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AP's thoughts as of 2JAN2019// big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

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  AP's thoughts as of 2JAN2019// big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics) Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2019-01-02 08:11 -0800
    Re: Archimedes "Village Idiot" Plutonium flunked the Math Test of a lifetime-generation test moroney@world.std.spaamtrap.com (Michael Moroney) - 2019-01-02 18:09 +0000
    Re: AP's thoughts as of 2JAN2019// big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics) Me <franz.fritschee.ff@gmail.com> - 2019-01-02 13:11 -0800
    skinny ellipses to see if formula is truly universal Re: big big  breakthrough in ellipse with a universal constant 1/137 (the fine structure  of physics) Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2019-01-02 14:28 -0800
      doubts about fetching the unique square Re: big big  breakthrough in ellipse with a universal constant 1/137 (the fine structure  of physics) Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2019-01-02 14:32 -0800
        long skinny ellipses Re: doubts about fetching the unique square Re: big big  breakthrough in ellipse with a universal constant 1/137 (the fine structure  of physics) Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2019-01-02 15:42 -0800
          Approx Square = Minor axis - (distance from focus to endpoint)  Re: big big  breakthrough in ellipse with a universal constant 1/137 (the fine structure  of physics) Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2019-01-02 18:16 -0800
            Re: Approx Square = Minor axis - (distance from focus to endpoint)  Re: big big  breakthrough in ellipse with a universal constant 1/137 (the fine structure  of physics) Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2019-01-02 20:58 -0800
              correct my mixup and is square 64% of ellipse maximum rectangle  Re: big big  breakthrough in ellipse with a universal constant 1/137 (the fine structure  of physics) Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2019-01-02 21:53 -0800
                Re: correct my mixup and is square 64% of ellipse maximum rectangle  Re: big big  breakthrough in ellipse with a universal constant 1/137 (the fine structure  of physics) Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2019-01-02 21:57 -0800
                  percentage table so far Re: big big  breakthrough in ellipse with a universal constant 1/137 (the fine structure  of physics) Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2019-01-02 23:16 -0800
                    Re: percentage table so far Re: big big  breakthrough in ellipse with a universal constant 1/137 (the fine structure  of physics) Me <franz.fritschee.ff@gmail.com> - 2019-01-03 04:53 -0800
                    percentages Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure  of physics) Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2019-01-03 14:05 -0800
                      Re: Archimedes "Village Idiot" Plutonium flunked the Math Test of a lifetime-generation test moroney@world.std.spaamtrap.com (Michael Moroney) - 2019-01-07 00:17 +0000

#430648 — AP's thoughts as of 2JAN2019// big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

Newsgroups: sci.math
Date: Wed, 2 Jan 2019 07:29:31 -0800 (PST)

Subject: Did I solve the ELLIPSE with 1/137 Re: why is not the maximum
 enclosed rectangle intersect with the foci ? Re: What 1/137 is the Planck
 constant for mathematics Re: Formula for foci
From: Archimedes Plutonium <plutonium....@gmail.com>
Injection-Date: Wed, 02 Jan 2019 15:29:32 +0000

Did I solve the ELLIPSE with 1/137 Re: why is not the maximum enclosed rectangle intersect with the foci ? Re: What 1/137 is the Planck constant for mathematics Re: Formula for foci

On Wednesday, January 2, 2019 at 12:45:41 AM UTC-6, Archimedes Plutonium wrote: 
> Alright i go to bed with a problem on my mind— why is the maximum enclosed rectangle inside a ellipse not intersect with two foci. For my intuition would have guessed the length of this rectangle is the length of the foci. And what is the formula for this discrepancy— does it involve a n*(1/137) 
> 


Alright, I may have a breakthrough here in my research of the Ellipse and where if any does the number 1/137 is a universal constant for the Ellipse. 

Alright, well yesterday I just learned that the focus formula is the Pythagorean theorem-- totally news to me-- in that the right triangle involved has a hypotenuse equal to the semimajor axis, and thus the focus is one of the legs of this right triangle. So the formula is F^2 = Semimajor^2 - Semiminor^2 

Now, here I need to ask a question-- how in the world did anyone prove or know that the right triangle hypotenuse was equal to the length of the semimajor axis? And was Ancient Greeks the ones to discover that ? 

Now, great progress with 1/137. 

In my specimen Ellipse of semimajor = 10, semiminor = 8 and thus foci is 10^2 - 8^2 = 100-64 = 36 = F^2  is F = 6 from center. 

