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Re: Default value for optional parameters unexpected behaviour?

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Excerpts from Marc Aymerich's message of Sun Jun 26 14:28:30 -0400 2011:
> Hi,
> I'm trying to define a function that has an optional parameter which
> should be an empty list whenever it isn't given. However, it takes as
> value the same value as the last time the function was executed. What
> is the reason of this behaviour? How does python deal with default
> values (i.e. when are they assigned/created)?
> 
> Thanks :)
> 

Really common mistake, I made it myself too. When Python evaluates the 
function, it sees the default parameter of `foo' as the new object you
create with []. It keeps that object around. The proper idiom instead of

> >>> def a(foo=[]):
> ...  foo.append(1)
> ...  print foo
> ...

is

def a(foo=None):
	if foo is None:
		foo = []
	foo.append(1)
	print foo
-- 
Corey Richardson
  "Those who deny freedom to others, deserve it not for themselves"
     -- Abraham Lincoln

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Default value for optional parameters unexpected behaviour? Marc Aymerich <glicerinu@gmail.com> - 2011-06-26 11:28 -0700
  Re: Default value for optional parameters unexpected behaviour? Shashank Singh <shashank.sunny.singh@gmail.com> - 2011-06-27 00:09 +0530
  Re: Default value for optional parameters unexpected behaviour? Corey Richardson <kb1pkl@aim.com> - 2011-06-26 14:36 -0400
  Re: Default value for optional parameters unexpected behaviour? Noah Hall <enalicho@gmail.com> - 2011-06-26 19:45 +0100
  Re: Default value for optional parameters unexpected behaviour? Terry Reedy <tjreedy@udel.edu> - 2011-06-26 14:46 -0400
  Re: Default value for optional parameters unexpected behaviour? Benjamin Kaplan <benjamin.kaplan@case.edu> - 2011-06-26 12:21 -0700
  Re: Default value for optional parameters unexpected behaviour? Corey Richardson <kb1pkl@aim.com> - 2011-06-26 15:23 -0400

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