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What does x.y.z mean?

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  What  does x.y.z mean? bit-naughty@hotmail.com - 2014-06-25 10:33 -0700
    Re: What  does x.y.z mean? Gregor Kofler <usenet@gregorkofler.com> - 2014-06-25 21:41 +0200
      Re: What  does x.y.z mean? Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2014-06-26 11:09 +0200
      Re: What  does x.y.z mean? bit-naughty@hotmail.com - 2014-06-26 06:25 -0700
        Re: What  does x.y.z mean? John Harris <niam@jghnorth.org.uk.invalid> - 2014-06-26 14:47 +0100
          Re: What  does x.y.z mean? John Harris <niam@jghnorth.org.uk.invalid> - 2014-06-27 09:52 +0100
    Re: What  does x.y.z mean? Denis McMahon <denismfmcmahon@gmail.com> - 2014-06-27 09:46 +0000

#25023 — What does x.y.z mean?

I always had this figured out:

x is an object, of which y is a method that returns an object itself, and z is a property or method of *that* object - am I right in this?


Also, what happens in the case of an object literal? Is y an object inside x, and z an object inside y? Or am I completely mistaken?

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#25025

Am 2014-06-25 19:33, bit-naughty@hotmail.com meinte:
> I always had this figured out:

Copying the question into the message body is smart?

> x is an object, of which y is a method that returns an object itself, and z is a property or method of *that* object - am I right in this?

No. This would be x.y().z
>
>
> Also, what happens in the case of an object literal?

What should "happen"?

> Is y an object inside x, and z an object inside y? Or am I completely mistaken?

y and z are properties, which values in turn can be objects. In the 
above example y is assumed to hold an object.

Gregor

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#25039

Gregor Kofler wrote:

> Am 2014-06-25 19:33, bit-naughty@hotmail.com meinte:
>> [x.y.z]
>> Is y an object inside x, and z an object inside y? Or am I completely
>> mistaken?
> 
> y and z are properties, which values in turn can be objects. In the
> above example y is assumed to hold an object.

The values are *references to* objects instead.  You are probably aware
of that; however, it is important to emphasize because it means that 
*different* properties and variables can refer to the *same* object, and 
that objects do not *contain* other objects in these languages.  IOW, 
“objects have identity, not name”.

Why are you reading and replying to postings from trollishly anonymous 
Google Groupers?

-- 
PointedEars
FAQ: <http://PointedEars.de/faq> | SVN: <http://PointedEars.de/wsvn/>
Twitter: @PointedEars2 | ES Matrix: <http://PointedEars.de/es-matrix>
Please do not Cc: me. / Bitte keine Kopien per E-Mail.

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#25042

On Thursday, June 26, 2014 1:11:07 AM UTC+5:30, Gregor Kofler wrote:
> y and z are properties, which values in turn can be objects. In the 
> 
> above example y is assumed to hold an object.
> 

Right, so what does "y.z" mean then?

And that brings me back to my original question - what is x.y.z?

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#25044

On Thu, 26 Jun 2014 06:25:50 -0700 (PDT), bit-naughty@hotmail.com
wrote:

>On Thursday, June 26, 2014 1:11:07 AM UTC+5:30, Gregor Kofler wrote:
>> y and z are properties, which values in turn can be objects. In the 
>> 
>> above example y is assumed to hold an object.
>> 
>
>Right, so what does "y.z" mean then?
>
>And that brings me back to my original question - what is x.y.z?

  x.y.z 
means exactly the same as
  x["y"]["z"]
by definition.

  John

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#25095

On Thu, 26 Jun 2014 14:47:04 +0100, John Harris
<niam@jghnorth.org.uk.invalid> wrote:

>On Thu, 26 Jun 2014 06:25:50 -0700 (PDT), bit-naughty@hotmail.com
>wrote:
>
>>On Thursday, June 26, 2014 1:11:07 AM UTC+5:30, Gregor Kofler wrote:
>>> y and z are properties, which values in turn can be objects. In the 
>>> 
>>> above example y is assumed to hold an object.
>>> 
>>
>>Right, so what does "y.z" mean then?
>>
>>And that brings me back to my original question - what is x.y.z?
>
>  x.y.z 
>means exactly the same as
>  x["y"]["z"]
>by definition.

If that doesn't help, then work it out this way :

  var a = x.y;
  var b = a.z;

The second line will go BANG! if a is not [aka is not a reference to]
an object.

  John

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#25096

On Wed, 25 Jun 2014 10:33:09 -0700, bit-naughty wrote:

> I always had this figured out:
> 
> x is an object, of which y is a method that returns an object itself,
> and z is a property or method of *that* object - am I right in this?
> 
> Also, what happens in the case of an object literal? Is y an object
> inside x, and z an object inside y? Or am I completely mistaken?

Stuff like this is so difficult to test for yourself isn't it.

<!doctype html>
<html lang="en">
  <head>
    <meta http-equiv="Content-Type" content="text/html; charset=utf-8">
    <title>x.y.z</title>
    <script type="application/javascript">
      function gebi(x) { return document.getElementById(x); }
      var x = JSON.parse('{"y":{"z":"zed"}}');
      function stuff() {
        gebi("tofx").value = typeof( x );
        gebi("tofxy").value = typeof( x.y );
        gebi("tofxyz").value = typeof( x.y.z );
        gebi("strx").value = x.toString();
        gebi("strxy").value = x.y.toString();
        gebi("strxyz").value = x.y.z.toString();
      }
    </script>
  </head>
  <body onload="stuff();">
    <pre>
      var x = JSON.parse('{"y":{"z":"value"}}');
    </pre>
    <p>
      typeof x = <input id="tofx"><br>
      typeof x.y = <input id="tofxy"><br>
      typeof x.y.z = <input id="tofxyz"><br>
      x.toString() = <input id="strx"><br>
      x.y.toString() = <input id="strxy"><br>
      x.y.z.toString() = <input id="strxyz"><br>
    </p>
  </body>
</html>

-- 
Denis McMahon, denismfmcmahon@gmail.com

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