Now, what is the Unique enclosed Square of this ellipse, and does it involve 1/137? So we have this ellipse plotted on a graph paper (at least I do) and looking at it and this ellipse has circumference of 56.72 and area of 251.32. Now taking .0072 of 56.72 I get .40 and divide by 2, I get .2 to that of 6 focus, making 6.2 and looking to see the distance perpendicular is 6.2 also. So this multiply the circumference by 1/137 yields the Unique Square in the given arbitrary ellipse. Now for the Maximum enclosed Rectangle of the given arbitrary Ellipse. I multiply the area, which in this case is 251.32 by the same constant .0072 and get 1.80. 

Now I add 1.80 to 6 and get the point 7.8 and look at what the perpendicular length is to the ellipse. I get a distance length of 5 which means I have a rectangle formed that is 15.6 by 10 or a area of 156 rectangle. Is that the Maximum Rectangle Enclosed? I think so, and would need the precision of Calculus to further support this data. 

So, in other words, if the above is all true, means that all ellipses, have a Universal Constant of .0072 = 1/137, the fine structure constant of physics, and this constant when multiplied by the circumference of ellipse gives the Unique Enclosed Square and when multiplied by the area of ellipse gives the Unique Maximum Enclosed Rectangle. 

So I need Calculus to confirm all this, for accuracy. And this is the way all mathematics should operate,-- all of it. We first do a hands on graphing and then roughly see what is what. Then, after we find out things about the graphing, only then do we turn to Calculus for greater accuracy. 

In our modern day math education, sadly, we eliminated the most important part of the math-work, for we do not plot on graph what we are doing and thus plunge directly into Calculus. This is like driving a car remotely in some building at a console while the car, like a drone is on the crowded expressway near a huge city. To properly drive a car, you need to be in the car, itself. 

Now, if the above is true, that 1/137 is a universal constant for all ellipses is of huge huge huge importance throughout all of mathematics, for it signals to us that mathematics is just a tiny tiny part of physics, and math is just a tiny tiny part of the physics of Electricity and Magnetism where the Fine Structure Constant comes from. 

AP 

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#430654 — Re: Archimedes "Village Idiot" Plutonium flunked the Math Test of a lifetime-generation test

Math Failure Archimedes Plutonium <plutonium.archimedes@gmail.com> fails:

>On Wednesday, January 2, 2019 at 9:31:38 AM UTC-6, Ser Gregor Clegane 
>(giganews) wrote:
>
>> Has anybody ever told you that sci.physics just isn't the place
>> for the incessant ravings of a lunatic?

>AP writes: maybe Clegane (giganews) describes Texas A&M as lunatic, but I 
>would never do so.

Archie, you failure, I already told you that you are not allowed to insult
your superiors like that. Do I have to tell the asylum to restrict your
internet access?

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#430656

On Wednesday, January 2, 2019 at 5:11:34 PM UTC+1, Archimedes Plutonium wrote:

> 1/137, the fine structure constant of physics

Actually, it's ~ 1/137.036

See: https://en.wikipedia.org/wiki/Fine-structure_constant#Measurement

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#430661 — skinny ellipses to see if formula is truly universal Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

Newsgroups: sci.physics
Date: Wed, 2 Jan 2019 14:22:47 -0800 (PST)

Subject: skinny ellipses to see if formula is truly universal Re: big big
 breakthrough in ellipse with a universal constant 1/137 (the fine structure
 of physics)
From: Archimedes Plutonium <plutonium....@gmail.com>
Injection-Date: Wed, 02 Jan 2019 22:22:48 +0000

skinny ellipses to see if formula is truly universal Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

Alright, let me do this on another ellipse, one that is long and skinny instead of short and fat. 

Let me try out an ellipse with (thanks for rechneronline.de for ellipse calculator) 
semimajor axis = 5 
semiminor axis = 2 
circumference 23.013 
area = 31.416 

Now the foci will be 5^2 - 2^2 = 25-4 = 21 = F^2 and focus is thus 4.58 from center 


Semimajor axis = 10 
Semiminor axis = 2 
circumference = 42.02 
area = 62.832 

Now the foci will be 10^2 - 2^2 = 100 - 4 = 96 = F^2 and focus will be 9.79 from center 

