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Re: querries

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It is probably because powers, x^y are multivalued. You can use 
expr//PowerExpand to short circuit these concerns. Be aware, however 
that the following does not give an answer

Sqrt[b^2]==b

but

Sqrt[b^2]==b//PowerExpand

Gives True, which means that the concerns about plus/minus are forgotten.

Kevin


On 6/9/2011 5:45 AM, Savits, Thomas H wrote:
> 1)       Why does Mathematica not give the value 0 to the expression
> (mu*lambda)^(b) - (mu^b)*(lambda^b)? It seems to treat the expression (mu*lambda) as a new variable. I used the greek letters from the palette in the actual expression.
>
> 2)       Many times I cannot get Mathematica to simplify expressions involving the exponential functions, e.g., it won't combine the arguments of the Exp functions. Is there a way to force this?
>
> Thanks,
> Tom Savits
> Statistics Department
> University of Pittsburgh

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querries "Savits, Thomas H" <savits@pitt.edu> - 2011-06-09 09:45 +0000
  Re: querries "Kevin J. McCann" <Kevin.McCann@umbc.edu> - 2011-06-10 10:40 +0000
  Re: querries "Dr. Wolfgang Hintze" <weh@snafu.de> - 2011-06-10 10:37 +0000

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