Re: Generating Filenames from Feeds

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Date	Thu, 14 Mar 2013 12:05:05 -0400
Subject	Re: Generating Filenames from Feeds
From	Joel Goldstick <joel.goldstick@gmail.com>
To	Chuck <galois271@gmail.com>
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On Thu, Mar 14, 2013 at 11:38 AM, Chuck <galois271@gmail.com> wrote:

> HI all,
>
> I am trying to write a podcast catcher for fun, and I am trying to come up
> with a way to generate a destination filename to use in the function
> urlretrieve(url, destination).  I  would like the destination filename to
> end in a .mp3 extension.
>
> My first attempts were parsing out the <pubdate> and stripping the
> whitespace characters, and joining with os.path.join.  I haven't been able
> to make that work for some reason.


The reason is apparently a  syntax error.

Whenever I put the .mp3 in the os.path.join I get syntax errors.  I am
> wondering if there is a better way?
>

Yes, don't write code with syntax errors!

>
> I was doing something like
> os.path.join('C:\\Users\\Me\\Music\\Podcasts\\', pubdate.mp3), where
> pubdate has been parsed and stripped of whitespace.  I keep getting an
> error around the .mp3.
>
> Any ideas?
>

Seriously, if you don't post a minimal code example that shows the problem
and with a full traceback you are asking strangers to do magic tricks for
your pleasure.

>
> Thanks!!
> Chuck
> --
> http://mail.python.org/mailman/listinfo/python-list
>



-- 
Joel Goldstick
http://joelgoldstick.com

Thread

Generating Filenames from Feeds Chuck <galois271@gmail.com> - 2013-03-14 08:38 -0700
  Re: Generating Filenames from Feeds Joel Goldstick <joel.goldstick@gmail.com> - 2013-03-14 12:05 -0400
    Re: Generating Filenames from Feeds Chuck <galois271@gmail.com> - 2013-03-14 11:19 -0700
      Re: Generating Filenames from Feeds Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2013-03-14 22:58 +0000
    Re: Generating Filenames from Feeds Chuck <galois271@gmail.com> - 2013-03-14 11:19 -0700
  Re: Generating Filenames from Feeds MRAB <python@mrabarnett.plus.com> - 2013-03-14 16:07 +0000

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