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| From | hk <hkadeveloper@gmail.com> |
| Newsgroups | gnu.bash.bug |
| Subject | Re: shouldn't it the comma operator has the lowerest precedence in the shell arithmetic expression? |
| Date | Wed, 2 Oct 2019 08:59:41 +0800 |
| Lines | 19 |
| Approved | bug-bash@gnu.org |
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sorry for the typo in the title, it should be *lowest*. On Wed, Oct 2, 2019 at 8:35 AM hk <hkadeveloper@gmail.com> wrote: > Configuration Information : > Bash Version: 5.0 > Patch Level: 0 > Release Status: release > > Description: > the code snippet from expr.c starting from line 141: > >> /* This should be the function corresponding to the operator with the >> highest precedence. */ >> #define EXP_HIGHEST expcomma > > > Am I understanding it wrong or is it a typo? >
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Re: shouldn't it the comma operator has the lowerest precedence in the shell arithmetic expression? hk <hkadeveloper@gmail.com> - 2019-10-02 08:59 +0800
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