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Re: sizeof()

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From Keith Thompson <Keith.S.Thompson+u@gmail.com>
Newsgroups comp.lang.c++
Subject Re: sizeof()
Date Mon, 19 Dec 2022 10:02:57 -0800
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"gdo...@gmail.com" <gdotone@gmail.com> writes:
> should be consider a function not an operator?
[...]

No, sizeof is an operator.  A function cannot take a type as an
argument, nor can it fail to evaluate its argument(s).

The sizeof operator seems odd because its symbol is a keyword rather
than a punctuation symbol.

-- 
Keith Thompson (The_Other_Keith) Keith.S.Thompson+u@gmail.com
Working, but not speaking, for XCOM Labs
void Void(void) { Void(); } /* The recursive call of the void */

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sizeof() "gdo...@gmail.com" <gdotone@gmail.com> - 2022-12-19 09:12 -0800
  Re: sizeof() Keith Thompson <Keith.S.Thompson+u@gmail.com> - 2022-12-19 10:02 -0800
  Re: sizeof() Juha Nieminen <nospam@thanks.invalid> - 2022-12-19 18:13 +0000
  Re: sizeof() Tony Oliver <guinness.tony@gmail.com> - 2022-12-19 16:35 -0800
  Re: sizeof() Öö Tiib <ootiib@hot.ee> - 2022-12-20 01:36 -0800

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