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From: hk <hkadeveloper@gmail.com>
Newsgroups: gnu.bash.bug
Subject: Re: shouldn't it the comma operator has the lowerest precedence in the shell arithmetic expression?
Date: Wed, 2 Oct 2019 08:59:41 +0800
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Xref: csiph.com gnu.bash.bug:15449

sorry for the typo in the title, it should be *lowest*.

On Wed, Oct 2, 2019 at 8:35 AM hk <hkadeveloper@gmail.com> wrote:

> Configuration Information :
> Bash Version: 5.0
> Patch Level: 0
> Release Status: release
>
> Description:
> the code snippet from expr.c starting from line 141:
>
>> /* This should be the function corresponding to the operator with the
>>    highest precedence. */
>> #define EXP_HIGHEST expcomma
>
>
> Am I understanding it wrong or is it a typo?
>