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Groups > gnu.bash.bug > #16529

Return from function depending on number of parameters

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I've used 'return $((!$#))' and 'return $[!$#]' to return an error if no 
parameters given to function.

Tested in a bash script 'exit $((!$#)) / $[!$#]' - both work.

'echo  $((!$#)) / $[!$#]' - both echo 1 when no params, 0 when any 
number of params.

I'm told ( https://wiki.bash-hackers.org/scripting/obsolete ) that 
$[...] is obsolete and that $((...)) should be used instead. OK so far.

However 'N=0; echo $((!$N))' gives an error at the bash prompt. 'echo 
$[!$N]' echo's 1 as expected.

My question - is $[...] actually obsolete? If so, what should I use at 
the bash prompt to get the same effect?

Cheers



-- 

Chris Elvidge

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Return from function depending on number of parameters Chris Elvidge <celvidge001@gmail.com> - 2020-07-03 19:00 +0100

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