On Wednesday, January 2, 2019 at 10:16:30 AM UTC-6, Archimedes Plutonium wrote: 
> AP's thoughts as of 2JAN2019// big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics) 
> 
> Newsgroups: sci.math 
> Date: Wed, 2 Jan 2019 07:29:31 -0800 (PST) 
> 
> Subject: Did I solve the ELLIPSE with 1/137 Re: why is not the maximum 
>  enclosed rectangle intersect with the foci ? Re: What 1/137 is the Planck 
>  constant for mathematics Re: Formula for foci 
> From: Archimedes Plutonium <plutonium....@gmail.com> 
> Injection-Date: Wed, 02 Jan 2019 15:29:32 +0000 
> 
> Did I solve the ELLIPSE with 1/137 Re: why is not the maximum enclosed rectangle intersect with the foci ? Re: What 1/137 is the Planck constant for mathematics Re: Formula for foci 
> 
> On Wednesday, January 2, 2019 at 12:45:41 AM UTC-6, Archimedes Plutonium wrote: 
> > Alright i go to bed with a problem on my mind— why is the maximum enclosed rectangle inside a ellipse not intersect with two foci. For my intuition would have guessed the length of this rectangle is the length of the foci. And what is the formula for this discrepancy— does it involve a n*(1/137) 
> > 

Yes, I need to find out how it was assumed, or presumed or proven that the semimajor axis is automatically the hypotenuse to find the focus location. 


> 
> 
> Alright, I may have a breakthrough here in my research of the Ellipse and where if any does the number 1/137 is a universal constant for the Ellipse. 
> 
> Alright, well yesterday I just learned that the focus formula is the Pythagorean theorem-- totally news to me-- in that the right triangle involved has a hypotenuse equal to the semimajor axis, and thus the focus is one of the legs of this right triangle. So the formula is F^2 = Semimajor^2 - Semiminor^2 
> 
> Now, here I need to ask a question-- how in the world did anyone prove or know that the right triangle hypotenuse was equal to the length of the semimajor axis? And was Ancient Greeks the ones to discover that ? 
> 
> Now, great progress with 1/137. 
> 
> In my specimen Ellipse of semimajor = 10, semiminor = 8 and thus foci is 10^2 - 8^2 = 100-64 = 36 = F^2  is F = 6 from center. 
> 
> Now, what is the Unique enclosed Square of this ellipse, and does it involve 1/137? So we have this ellipse plotted on a graph paper (at least I do) and looking at it and this ellipse has circumference of 56.72 and area of 251.32. Now taking .0072 of 56.72 I get .40 and divide by 2, I get .2 to that of 6 focus, making 6.2 and looking to see the distance perpendicular is 6.2 also. So this multiply the circumference by 1/137 yields the Unique Square in the given arbitrary ellipse. Now for the Maximum enclosed Rectangle of the given arbitrary Ellipse. I multiply the area, which in this case is 251.32 by the same constant .0072 and get 1.80. 
> 
> Now I add 1.80 to 6 and get the point 7.8 and look at what the perpendicular length is to the ellipse. I get a distance length of 5 which means I have a rectangle formed that is 15.6 by 10 or a area of 156 rectangle. Is that the Maximum Rectangle Enclosed? I think so, and would need the precision of Calculus to further support this data. 
> 
> So, in other words, if the above is all true, means that all ellipses, have a Universal Constant of .0072 = 1/137, the fine structure constant of physics, and this constant when multiplied by the circumference of ellipse gives the Unique Enclosed Square and when multiplied by the area of ellipse gives the Unique Maximum Enclosed Rectangle. 
> 
> So I need Calculus to confirm all this, for accuracy. And this is the way all mathematics should operate,-- all of it. We first do a hands on graphing and then roughly see what is what. Then, after we find out things about the graphing, only then do we turn to Calculus for greater accuracy. 
> 
> In our modern day math education, sadly, we eliminated the most important part of the math-work, for we do not plot on graph what we are doing and thus plunge directly into Calculus. This is like driving a car remotely in some building at a console while the car, like a drone is on the crowded expressway near a huge city. To properly drive a car, you need to be in the car, itself. 
> 
> Now, if the above is true, that 1/137 is a universal constant for all ellipses is of huge huge huge importance throughout all of mathematics, for it signals to us that mathematics is just a tiny tiny part of physics, and math is just a tiny tiny part of the physics of Electricity and Magnetism where the Fine Structure Constant comes from. 
> 

So, let me go through the same procedure and see if I can get the Unique Square and unique maximum Rectangle on these skinny ellipses. 

