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Groups > comp.compilers > #1870
| From | Hans-Peter Diettrich <DrDiettrich1@netscape.net> |
|---|---|
| Newsgroups | comp.compilers |
| Subject | Preprocessing ## |
| Date | 2017-05-13 08:49 +0200 |
| Organization | Compilers Central |
| Message-ID | <17-05-003@comp.compilers> (permalink) |
How is the C preprocessor assumed to handle the ## concatenation operator? In the Windows headers I found macros like #define foo(x) bar(##baz(x)) where an expansion into ... (baz ... doesn't make sense, because "(baz" is not a valid preprocessor token. Can somebody explain the meaning and handling of such constructs? DoDi [I would guess that some macro between ( and ## expanded to nothing. Or it could just be one of those text editing errors. -John]
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Preprocessing ## Hans-Peter Diettrich <DrDiettrich1@netscape.net> - 2017-05-13 08:49 +0200
Re: Preprocessing ## Hans-Peter Diettrich <DrDiettrich1@netscape.net> - 2017-05-15 11:28 +0200
Re: Preprocessing ## Kaz Kylheku <686-678-9105@kylheku.com> - 2017-05-15 13:41 +0000
Re: Preprocessing ## George Neuner <gneuner2@comcast.net> - 2017-05-15 11:31 -0400
Re: Preprocessing ## Hans-Peter Diettrich <DrDiettrich1@aol.com.dmarc.email> - 2017-06-02 08:04 +0200
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