Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]

Groups > comp.programming > #1063 > unrolled thread

Incrementing IPv6 address

Back to article view | Back to comp.programming

Contents

  Incrementing IPv6 address Tester Tester <codectest99@gmail.com> - 2011-11-30 05:11 -0800
    Re: Incrementing IPv6 address Willem <willem@toad.stack.nl> - 2011-11-30 13:44 +0000
    Re: Incrementing IPv6 address Ben Bacarisse <ben.usenet@bsb.me.uk> - 2011-11-30 16:51 +0000

#1063 — Incrementing IPv6 address

hello every body.
I am working in address incrementation(+1) using c language.User
inputs a value which is in hex address and incremented by 1.
Suppose my address is - abc5:5723:2109:ffff:76af:82ea:9256:ffff.
So my output becomes - abc5:5723:2109:ffff:76af:82ea:9257:0000

I already parse the entire string and put it in 8 different array but
unable to do when the the last 4 digit reaches FFFF..I could not write
the logic of that last portion.can any body help me to solve the
problem?

My code is -

#include "stdafx.h"
#include "conio.h"
#include "stdio.h"
#include "string.h"


int _tmain(int argc, _TCHAR* argv[])
{
    char address[] = "abc5:5723:2109:ffff:76af:82ea:9256:ffff";
    printf("Your IPv6 address is ");
    puts(address);
    char a[10], b[10], c[10], d[10], e[10], f[10], g[10], h[10];
    if(sscanf(address, "%10[^:]:%10[^:]:%10[^:]:%10[^:]:%10[^:]:
%10[^:]:%10[^:]:%10[^:]:",a,b,c,d,e,f,g,h)==8)
    {
        //puts(a);
        //puts(b);
    }
int m,n,o,p,q,r,s,t;
 sscanf(a,"%x", &m);
 sscanf(b,"%x", &n);
 sscanf(c,"%x", &o);
 sscanf(d,"%x", &p);
 sscanf(e,"%x", &q);
 sscanf(f,"%x", &r);
 sscanf(g,"%x", &s);
 sscanf(h,"%x", &t);

t++;


printf("The final output is %x:%x:%x:%x:%x:%x:%x:%x",m,n,o,p,q,r,s,t);


   getch();
   return 0;

}

Output -

You IPv6 address is abc5:5723:2109:ffff:76af:82ea:9256:ffff
The final output is abc5:5723:2109:ffff:76af:82ea:9256:10000

Waiting for your reply.

Ayanava

[toc] | [next] | [standalone]

#1064

Tester Tester wrote:
) hello every body.
) I am working in address incrementation(+1) using c language.User
) inputs a value which is in hex address and incremented by 1.
) Suppose my address is - abc5:5723:2109:ffff:76af:82ea:9256:ffff.
) So my output becomes - abc5:5723:2109:ffff:76af:82ea:9257:0000
)
) I already parse the entire string and put it in 8 different array but
) unable to do when the the last 4 digit reaches FFFF..I could not write
) the logic of that last portion.can any body help me to solve the
) problem?

Can you describe, in plain old English, what's supposed to happen when
a set of digits that is 0xffff is increased ?

So basically, when it's not 0xffff, it's increased by 1, and when
it *is* 0xffff, then what should happen ?


SaSW, Willem
-- 
Disclaimer: I am in no way responsible for any of the statements
            made in the above text. For all I know I might be
            drugged or something..
            No I'm not paranoid. You all think I'm paranoid, don't you !
#EOT

[toc] | [prev] | [next] | [standalone]

#1065

Tester Tester <codectest99@gmail.com> writes:

> I am working in address incrementation(+1) using c language.User
> inputs a value which is in hex address and incremented by 1.

You multi-posted.  This is rarely a good idea. When a post is relevant
to more that one group (and you wish to post to them all) then cross
posting is the preferred method.  To see why, imagine someone here
spending time answering you with all the same points I made in
comp.lang.c simply because they don't happen to read both groups.

<snip>
-- 
Ben.

[toc] | [prev] | [standalone]

Back to top | Article view | comp.programming

csiph-web