AP 

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#430663 — doubts about fetching the unique square Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

On Wednesday, January 2, 2019 at 4:28:58 PM UTC-6, Archimedes Plutonium wrote:
(snipped)
> Alright, let me do this on another ellipse, one that is long and skinny instead of short and fat. 
> 
> Let me try out an ellipse with (thanks for rechneronline.de for ellipse calculator) 
> semimajor axis = 5 
> semiminor axis = 2 
> circumference 23.013 
> area = 31.416 
> 
> Now the foci will be 5^2 - 2^2 = 25-4 = 21 = F^2 and focus is thus 4.58 from center 
> 
> 
> Semimajor axis = 10 
> Semiminor axis = 2 
> circumference = 42.02 
> area = 62.832 
> 
> Now the foci will be 10^2 - 2^2 = 100 - 4 = 96 = F^2 and focus will be 9.79 from center 

Now, to tell you, right out of the starting block I have no hope that the techniqe will deliver the unique square inside the ellipse, but every confidence that it will deliver the maximum rectangle.

That is just my suspicion, so maybe I can tinker around to find that unique square, for it is nowhere close to where the foci are located.

AP

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#430664 — long skinny ellipses Re: doubts about fetching the unique square Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

On Wednesday, January 2, 2019 at 4:32:48 PM UTC-6, Archimedes Plutonium wrote:
> On Wednesday, January 2, 2019 at 4:28:58 PM UTC-6, Archimedes Plutonium wrote:
> (snipped)
> > Alright, let me do this on another ellipse, one that is long and skinny instead of short and fat. 
> > 
> > Let me try out an ellipse with (thanks for rechneronline.de for ellipse calculator) 
> > semimajor axis = 5 
> > semiminor axis = 2 
> > circumference 23.013 
> > area = 31.416 
> > 
> > Now the foci will be 5^2 - 2^2 = 25-4 = 21 = F^2 and focus is thus 4.58 from center 
> > 

Alright, so the focus is near the endpoint of 5 on the ellipse, for it is 4.58 then nearby is 5, with space of only 5- 4.58 = .42 space.

So we multiply the area 31.416 by .0072 is .22 so is the maximum rectangle with length of 4.58+.22

I do not know if this is the maximum rectangle and have to draw a graph.

As for the Unique Square I multiply the circumference by .0072 which is 23.013 * .0072 = .165

Obviously there is no square near 4.58



> > 
> > Semimajor axis = 10 
> > Semiminor axis = 2 
> > circumference = 42.02 
> > area = 62.832 
> > 
> > Now the foci will be 10^2 - 2^2 = 100 - 4 = 96 = F^2 and focus will be 9.79 from center 
> 
> Now, to tell you, right out of the starting block I have no hope that the techniqe will deliver the unique square inside the ellipse, but every confidence that it will deliver the maximum rectangle.
> 
> That is just my suspicion, so maybe I can tinker around to find that unique square, for it is nowhere close to where the foci are located.
> 
> AP

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#430666 — Approx Square = Minor axis - (distance from focus to endpoint) Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

On Wednesday, January 2, 2019 at 5:42:15 PM UTC-6, Archimedes Plutonium wrote:
> On Wednesday, January 2, 2019 at 4:32:48 PM UTC-6, Archimedes Plutonium wrote:
> > On Wednesday, January 2, 2019 at 4:28:58 PM UTC-6, Archimedes Plutonium wrote:
> > (snipped)
> > > Alright, let me do this on another ellipse, one that is long and skinny instead of short and fat. 
> > > 
> > > Let me try out an ellipse with (thanks for rechneronline.de for ellipse calculator) 
> > > semimajor axis = 5 
> > > semiminor axis = 2 
> > > circumference 23.013 
> > > area = 31.416 
> > > 
> > > Now the foci will be 5^2 - 2^2 = 25-4 = 21 = F^2 and focus is thus 4.58 from center 
> > > 
> 
> Alright, so the focus is near the endpoint of 5 on the ellipse, for it is 4.58 then nearby is 5, with space of only 5- 4.58 = .42 space.
> 
> So we multiply the area 31.416 by .0072 is .22 so is the maximum rectangle with length of 4.58+.22
> 
> I do not know if this is the maximum rectangle and have to draw a graph.
> 
> As for the Unique Square I multiply the circumference by .0072 which is 23.013 * .0072 = .165
> 
> Obviously there is no square near 4.58
> 

Alright, now in my 10by8ellipse it was not obvious the square would be around 12by12 give or take.

