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Re: taking address of temporary object

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On 10.02.2012 14:44, V.Subramanian, India wrote:
> The following post is for learning purpose only.
> I am using g++ 3.4.3
> Consider the following program x.cpp
>
> #include<cstdlib>
> #include<iostream>
> #include<ostream>
>
> using namespace std;
>
> class Test {
> public:
> 	explicit Test(int arg = 0);
> 	Test&  operator+=(const Test&  rhs);
> 	int value() const;
> private:
> 	int x;
> };
>
> inline Test::Test(int arg) : x(arg)
> {
> }
>
> inline Test&  Test::operator+=(const Test&  rhs)
> {
> 	x += rhs.value();
> 	return *this;
> }
>
> inline int Test::value() const
> {
> 	return x;
> }
>
> inline const Test operator+(const Test&  lhs,
>                                          const Test&  rhs)
> {
> 	Test temp(lhs);
> 	return temp += rhs;
> }
>
> int main()
> {
> 	Test x(100);
> 	Test y(200);
> 	const Test* p =&(x + y);
>
> 	int a = 10;
> 	int b = 20;
> 	const int* i =&(a + b);
>
> 	return EXIT_SUCCESS;
> }

Please convert tabs to spaces before posting.


> When I compile this program x.cpp as
> g++ -std=c++98 -pedantic -Wall -Wextra x.cpp
> I get the following warning and error.
>
> x.cpp: In function `int main()':
> x.cpp:42: warning: taking address of temporary
> x.cpp:46: error: non-lvalue in unary `&'
> x.cpp:42: warning: unused variable 'p'
> x.cpp:46: warning: unused variable 'i'

Hm, it should not compile at all. Lemme test.

<test>
[d:\dev\test]
 > g++ -std=c++98 -pedantic -Wall -Wextra foo.cpp
foo.cpp: In function 'int main()':
foo.cpp:42:25: error: taking address of temporary [-fpermissive]
foo.cpp:46:24: error: lvalue required as unary '&' operand
foo.cpp:42:14: warning: unused variable 'p' [-Wunused-variable]
foo.cpp:46:13: warning: unused variable 'i' [-Wunused-variable]

[d:\dev\test]
 > _
</test>

Solution: upgrade to more recent version of the compiler.


>
> Question:
> In the above code, why does the compiler give warning for
> taking the address of temporary-class-object namely
> (x + y) whereas it generates error for taking the address of
> temporary-built-in-object namely (a + b) ? I expected error
> message for taking&(x + y) similar to that of&(a + b).

I think it must be a very old version of g++ you're using.

The Holy Standard does not permit using the built-in address operator to 
take the address of a temporary.


> Is ithis behaviour specific to g++3.4.3 ? Or the standard
> itself requires so ?

Specific.


Cheers & hth.,

- Alf

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Thread

taking address of temporary object "V.Subramanian, India" <subramanian100in@yahoo.com> - 2012-02-10 05:44 -0800
  Re: taking address of temporary object Victor Bazarov <v.bazarov@comcast.invalid> - 2012-02-10 08:53 -0500
  Re: taking address of temporary object "Alf P. Steinbach" <alf.p.steinbach+usenet@gmail.com> - 2012-02-10 15:08 +0100
    Re: taking address of temporary object Gareth Owen <gwowen@gmail.com> - 2012-02-10 17:51 +0000

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