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| From | Chris Elvidge <celvidge001@gmail.com> |
| Newsgroups | gnu.bash.bug |
| Subject | Return from function depending on number of parameters |
| Date | Fri, 3 Jul 2020 19:00:54 +0100 |
| Lines | 25 |
| Approved | bug-bash@gnu.org |
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I've used 'return $((!$#))' and 'return $[!$#]' to return an error if no parameters given to function. Tested in a bash script 'exit $((!$#)) / $[!$#]' - both work. 'echo $((!$#)) / $[!$#]' - both echo 1 when no params, 0 when any number of params. I'm told ( https://wiki.bash-hackers.org/scripting/obsolete ) that $[...] is obsolete and that $((...)) should be used instead. OK so far. However 'N=0; echo $((!$N))' gives an error at the bash prompt. 'echo $[!$N]' echo's 1 as expected. My question - is $[...] actually obsolete? If so, what should I use at the bash prompt to get the same effect? Cheers -- Chris Elvidge
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Return from function depending on number of parameters Chris Elvidge <celvidge001@gmail.com> - 2020-07-03 19:00 +0100
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