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| From | Hans-Peter Diettrich <DrDiettrich1@netscape.net> |
| Newsgroups | comp.compilers |
| Subject | Re: Preprocessing ## |
| Date | Mon, 15 May 2017 11:28:46 +0200 |
| Organization | Compilers Central |
| Lines | 30 |
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| Keywords | C |
| Posted-Date | 15 May 2017 10:46:40 EDT |
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Am 13.05.2017 um 08:49 schrieb Hans-Peter Diettrich:
> How is the C preprocessor assumed to handle the ## concatenation operator?
>
> In the Windows headers I found macros like
> #define foo(x) bar(##baz(x))
> where an expansion into ... (baz ... doesn't make sense, because "(baz"
> is not a valid preprocessor token. Can somebody explain the meaning and
> handling of such constructs?
[John]
> [I would guess that some macro between ( and ## expanded to
> nothing.
The #define's leave no room for macros to the left of ##.
If, in above example, bar() were another macro, would the ## operator
stay literal part of the argument's token sequence?
E.g. with
#define bar(z) some_prefix z
would foo(suffix) expand into
some_prefix ##baz(suffix)
?
> Or it could just be one of those text editing errors. -John]
Not here. A comment before a couple of such #define's suggests, that
they are a workaround for the lack of variadic macros ("..." arguments).
DoDi
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Preprocessing ## Hans-Peter Diettrich <DrDiettrich1@netscape.net> - 2017-05-13 08:49 +0200
Re: Preprocessing ## Hans-Peter Diettrich <DrDiettrich1@netscape.net> - 2017-05-15 11:28 +0200
Re: Preprocessing ## Kaz Kylheku <686-678-9105@kylheku.com> - 2017-05-15 13:41 +0000
Re: Preprocessing ## George Neuner <gneuner2@comcast.net> - 2017-05-15 11:31 -0400
Re: Preprocessing ## Hans-Peter Diettrich <DrDiettrich1@aol.com.dmarc.email> - 2017-06-02 08:04 +0200
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