So I need a way of spotting where the unique square sort of occurs. So in the 5by2ellipse we immediately recognize 4 as an upper bound on the square. It cannot be a 4by4 square. So it has to be less than 4. In the same manner we recognize in the 10by8ellipse, it cannot be a 16by16 square but less. Is there someway of paring down where we can say the square lies approximately? In the 10by8ellipse the distance from endpoint of semimajor axis with focus is 10-6= 4. The distance of minor axis is 16, so that 16-4 = 12, around 12 is the square. Let me try that on the 5by2ellipse. The focal point is 4.58 leaving .42 distance from endpoint. The minor axis is 4 and thus 4-.42 = 3.58. Is the square approx 3.58by3.58 with only a 1/137 adjustment?

So if true I have this as formula of Approx Square = Minor axis - (distance from focus to endpoint)

Then what I am hoping for, is that the Approx Square + or - a 1/137 adjustment is equal to Unique Square.

AP

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#430670 — Re: Approx Square = Minor axis - (distance from focus to endpoint) Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

Newsgroups: sci.physics
Date: Wed, 2 Jan 2019 18:34:53 -0800 (PST)

Subject: amazing number in math 1/137 Re: big big breakthrough in ellipse with
 a universal constant 1/137 (the fine structure of physics)
From: Archimedes Plutonium <plutonium....@gmail.com>
Injection-Date: Thu, 03 Jan 2019 02:54:54 +0000

amazing number in math 1/137 Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

Now, if this is all true, the only really incredible thing about this whole story, is that a number-- seemingly coming from out of nowhere, 1/137 governs where the key features of a ellipse lie. And if true, that number 1/137 is the Fine Structure Constant of Physics, with its Angular Momentum that is defined as being-- sweeping out equal areas in equal time intervals. That is the definition not only of Angular Momentum but also of the ellipse. 

AP

Newsgroups: sci.physics
Date: Wed, 2 Jan 2019 19:56:36 -0800 (PST)

Subject: in the 5by2ellipse is the unique square 3.56by3.56 or is it
 3.78by3.78 ? Re: big big breakthrough in ellipse with a universal constant
 1/137 (the fine structure of physics)
From: Archimedes Plutonium <plutonium....@gmail.com>
Injection-Date: Thu, 03 Jan 2019 04:16:38 +0000

in the 5by2ellipse is the unique square 3.56by3.56 or is it 3.78by3.78 ? Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

On Wednesday, January 2, 2019 at 8:54:58 PM UTC-6, Archimedes Plutonium wrote: 
> Now, if this is all true, the only really incredible thing about this whole story, is that a number-- seemingly coming from out of nowhere, 1/137 governs where the key features of a ellipse lie. And if true, that number 1/137 is the Fine Structure Constant of Physics, with its Angular Momentum that is defined as being-- sweeping out equal areas in equal time intervals. That is the definition not only of Angular Momentum but also of the ellipse. 
> 

You see, this is a huge farce of modern day math education. Classrooms filled with students with only book and paper and pencil, feverishly calculating away. When they should be having graph paper, pencil and various instruments. And only once they done some graph work do they then go to Calculus to make accuracy better. But the greatest sin of all math classrooms is to see students taking notes. Why take notes when the textbook should have all that in the textbook, and the teacher should be teaching not, repeating the text. So pitiful is modern day College math, that you would be hard pressed to tell if the classroom was a history class, and there you really do need to take notes, but not a math class. What i want to see in all math classes is graph paper, instantly ready to be put in use. 

So I graphed the 5by2ellipse and checked out the 4by4square where we need to subtract a increment to find the unique square in 5by2. Its area is 31.416 and multiply that by .0072 is .22. Now, if I subtract .22 from the four corners of 4by4 I end up with 4-.44 = 3.56 and looking at my graph paper of this ellipse that is too much but 4-.22 = 3.78 looks just fine. 

AP 

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#430671 — correct my mixup and is square 64% of ellipse maximum rectangle Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

