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Groups > comp.lang.c++ > #13884 > unrolled thread
| Started by | "V.Subramanian, India" <subramanian100in@yahoo.com> |
|---|---|
| First post | 2012-02-10 05:44 -0800 |
| Last post | 2012-02-10 17:51 +0000 |
| Articles | 4 — 4 participants |
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taking address of temporary object "V.Subramanian, India" <subramanian100in@yahoo.com> - 2012-02-10 05:44 -0800
Re: taking address of temporary object Victor Bazarov <v.bazarov@comcast.invalid> - 2012-02-10 08:53 -0500
Re: taking address of temporary object "Alf P. Steinbach" <alf.p.steinbach+usenet@gmail.com> - 2012-02-10 15:08 +0100
Re: taking address of temporary object Gareth Owen <gwowen@gmail.com> - 2012-02-10 17:51 +0000
| From | "V.Subramanian, India" <subramanian100in@yahoo.com> |
|---|---|
| Date | 2012-02-10 05:44 -0800 |
| Subject | taking address of temporary object |
| Message-ID | <93e89895-796d-48bb-abd6-3f560410b006@tj4g2000pbc.googlegroups.com> |
The following post is for learning purpose only.
I am using g++ 3.4.3
Consider the following program x.cpp
#include <cstdlib>
#include <iostream>
#include <ostream>
using namespace std;
class Test {
public:
explicit Test(int arg = 0);
Test& operator+=(const Test& rhs);
int value() const;
private:
int x;
};
inline Test::Test(int arg) : x(arg)
{
}
inline Test& Test::operator+=(const Test& rhs)
{
x += rhs.value();
return *this;
}
inline int Test::value() const
{
return x;
}
inline const Test operator+(const Test& lhs,
const Test& rhs)
{
Test temp(lhs);
return temp += rhs;
}
int main()
{
Test x(100);
Test y(200);
const Test* p = &(x + y);
int a = 10;
int b = 20;
const int* i = &(a + b);
return EXIT_SUCCESS;
}
When I compile this program x.cpp as
g++ -std=c++98 -pedantic -Wall -Wextra x.cpp
I get the following warning and error.
x.cpp: In function `int main()':
x.cpp:42: warning: taking address of temporary
x.cpp:46: error: non-lvalue in unary `&'
x.cpp:42: warning: unused variable 'p'
x.cpp:46: warning: unused variable 'i'
Question:
In the above code, why does the compiler give warning for
taking the address of temporary-class-object namely
(x + y) whereas it generates error for taking the address of
temporary-built-in-object namely (a + b) ? I expected error
message for taking &(x + y) similar to that of &(a + b).
Is ithis behaviour specific to g++3.4.3 ? Or the standard
itself requires so ?
Please explain.
Thanks
V.Subramanian
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| From | Victor Bazarov <v.bazarov@comcast.invalid> |
|---|---|
| Date | 2012-02-10 08:53 -0500 |
| Message-ID | <jh37hl$tip$1@dont-email.me> |
| In reply to | #13884 |
On 2/10/2012 8:44 AM, V.Subramanian, India wrote:
> The following post is for learning purpose only.
> I am using g++ 3.4.3
> Consider the following program x.cpp
>
> #include<cstdlib>
> #include<iostream>
> #include<ostream>
>
> using namespace std;
>
> class Test {
> public:
> explicit Test(int arg = 0);
> Test& operator+=(const Test& rhs);
> int value() const;
> private:
> int x;
> };
>
> inline Test::Test(int arg) : x(arg)
> {
> }
>
> inline Test& Test::operator+=(const Test& rhs)
> {
> x += rhs.value();
> return *this;
> }
>
> inline int Test::value() const
> {
> return x;
> }
>
> inline const Test operator+(const Test& lhs,
> const Test& rhs)
> {
> Test temp(lhs);
> return temp += rhs;
> }
>
> int main()
> {
> Test x(100);
> Test y(200);
> const Test* p =&(x + y);
>
> int a = 10;
> int b = 20;
> const int* i =&(a + b);
>
> return EXIT_SUCCESS;
> }
>
> When I compile this program x.cpp as
> g++ -std=c++98 -pedantic -Wall -Wextra x.cpp
> I get the following warning and error.
