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| From | Willem <willem@toad.stack.nl> |
| Newsgroups | comp.programming |
| Subject | Re: Incrementing IPv6 address |
| Date | Wed, 30 Nov 2011 13:44:16 +0000 (UTC) |
| Organization | Stack Usenet News Service |
| Lines | 26 |
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Tester Tester wrote:
) hello every body.
) I am working in address incrementation(+1) using c language.User
) inputs a value which is in hex address and incremented by 1.
) Suppose my address is - abc5:5723:2109:ffff:76af:82ea:9256:ffff.
) So my output becomes - abc5:5723:2109:ffff:76af:82ea:9257:0000
)
) I already parse the entire string and put it in 8 different array but
) unable to do when the the last 4 digit reaches FFFF..I could not write
) the logic of that last portion.can any body help me to solve the
) problem?
Can you describe, in plain old English, what's supposed to happen when
a set of digits that is 0xffff is increased ?
So basically, when it's not 0xffff, it's increased by 1, and when
it *is* 0xffff, then what should happen ?
SaSW, Willem
--
Disclaimer: I am in no way responsible for any of the statements
made in the above text. For all I know I might be
drugged or something..
No I'm not paranoid. You all think I'm paranoid, don't you !
#EOT
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Incrementing IPv6 address Tester Tester <codectest99@gmail.com> - 2011-11-30 05:11 -0800 Re: Incrementing IPv6 address Willem <willem@toad.stack.nl> - 2011-11-30 13:44 +0000 Re: Incrementing IPv6 address Ben Bacarisse <ben.usenet@bsb.me.uk> - 2011-11-30 16:51 +0000
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