On Wednesday, January 2, 2019 at 10:58:38 PM UTC-6, Archimedes Plutonium wrote:
> Newsgroups: sci.physics
> Date: Wed, 2 Jan 2019 18:34:53 -0800 (PST)
> 
> Subject: amazing number in math 1/137 Re: big big breakthrough in ellipse with
>  a universal constant 1/137 (the fine structure of physics)
> From: Archimedes Plutonium <plutonium....@gmail.com>
> Injection-Date: Thu, 03 Jan 2019 02:54:54 +0000
> 
> amazing number in math 1/137 Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)
> 
> Now, if this is all true, the only really incredible thing about this whole story, is that a number-- seemingly coming from out of nowhere, 1/137 governs where the key features of a ellipse lie. And if true, that number 1/137 is the Fine Structure Constant of Physics, with its Angular Momentum that is defined as being-- sweeping out equal areas in equal time intervals. That is the definition not only of Angular Momentum but also of the ellipse. 
> 
> AP
> 
> Newsgroups: sci.physics
> Date: Wed, 2 Jan 2019 19:56:36 -0800 (PST)
> 
> Subject: in the 5by2ellipse is the unique square 3.56by3.56 or is it
>  3.78by3.78 ? Re: big big breakthrough in ellipse with a universal constant
>  1/137 (the fine structure of physics)
> From: Archimedes Plutonium <plutonium....@gmail.com>
> Injection-Date: Thu, 03 Jan 2019 04:16:38 +0000
> 
> in the 5by2ellipse is the unique square 3.56by3.56 or is it 3.78by3.78 ? Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)
> 
> On Wednesday, January 2, 2019 at 8:54:58 PM UTC-6, Archimedes Plutonium wrote: 
> > Now, if this is all true, the only really incredible thing about this whole story, is that a number-- seemingly coming from out of nowhere, 1/137 governs where the key features of a ellipse lie. And if true, that number 1/137 is the Fine Structure Constant of Physics, with its Angular Momentum that is defined as being-- sweeping out equal areas in equal time intervals. That is the definition not only of Angular Momentum but also of the ellipse. 
> > 
> 
> You see, this is a huge farce of modern day math education. Classrooms filled with students with only book and paper and pencil, feverishly calculating away. When they should be having graph paper, pencil and various instruments. And only once they done some graph work do they then go to Calculus to make accuracy better. But the greatest sin of all math classrooms is to see students taking notes. Why take notes when the textbook should have all that in the textbook, and the teacher should be teaching not, repeating the text. So pitiful is modern day College math, that you would be hard pressed to tell if the classroom was a history class, and there you really do need to take notes, but not a math class. What i want to see in all math classes is graph paper, instantly ready to be put in use. 
> 
> So I graphed the 5by2ellipse and checked out the 4by4square where we need to subtract a increment to find the unique square in 5by2. Its area is 31.416 and multiply that by .0072 is .22. Now, if I subtract .22 from the four corners of 4by4 I end up with 4-.44 = 3.56 and looking at my graph paper of this ellipse that is too much but 4-.22 = 3.78 looks just fine. 
> 

Apparently I am confusing my numbers. I should use .0072*23.013 for the square determination and use .0072*31.416 for the rectangle determination

For my 5by2ellipse the Maximum Rectangle according to graphing is a 8by2.6= 20.8. And with .0072*31.416 = .22 then subtract from 4.58 does not give me the 8 I need, however if we double the .22 to .44 we get 8.1*2.6 = 21.06.

So, that is close enough that one suspects 1/137 is involved.

As for the square, I need to use .0072* 23.013 = .165 and doubling that is .33 so if I nip off the corners of 4by4square to be 4-.33= 3.67 of a square that is 3.67 by 3.67.

Now recently I did a formula for the Torus using percentages because Old Math was totally wrong in thinking a cylinder that is bent can provide the torus volume and area. Totally wrong.

So here I wonder if the ellipse square is related to the ellipse maximum rectangle in a universal percentage.

So that we have 3.67^2 = 13.46 and maximum rectangle at 21.06 we have a percentage of 13.46/21.06 = 64%. Is the percentage of all ellipse squares 64% of their maximum rectangle?

AP

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#430672 — Re: correct my mixup and is square 64% of ellipse maximum rectangle Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

Newsgroups: sci.physics
Date: Wed, 2 Jan 2019 18:34:53 -0800 (PST)

Subject: amazing number in math 1/137 Re: big big breakthrough in ellipse with
 a universal constant 1/137 (the fine structure of physics)
From: Archimedes Plutonium <plutonium....@gmail.com>
Injection-Date: Thu, 03 Jan 2019 02:54:54 +0000

amazing number in math 1/137 Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

Now, if this is all true, the only really incredible thing about this whole story, is that a number-- seemingly coming from out of nowhere, 1/137 governs where the key features of a ellipse lie. And if true, that number 1/137 is the Fine Structure Constant of Physics, with its Angular Momentum that is defined as being-- sweeping out equal areas in equal time intervals. That is the definition not only of Angular Momentum but also of the ellipse. 

