+14	4.78723311866901E+00	3.95750392900614E-14
>>>>> 5.79092310294605E+15	4.78723311866901E-01	3.95750392900614E-17
>>>>> 5.79092310294605E+16	4.78723311866901E-02	3.95750392900614E-20
>>>>> 5.79092310294605E+17	4.78723311866901E-03	3.95750392900614E-23
>>>>> 5.79092310294605E+18	4.78723311866901E-04	3.95750392900614E-26
>>>>> 5.79092310294605E+19	4.78723311866901E-05	3.95750392900614E-29
>>>>> 5.79092310294605E+20	4.78723311866901E-06	3.95750392900614E-32
>>>>> 5.79092310294605E+21	4.78723311866901E-07	3.95750392900614E-35
>>>>>
>>>>
>>>> When the planet is at the centre of the sun.
>>>>
>>>> Sylvia.
>>>
>>> Incorrect. Gravity is at maximum at the centre of the sun. At the distance of the surface of the planet from the centre it is less but not zero.
>>>
>>
>> I encountered a physics student who made that claim.
>>
>> It should be obvious that it cannot possibly be true - what would the
>> direction of the force be?
>>
>> Sylvia.
>
> Please tell me why you think gravity is zero in the centre of the sun?
>

Consider yourself at the centre of the sun. Looking upwards (i.e. 
towards the surface) in some direction. You see a narrow cone of matter, 
which exerts a gravitational force on you. In the opposite direction is 
another cone, which exerts an equal and opposite gravitational force, so 
the combine force of the two cones is zero.

The same applies for every upwards direction, so the total force on you 
is zero.

Or use symmetry. Since the sun is symmetrical, the force must be, but 
any non-zero force would have a definite direction, and thus not be 
symmetrical. So the force must be zero.

Or do the math.

Sylvia.

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#389674

FromPeter Riedt <riedt1@yahoo.co.uk>
Date2016-08-10 00:56 -0700
Message-ID<a1ab47e8-49a6-4fd5-aa9a-61c5758d4cfc@googlegroups.com>
In reply to#389658
On Wednesday, August 10, 2016 at 11:12:53 AM UTC+8, Sylvia Else wrote:
> On 10/08/2016 10:20 AM, Peter Riedt wrote:
> > On Tuesday, August 9, 2016 at 2:38:06 PM UTC+8, Sylvia Else wrote:

Post 
Discard

> >> On 9/08/2016 2:57 PM, Peter Riedt wrote:
> >>> On Monday, August 8, 2016 at 8:27:57 PM UTC+8, Sylvia Else wrote:
> >>>> On 8/08/2016 4:45 PM, Peter Riedt wrote:
> >>>>> Zero Gravity
> >>>>>
> >>>>> The gravitational force applied by the sun on each planet decreases with distance. It is 3.95750392900614E-02m/sec2 (small g) at the distance of Mercury and diminishes by a factor of 1000 with every assumed increase of distance of 10m and a corresponding decrease of orbital velocity by 10m (gsunatpl = vm^2/rm).
> >>>>>
> >>>>> When is it zero?
> >>>>>
> >>>>>             rm	                      vm	            gsunatpl
> >>>>> 5.79092310294605E+10	4.78723311866901E+04	3.95750392900614E-02
> >>>>> 5.79092310294605E+11	4.78723311866901E+03	3.95750392900614E-05
> >>>>> 5.79092310294605E+12	4.78723311866901E+02	3.95750392900614E-08
> >>>>> 5.79092310294605E+13	4.78723311866901E+01	3.95750392900614E-11
> >>>>> 5.79092310294605E+14	4.78723311866901E+00	3.95750392900614E-14
> >>>>> 5.79092310294605E+15	4.78723311866901E-01	3.95750392900614E-17
> >>>>> 5.79092310294605E+16	4.78723311866901E-02	3.95750392900614E-20
> >>>>> 5.79092310294605E+17	4.78723311866901E-03	3.95750392900614E-23
> >>>>> 5.79092310294605E+18	4.78723311866901E-04	3.95750392900614E-26
> >>>>> 5.79092310294605E+19	4.78723311866901E-05	3.95750392900614E-29
> >>>>> 5.79092310294605E+20	4.78723311866901E-06	3.95750392900614E-32
> >>>>> 5.79092310294605E+21	4.78723311866901E-07	3.95750392900614E-35
> >>>>>
> >>>>
> >>>> When the planet is at the centre of the sun.
> >>>>
> >>>> Sylvia.
> >>>
> >>> Incorrect. Gravity is at maximum at the centre of the sun. At the distance of the surface of the planet from the centre it is less but not zero.
> >>>
> >>
> >> I encountered a physics student who made that claim.
> >>
> >> It should be obvious that it cannot possibly be true - what would the
> >> direction of the force be?
> >>
> >> Sylvia.
> >
> > Please tell me why you think gravity is zero in the centre of the sun?
> >
> 
> Consider yourself at the centre of the sun. Looking upwards (i.e. 
> towards the surface) in some direction. You see a narrow cone of matter, 
> which exerts a gravitational force on you. In the opposite direction is 
> another cone, which exerts an equal and opposite gravitational force, so 
> the combine force of the two cones is zero.
> 
> The same applies for every upwards direction, so the total force on you 
> is zero.
> 
> Or use symmetry. Since the sun is symmetrical, the force must be, but 
> any non-zero force would have a definite direction, and thus not be 
> symmetrical. So the force must be zero.
> 
> Or do the math.
> 
> Sylvia.

