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Groups > comp.lang.python > #42829
| References | <ed17e4ac-2000-42ef-aa2b-69ff421ae3fa@googlegroups.com> |
|---|---|
| Date | 2013-04-05 15:53 +0100 |
| Subject | Re: is operator versus id() function |
| From | Arnaud Delobelle <arnodel@gmail.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.144.1365173642.3114.python-list@python.org> (permalink) |
On 5 April 2013 14:49, Candide Dandide <c.candide@laposte.net> wrote: > Until now, I was quite sure that the is operator acts the same as the id builtin function, or, to be more formal, that o1 is o2 to be exactly equivalent to id(o1) == id(o2). This equivalence is reported in many books, for instance Martelli's Python in a Nutshell. > > But with the following code, I'm not still sure the equivalence above is correct. Here's the code : > > > #-------------------------------------------------------- > class A(object): > def f(self): > print "A" > > a=A() > print id(A.f) == id(a.f), A.f is a.f > #-------------------------------------------------------- > > > outputing: > > True False > > So, could someone please explain what exactly the is operator returns ? The official doc says : > > The ‘is‘ operator compares the identity of two objects; the id() function returns an integer representing its identity (currently implemented as its address). And the doc is right! >>> Af = A.f >>> af = a.f >>> print id(Af) == id(af), Af is af False False You've fallen victim to the fact that CPython is very quick to collect garbage. More precisely, when Python interprets `id(A.f) == id(a.f)`, it does the following: 1. Create a new unbound method (A.f) 2. Calculate its id 3. Now the refcount of A.f is down to 0, so it's garbage collected 4 Create a new bound method (a.f) **and very probably use the same memory slot as that of A.f** 5 Calculate its id 6 ... -- Arnaud
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is operator versus id() function Candide Dandide <c.candide@laposte.net> - 2013-04-05 06:49 -0700
Re: is operator versus id() function Arnaud Delobelle <arnodel@gmail.com> - 2013-04-05 15:53 +0100
Re: is operator versus id() function candide <c.candide@laposte.net> - 2013-04-05 09:40 -0700
Re: is operator versus id() function Tim Delaney <timothy.c.delaney@gmail.com> - 2013-04-06 06:57 +1100
Re: is operator versus id() function candide <c.candide@laposte.net> - 2013-04-05 09:40 -0700
Re: is operator versus id() function Nobody <nobody@nowhere.com> - 2013-04-06 14:35 +0100
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