AP

Newsgroups: sci.physics
Date: Wed, 2 Jan 2019 19:56:36 -0800 (PST)

Subject: in the 5by2ellipse is the unique square 3.56by3.56 or is it
 3.78by3.78 ? Re: big big breakthrough in ellipse with a universal constant
 1/137 (the fine structure of physics)
From: Archimedes Plutonium <plutonium....@gmail.com>
Injection-Date: Thu, 03 Jan 2019 04:16:38 +0000

in the 5by2ellipse is the unique square 3.56by3.56 or is it 3.78by3.78 ? Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

On Wednesday, January 2, 2019 at 8:54:58 PM UTC-6, Archimedes Plutonium wrote: 
> Now, if this is all true, the only really incredible thing about this whole story, is that a number-- seemingly coming from out of nowhere, 1/137 governs where the key features of a ellipse lie. And if true, that number 1/137 is the Fine Structure Constant of Physics, with its Angular Momentum that is defined as being-- sweeping out equal areas in equal time intervals. That is the definition not only of Angular Momentum but also of the ellipse. 
> 

You see, this is a huge farce of modern day math education. Classrooms filled with students with only book and paper and pencil, feverishly calculating away. When they should be having graph paper, pencil and various instruments. And only once they done some graph work do they then go to Calculus to make accuracy better. But the greatest sin of all math classrooms is to see students taking notes. Why take notes when the textbook should have all that in the textbook, and the teacher should be teaching not, repeating the text. So pitiful is modern day College math, that you would be hard pressed to tell if the classroom was a history class, and there you really do need to take notes, but not a math class. What i want to see in all math classes is graph paper, instantly ready to be put in use. 

So I graphed the 5by2ellipse and checked out the 4by4square where we need to subtract a increment to find the unique square in 5by2. Its area is 31.416 and multiply that by .0072 is .22. Now, if I subtract .22 from the four corners of 4by4 I end up with 4-.44 = 3.56 and looking at my graph paper of this ellipse that is too much but 4-.22 = 3.78 looks just fine. 

AP 

Newsgroups: sci.math
Date: Wed, 2 Jan 2019 21:53:39 -0800 (PST)

Subject: correct my mixup and is square 64% of ellipse maximum rectangle  Re:
 big big  breakthrough in ellipse with a universal constant 1/137 (the fine
 structure  of physics)
From: Archimedes Plutonium <plutonium....@gmail.com>
Injection-Date: Thu, 03 Jan 2019 05:53:40 +0000

correct my mixup and is square 64% of ellipse maximum rectangle Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

- show quoted text -
Apparently I am confusing my numbers. I should use .0072*23.013 for the square determination and use .0072*31.416 for the rectangle determination 

For my 5by2ellipse the Maximum Rectangle according to graphing is a 8by2.6= 20.8. And with .0072*31.416 = .22 then subtract from 4.58 does not give me the 8 I need, however if we double the .22 to .44 we get 8.1*2.6 = 21.06. 

So, that is close enough that one suspects 1/137 is involved. 

As for the square, I need to use .0072* 23.013 = .165 and doubling that is .33 so if I nip off the corners of 4by4square to be 4-.33= 3.67 of a square that is 3.67 by 3.67. 

Now recently I did a formula for the Torus using percentages because Old Math was totally wrong in thinking a cylinder that is bent can provide the torus volume and area. Totally wrong. 

So here I wonder if the ellipse square is related to the ellipse maximum rectangle in a universal percentage. 

So that we have 3.67^2 = 13.46 and maximum rectangle at 21.06 we have a percentage of 13.46/21.06 = 64%. Is the percentage of all ellipse squares 64% of their maximum rectangle? 

AP 

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#430687 — percentage table so far Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

Alright so far I have data on just two ellipses, and wanting to start percentage formula. Mind you the case of 1/137 is not yet resolved as to whether it is a universal constant of ellipses. But rather than just sit around I move on to percentages, the percentage of the unique square inside the ellipse and the maximum rectangle inside the ellipse.