Drill a shaft through the sun which goes through the centre. The gravity from either end increases uniformly towards the centre. At the centre the small g gravity is at a maximum and in balance between the two halves. It doesn't reduce nor change to zero in any part of both halves. At the centre it cannot cause any motion, only on the way down. If a cannon ball is dropped into the shaft and it reaches the centre, the same effect occurs as if it were falling from a height of 100 m or any other to a solid surface: it comes to an immediate halt. It cannot overcome or penetrate the maximum gravity that is at the centre point of the antipodean's shaft.

Or do the math. Rsun=696000km, g=273msec2 at surface. You will find the answer to be GM.

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#389675

FromPeter Riedt <riedt1@yahoo.co.uk>
Date2016-08-10 01:02 -0700
Message-ID<5b8ea9a2-e7b2-462a-85d9-e87525f72984@googlegroups.com>
In reply to#389658
On Wednesday, August 10, 2016 at 11:12:53 AM UTC+8, Sylvia Else wrote:
> On 10/08/2016 10:20 AM, Peter Riedt wrote:
> > On Tuesday, August 9, 2016 at 2:38:06 PM UTC+8, Sylvia Else wrote:
> >> On 9/08/2016 2:57 PM, Peter Riedt wrote:
> >>> On Monday, August 8, 2016 at 8:27:57 PM UTC+8, Sylvia Else wrote:
> >>>> On 8/08/2016 4:45 PM, Peter Riedt wrote:
> >>>>> Zero Gravity
> >>>>>
> >>>>> The gravitational force applied by the sun on each planet decreases with distance. It is 3.95750392900614E-02m/sec2 (small g) at the distance of Mercury and diminishes by a factor of 1000 with every assumed increase of distance of 10m and a corresponding decrease of orbital velocity by 10m (gsunatpl = vm^2/rm).
> >>>>>
> >>>>> When is it zero?
> >>>>>
> >>>>>             rm	                      vm	            gsunatpl
> >>>>> 5.79092310294605E+10	4.78723311866901E+04	3.95750392900614E-02
> >>>>> 5.79092310294605E+11	4.78723311866901E+03	3.95750392900614E-05
> >>>>> 5.79092310294605E+12	4.78723311866901E+02	3.95750392900614E-08
> >>>>> 5.79092310294605E+13	4.78723311866901E+01	3.95750392900614E-11
> >>>>> 5.79092310294605E+14	4.78723311866901E+00	3.95750392900614E-14
> >>>>> 5.79092310294605E+15	4.78723311866901E-01	3.95750392900614E-17
> >>>>> 5.79092310294605E+16	4.78723311866901E-02	3.95750392900614E-20
> >>>>> 5.79092310294605E+17	4.78723311866901E-03	3.95750392900614E-23
> >>>>> 5.79092310294605E+18	4.78723311866901E-04	3.95750392900614E-26
> >>>>> 5.79092310294605E+19	4.78723311866901E-05	3.95750392900614E-29
> >>>>> 5.79092310294605E+20	4.78723311866901E-06	3.95750392900614E-32
> >>>>> 5.79092310294605E+21	4.78723311866901E-07	3.95750392900614E-35
> >>>>>
> >>>>
> >>>> When the planet is at the centre of the sun.
> >>>>
> >>>> Sylvia.
> >>>
> >>> Incorrect. Gravity is at maximum at the centre of the sun. At the distance of the surface of the planet from the centre it is less but not zero.
> >>>
> >>
> >> I encountered a physics student who made that claim.
> >>
> >> It should be obvious that it cannot possibly be true - what would the
> >> direction of the force be?
> >>
> >> Sylvia.
> >
> > Please tell me why you think gravity is zero in the centre of the sun?
> >
> 
> Consider yourself at the centre of the sun. Looking upwards (i.e. 
> towards the surface) in some direction. You see a narrow cone of matter, 
> which exerts a gravitational force on you. In the opposite direction is 
> another cone, which exerts an equal and opposite gravitational force, so 
> the combine force of the two cones is zero.
> 
> The same applies for every upwards direction, so the total force on you 
> is zero.
> 
> Or use symmetry. Since the sun is symmetrical, the force must be, but 
> any non-zero force would have a definite direction, and thus not be 
> symmetrical. So the force must be zero.
> 
> Or do the math.
> 
> Sylvia.

Drill a shaft through the sun which goes through the centre. The gravity from either end increases uniformly towards the centre. At the centre the small g gravity is at a maximum and in balance between the two halves. It doesn't reduce nor change to zero in any part of both halves. At the centre it cannot cause any motion, only on the way down. If a cannon ball is dropped into the shaft and it reaches the centre, the same effect occurs as if it were falling from a height of 100 m to a solid surface: it comes to an immediate halt. It cannot overcome or penetrate the maximum gravity that is at the centre point of the antipodean's shaft.

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#389678

FromMikko <mikko.levanto@outlook.com>
Date2016-08-10 11:35 +0300
Message-ID<mikko.levanto-99B843.11353510082016@88-209-239-213.giganet.hu>
In reply to#389675
In article <5b8ea9a2-e7b2-462a-85d9-e87525f72984@googlegroups.com>,
 Peter Riedt <riedt1@yahoo.co.uk> wrote:

> Drill a shaft through the sun which goes through the centre. The gravity from 
> either end increases uniformly towards the centre. At the centre the small g 
> gravity is at a maximum and in balance between the two halves. It doesn't 
> reduce nor change to zero in any part of both halves. At the centre it cannot 
> cause any motion, only on the way down. If a cannon ball is dropped into the 
> shaft and it reaches the centre, the same effect occurs as if it were falling 
> from a height of 100 m to a solid surface: it comes to an immediate halt. It 
> cannot overcome or penetrate the maximum gravity that is at the centre point 
> of the antipodean's shaft.

Why do you believe so? Why should anyone believe so? You offer no proof.

Mikko

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