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Re: is operator versus id() function

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On Fri, 05 Apr 2013 06:49:14 -0700, Candide Dandide wrote:

> So, could someone please explain what exactly the is operator returns ?
> The official doc says :
> 
> The ‘is‘ operator compares the identity of two objects; the id()
> function returns an integer representing its identity (currently
> implemented as its address). 

The docs are correct.

But an identity is only unique for the lifetime of the object, so
"x is y" and "id(x)==id(y)" are only equivalent if the lifetimes of
x and y overlap.

If the objects have disjoint lifetimes (i.e. one is created after the
other has been destroyed), then it's possible for id() to return the same
value for both objects, so id(x)==id(y) can return a "false positive"
result, as happened in your example.

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is operator versus id() function Candide Dandide <c.candide@laposte.net> - 2013-04-05 06:49 -0700
  Re: is operator versus id() function Arnaud Delobelle <arnodel@gmail.com> - 2013-04-05 15:53 +0100
    Re: is operator versus id() function candide <c.candide@laposte.net> - 2013-04-05 09:40 -0700
      Re: is operator versus id() function Tim Delaney <timothy.c.delaney@gmail.com> - 2013-04-06 06:57 +1100
    Re: is operator versus id() function candide <c.candide@laposte.net> - 2013-04-05 09:40 -0700
  Re: is operator versus id() function Nobody <nobody@nowhere.com> - 2013-04-06 14:35 +0100

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