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Groups > comp.lang.python > #80567
| From | Rob Gaddi <rgaddi@technologyhighland.invalid> |
|---|---|
| Newsgroups | comp.lang.python |
| Subject | Re: Combining lists to dictionary |
| Date | 2014-11-11 13:42 -0800 |
| Organization | Highland Technology, Inc. |
| Message-ID | <20141111134230.4a597eb6@rg.highlandtechnology.com> (permalink) |
| References | <m3tscl$f1e$2@dont-email.me> |
On Tue, 11 Nov 2014 20:43:01 +0000 (UTC)
Denis McMahon <denismfmcmahon@gmail.com> wrote:
> Hi
>
> Given x,y are a lists of keys and value that I wish to combine to a
> dictionary, such that x[n] is the key for value y[n], which is preferred:
>
> z = {a:b for (a,b) in zip(x,y)}
> z = {x[n]:y[n] for n in range(min(len(x),len(y)))}
>
> The zip feels more elegant, but it seems clunky to use the zip method to
> create a list of tuples just to split them up into key:value pairs.
> However the zip method handles the inequal length list problem. Granted
> it would probably be advisable to check that x and y are the same length
> before starting anyway.
>
> --
> Denis McMahon, denismfmcmahon@gmail.com
To add to what Gary said, the explicit dict() init knows how to handle
an iterable that emits pairs of data. So you can simplify further down to:
z = dict(zip(x, y))
If you're running Python2, and really that concerned about the extra
memory used by zip returning a list rather than an iterator, you can
use itertools.izip
--
Rob Gaddi, Highland Technology -- www.highlandtechnology.com
Email address domain is currently out of order. See above to fix.
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Combining lists to dictionary Denis McMahon <denismfmcmahon@gmail.com> - 2014-11-11 20:43 +0000 Re: Combining lists to dictionary Gary Herron <gherron@digipen.edu> - 2014-11-11 12:55 -0800 Re: Combining lists to dictionary Rob Gaddi <rgaddi@technologyhighland.invalid> - 2014-11-11 13:42 -0800 Re: Combining lists to dictionary Roy Smith <roy@panix.com> - 2014-11-11 20:06 -0500 Re: Combining lists to dictionary Ben Finney <ben+python@benfinney.id.au> - 2014-11-12 12:16 +1100 Re: Combining lists to dictionary Dave Angel <davea@davea.name> - 2014-11-12 01:13 -0500
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