The 10by8ellipse

Semimajor axis = 10 
Semiminor axis = 8 
Foci distance from center = 6 using formula F^2 = semimajor axis^2 - semiminor axis^2
Circumference = 56.7 
Area = 251.3
Interior Square 12.2by12.2   from .0072*56.7 = .40; area = 148.8, perimeter = 48.8
Interior Maximum Rectangle 15.6by10  from .0072*251.3 = 1.80; area = 156, perimeter = 51.2
Exterior Rectangle 20by16 area=320, perimeter = 72

So some percentages so far would be ellipse area to exterior rectangle 251.3/320 = 78%
ellipse area to interior rectangle 156/251.3 = 62%
ellipse perimeter to exterior rectangle perimeter 56.7/72 = 78% nice match
ellipse perimeter to interior rectangle 51.2/56.7 = 90%
interior rectangle area to exterior rectangle area 156/320 = 48%
interior rectangle perimeter to exterior rectangle perimeter 51.2/72 = 71%
square area to interior rectangle area 148.8/156 = 95%
square perimeter to interior rectangle perimeter 48.8/51.2 = 95% nice match

AP

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#430698 — Re: percentage table so far Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

On Thursday, January 3, 2019 at 8:16:09 AM UTC+1, Archimedes Plutonium wrote:

> Alright so far I have data on just two ellipses [...]. Mind you the case of
> 1/137 is not yet resolved as to whether it is a universal constant of 
> ellipses. [...]

You might try the 10by10ellipse too!

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#430747 — percentages Re: big big breakthrough in ellipse with a universal constant 1/137 (the fine structure of physics)

On Thursday, January 3, 2019 at 1:16:09 AM UTC-6, Archimedes Plutonium wrote:
> Alright so far I have data on just two ellipses, and wanting to start percentage formula. Mind you the case of 1/137 is not yet resolved as to whether it is a universal constant of ellipses. But rather than just sit around I move on to percentages, the percentage of the unique square inside the ellipse and the maximum rectangle inside the ellipse.
> 
> The 10by8ellipse
> 
> Semimajor axis = 10 
> Semiminor axis = 8 
> Foci distance from center = 6 using formula F^2 = semimajor axis^2 - semiminor axis^2
> Circumference = 56.7 
> Area = 251.3
> Interior Square 12.2by12.2   from .0072*56.7 = .40; area = 148.8, perimeter = 48.8
> Interior Maximum Rectangle 15.6by10  from .0072*251.3 = 1.80; area = 156, perimeter = 51.2
> Exterior Rectangle 20by16 area=320, perimeter = 72
> 
> So some percentages so far would be ellipse area to exterior rectangle 251.3/320 = 78%
> ellipse area to interior rectangle 156/251.3 = 62%
> ellipse perimeter to exterior rectangle perimeter 56.7/72 = 78% nice match
> ellipse perimeter to interior rectangle 51.2/56.7 = 90%
> interior rectangle area to exterior rectangle area 156/320 = 48%
> interior rectangle perimeter to exterior rectangle perimeter 51.2/72 = 71%
> square area to interior rectangle area 148.8/156 = 95%
> square perimeter to interior rectangle perimeter 48.8/51.2 = 95% nice match
> 

The 5by2ellipse 

Semimajor axis = 5 
Semiminor axis = 2
Foci distance from center = 4.58 using formula F^2 = semimajor axis^2 - semiminor axis^2 
Circumference = 23.013
Area = 31.416
Interior Square 3.67by3.67 from .0072*23.013 = .165; area = 13.46, perimeter = 14.68 
Interior Maximum Rectangle 8.1by2.6  from .0072*31.416 = .22; area = 21.06, perimeter = 21.4 
Exterior Rectangle 10by4 area=40, perimeter = 28 

So some percentages so far would be ellipse area to exterior rectangle 31.41/40 = 78% 
ellipse area to interior rectangle 21.06/31.4 = 66% 
ellipse perimeter to exterior rectangle perimeter 23/28 = 82%
ellipse perimeter to interior rectangle 21.4/23 = 93% 
interior rectangle area to exterior rectangle area 21.06/40 = 52% 
interior rectangle perimeter to exterior rectangle perimeter 21.4/28 = 76% 
square area to interior rectangle area 13.46/21.06 = 63% 
square perimeter to interior rectangle perimeter 14.68/21.4 = 68%

AP

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#430967 — Re: Archimedes "Village Idiot" Plutonium flunked the Math Test of a lifetime-generation test

Math Failure Archimedes Plutonium <plutonium.archimedes@gmail.com> fails:

On Sunday, January 6, 2019 at 12:28:12 AM UTC-6, Michael Moroney wrote:
> Math Failure

No, no, no. I already told you you have to quote properly. It is supposed to be:
>>Math Failure Archimedes Plutonium <plutonium.archimedes@gmail.com> fails:

And again I see you are still too dumb and stoopid to not attack me.

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