>
> x.cpp: In function `int main()':
> x.cpp:42: warning: taking address of temporary
> x.cpp:46: error: non-lvalue in unary `&'
> x.cpp:42: warning: unused variable 'p'
> x.cpp:46: warning: unused variable 'i'
>
> Question:
> In the above code, why does the compiler give warning for
> taking the address of temporary-class-object namely
> (x + y) whereas it generates error for taking the address of
> temporary-built-in-object namely (a + b) ? I expected error
> message for taking&(x + y) similar to that of&(a + b).
>
> Is ithis behaviour specific to g++3.4.3 ? Or the standard
> itself requires so ?
>
> Please explain.
I think the answer lies in the fact that a temporary object of a class
type (especially one that has a c-tor) usually resides in memory anyway
(and the compiler knows that), so taking its address is not a totally
impossible operation, whereas a temporary of a built-in type can easily
reside in the CPU register which does not have an address.
A class object that has any non-static member functions must have the
unique "this" pointer when the control is inside that function, which
means that even a temporary has to reside in memory.
V
--
I do not respond to top-posted replies, please don't ask
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| From | "Alf P. Steinbach" <alf.p.steinbach+usenet@gmail.com> |
|---|---|
| Date | 2012-02-10 15:08 +0100 |
| Message-ID | <jh38ck$2uj$1@dont-email.me> |
| In reply to | #13884 |
On 10.02.2012 14:44, V.Subramanian, India wrote:
> The following post is for learning purpose only.
> I am using g++ 3.4.3
> Consider the following program x.cpp
>
> #include<cstdlib>
> #include<iostream>
> #include<ostream>
>
> using namespace std;
>
> class Test {
> public:
> explicit Test(int arg = 0);
> Test& operator+=(const Test& rhs);
> int value() const;
> private:
> int x;
> };
>
> inline Test::Test(int arg) : x(arg)
> {
> }
>
> inline Test& Test::operator+=(const Test& rhs)
> {
> x += rhs.value();
> return *this;
> }
>
> inline int Test::value() const
> {
> return x;
> }
>
> inline const Test operator+(const Test& lhs,
> const Test& rhs)
> {
> Test temp(lhs);
> return temp += rhs;
> }
>
> int main()
> {
> Test x(100);
> Test y(200);
> const Test* p =&(x + y);
>
> int a = 10;
> int b = 20;
> const int* i =&(a + b);
>
> return EXIT_SUCCESS;
> }
Please convert tabs to spaces before posting.
> When I compile this program x.cpp as
> g++ -std=c++98 -pedantic -Wall -Wextra x.cpp
> I get the following warning and error.
>
> x.cpp: In function `int main()':
> x.cpp:42: warning: taking address of temporary
> x.cpp:46: error: non-lvalue in unary `&'
> x.cpp:42: warning: unused variable 'p'
> x.cpp:46: warning: unused variable 'i'
Hm, it should not compile at all. Lemme test.
<test>
[d:\dev\test]
> g++ -std=c++98 -pedantic -Wall -Wextra foo.cpp
foo.cpp: In function 'int main()':
foo.cpp:42:25: error: taking address of temporary [-fpermissive]
foo.cpp:46:24: error: lvalue required as unary '&' operand
foo.cpp:42:14: warning: unused variable 'p' [-Wunused-variable]
foo.cpp:46:13: warning: unused variable 'i' [-Wunused-variable]
[d:\dev\test]
> _
</test>
Solution: upgrade to more recent version of the compiler.
>
> Question:
> In the above code, why does the compiler give warning for
> taking the address of temporary-class-object namely
> (x + y) whereas it generates error for taking the address of
> temporary-built-in-object namely (a + b) ? I expected error
> message for taking&(x + y) similar to that of&(a + b).
I think it must be a very old version of g++ you're using.
The Holy Standard does not permit using the built-in address operator to
take the address of a temporary.
> Is ithis behaviour specific to g++3.4.3 ? Or the standard
> itself requires so ?
Specific.
Cheers & hth.,
- Alf
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| From | Gareth Owen <gwowen@gmail.com> |
|---|---|
| Date | 2012-02-10 17:51 +0000 |
| Message-ID | <87zkcqtw41.fsf@gmail.com> |
| In reply to | #13886 |
"Alf P. Steinbach" <alf.p.steinbach+usenet@gmail.com> writes: > The Holy Standard does not permit using the built-in address operator > to take the address of a temporary. Presumably you can call an over-ridden unary & operator? (which isn't to say that to do so isn't a horrible design decision)
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