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Groups > comp.lang.c++ > #88065
| From | Keith Thompson <Keith.S.Thompson+u@gmail.com> |
|---|---|
| Newsgroups | comp.lang.c++ |
| Subject | Re: sizeof() |
| Date | 2022-12-19 10:02 -0800 |
| Organization | None to speak of |
| Message-ID | <87mt7js23y.fsf@nosuchdomain.example.com> (permalink) |
| References | <fef9de52-9919-4d1d-9b5f-aa67f6c40c03n@googlegroups.com> |
"gdo...@gmail.com" <gdotone@gmail.com> writes:
> should be consider a function not an operator?
[...]
No, sizeof is an operator. A function cannot take a type as an
argument, nor can it fail to evaluate its argument(s).
The sizeof operator seems odd because its symbol is a keyword rather
than a punctuation symbol.
--
Keith Thompson (The_Other_Keith) Keith.S.Thompson+u@gmail.com
Working, but not speaking, for XCOM Labs
void Void(void) { Void(); } /* The recursive call of the void */
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sizeof() "gdo...@gmail.com" <gdotone@gmail.com> - 2022-12-19 09:12 -0800 Re: sizeof() Keith Thompson <Keith.S.Thompson+u@gmail.com> - 2022-12-19 10:02 -0800 Re: sizeof() Juha Nieminen <nospam@thanks.invalid> - 2022-12-19 18:13 +0000 Re: sizeof() Tony Oliver <guinness.tony@gmail.com> - 2022-12-19 16:35 -0800 Re: sizeof() Öö Tiib <ootiib@hot.ee> - 2022-12-20 01:36 -0800
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