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Groups > linux.kernel > #1382866 > unrolled thread
| Started by | Davidlohr Bueso <dave@stgolabs.net> |
|---|---|
| First post | 2016-04-20 00:30 +0200 |
| Last post | 2016-04-20 09:40 +0200 |
| Articles | 3 — 3 participants |
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Re: [PATCH] kernel/futex: handle the case where we got a "late" waiter Davidlohr Bueso <dave@stgolabs.net> - 2016-04-20 00:30 +0200
Re: [PATCH] kernel/futex: handle the case where we got a "late" waiter Sebastian Andrzej Siewior <bigeasy@linutronix.de> - 2016-04-20 09:10 +0200
Re: [PATCH] kernel/futex: handle the case where we got a "late" waiter Thomas Gleixner <tglx@linutronix.de> - 2016-04-20 09:40 +0200
| From | Davidlohr Bueso <dave@stgolabs.net> |
|---|---|
| Date | 2016-04-20 00:30 +0200 |
| Subject | Re: [PATCH] kernel/futex: handle the case where we got a "late" waiter |
| Message-ID | <rpMjE-5XD-1@gated-at.bofh.it> |
On Fri, 15 Apr 2016, Sebastian Andrzej Siewior wrote: >futex_unlock_pi() gets uval before taking the hb lock. Now imagine >someone in futex_lock_pi() took the lock. While futex_unlock_pi() waits >for the hb lock, the LOCK_PI sets FUTEX_WAITERS and drops the lock. >Now, futex_unlock_pi() figures out that there is waiter and invokes >wake_futex_pi() with the old uval which does not yet have FUTEX_WAITERS >set. This flaw lets cmpxchg_futex_value_locked() fail and return -EINVAL. Hmm but if we're calling futex_unlock_pi() in the first place, doesn't that indicate that the uval already has FUTEX_WAITERS and therefore failed the TID->0 transition in userland? That or the thread is bogusly unlocking a lock that it doesn't own. This is of course different than the requeue_pi case which can specify set_waiters but also gets the value via get_futex_value_locked(). Is this a real issue or did you find it by code inspection? Thanks, Davidlohr
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| From | Sebastian Andrzej Siewior <bigeasy@linutronix.de> |
|---|---|
| Date | 2016-04-20 09:10 +0200 |
| Message-ID | <rpUqR-3QU-1@gated-at.bofh.it> |
| In reply to | #1382866 |
On 04/20/2016 12:27 AM, Davidlohr Bueso wrote: > On Fri, 15 Apr 2016, Sebastian Andrzej Siewior wrote: > >> futex_unlock_pi() gets uval before taking the hb lock. Now imagine >> someone in futex_lock_pi() took the lock. While futex_unlock_pi() waits >> for the hb lock, the LOCK_PI sets FUTEX_WAITERS and drops the lock. >> Now, futex_unlock_pi() figures out that there is waiter and invokes >> wake_futex_pi() with the old uval which does not yet have FUTEX_WAITERS >> set. This flaw lets cmpxchg_futex_value_locked() fail and return -EINVAL. > > Hmm but if we're calling futex_unlock_pi() in the first place, doesn't that > indicate that the uval already has FUTEX_WAITERS and therefore failed the > TID->0 transition in userland? That or the thread is bogusly unlocking a > lock that it doesn't own. I hacked a testing tool which always did the syscall for LOCK_PI / UNLOCK_PI and this popped up. > > This is of course different than the requeue_pi case which can specify > set_waiters but also gets the value via get_futex_value_locked(). > > Is this a real issue or did you find it by code inspection? real issue. https://breakpoint.cc/mass-futex2-rl.c > Thanks, > Davidlohr Sebastian
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| From | Thomas Gleixner <tglx@linutronix.de> |
|---|---|
| Date | 2016-04-20 09:40 +0200 |
| Message-ID | <rpUTT-43d-5@gated-at.bofh.it> |
| In reply to | #1382866 |
On Tue, 19 Apr 2016, Davidlohr Bueso wrote: > On Fri, 15 Apr 2016, Sebastian Andrzej Siewior wrote: > > > futex_unlock_pi() gets uval before taking the hb lock. Now imagine > > someone in futex_lock_pi() took the lock. While futex_unlock_pi() waits > > for the hb lock, the LOCK_PI sets FUTEX_WAITERS and drops the lock. > > Now, futex_unlock_pi() figures out that there is waiter and invokes > > wake_futex_pi() with the old uval which does not yet have FUTEX_WAITERS > > set. This flaw lets cmpxchg_futex_value_locked() fail and return -EINVAL. > > Hmm but if we're calling futex_unlock_pi() in the first place, doesn't that > indicate that the uval already has FUTEX_WAITERS and therefore failed the > TID->0 transition in userland? That or the thread is bogusly unlocking a > lock that it doesn't own. It can be called unconditionally w/o trying the TID->0 transition in user space first and we should handle that case. Thanks, tglx
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