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| Date | Sun, 26 Jun 2011 12:21:55 -0700 |
| Subject | Re: Default value for optional parameters unexpected behaviour? |
| From | Benjamin Kaplan <benjamin.kaplan@case.edu> |
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On Sun, Jun 26, 2011 at 11:28 AM, Marc Aymerich <glicerinu@gmail.com> wrote: > Hi, > I'm trying to define a function that has an optional parameter which > should be an empty list whenever it isn't given. However, it takes as > value the same value as the last time the function was executed. What > is the reason of this behaviour? How does python deal with default > values (i.e. when are they assigned/created)? > > Thanks :) > So the thing about Python is that you don't actually declare functions. You create them. def is an executable statement that creates a function object. Default arguments are part of the function object, so they get evaluated when the function is created. >>> foo Traceback (most recent call last): File "<stdin>", line 1, in <module> NameError: name 'foo' is not defined >>> def foo(a = []) : ... a.append(1) ... >>> foo.func_defaults ([],) >>> foo() >>> foo.func_defaults ([1],) >>>
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Default value for optional parameters unexpected behaviour? Marc Aymerich <glicerinu@gmail.com> - 2011-06-26 11:28 -0700 Re: Default value for optional parameters unexpected behaviour? Shashank Singh <shashank.sunny.singh@gmail.com> - 2011-06-27 00:09 +0530 Re: Default value for optional parameters unexpected behaviour? Corey Richardson <kb1pkl@aim.com> - 2011-06-26 14:36 -0400 Re: Default value for optional parameters unexpected behaviour? Noah Hall <enalicho@gmail.com> - 2011-06-26 19:45 +0100 Re: Default value for optional parameters unexpected behaviour? Terry Reedy <tjreedy@udel.edu> - 2011-06-26 14:46 -0400 Re: Default value for optional parameters unexpected behaviour? Benjamin Kaplan <benjamin.kaplan@case.edu> - 2011-06-26 12:21 -0700 Re: Default value for optional parameters unexpected behaviour? Corey Richardson <kb1pkl@aim.com> - 2011-06-26 15:23 -0400
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