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Date: Thu, 14 Mar 2013 12:05:05 -0400
Subject: Re: Generating Filenames from Feeds
From: Joel Goldstick <joel.goldstick@gmail.com>
To: Chuck <galois271@gmail.com>
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On Thu, Mar 14, 2013 at 11:38 AM, Chuck <galois271@gmail.com> wrote:

> HI all,
>
> I am trying to write a podcast catcher for fun, and I am trying to come up
> with a way to generate a destination filename to use in the function
> urlretrieve(url, destination).  I  would like the destination filename to
> end in a .mp3 extension.
>
> My first attempts were parsing out the <pubdate> and stripping the
> whitespace characters, and joining with os.path.join.  I haven't been able
> to make that work for some reason.


The reason is apparently a  syntax error.

Whenever I put the .mp3 in the os.path.join I get syntax errors.  I am
> wondering if there is a better way?
>

Yes, don't write code with syntax errors!

>
> I was doing something like
> os.path.join('C:\\Users\\Me\\Music\\Podcasts\\', pubdate.mp3), where
> pubdate has been parsed and stripped of whitespace.  I keep getting an
> error around the .mp3.
>
> Any ideas?
>

Seriously, if you don't post a minimal code example that shows the problem
and with a full traceback you are asking strangers to do magic tricks for
your pleasure.

>
> Thanks!!
> Chuck
> --
> http://mail.python.org/mailman/listinfo/python-list
>



-- 
Joel Goldstick
http://joelgoldstick.com

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<div dir=3D"ltr"><br><div class=3D"gmail_extra"><br><br><div class=3D"gmail=
_quote">On Thu, Mar 14, 2013 at 11:38 AM, Chuck <span dir=3D"ltr">&lt;<a hr=
ef=3D"mailto:galois271@gmail.com" target=3D"_blank">galois271@gmail.com</a>=
&gt;</span> wrote:<br>
<blockquote class=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;border-left:1p=
x #ccc solid;padding-left:1ex">HI all,<br>
<br>
I am trying to write a podcast catcher for fun, and I am trying to come up =
with a way to generate a destination filename to use in the function urlret=
rieve(url, destination). =C2=A0I =C2=A0would like the destination filename =
to end in a .mp3 extension.<br>

<br>
My first attempts were parsing out the &lt;pubdate&gt; and stripping the wh=
itespace characters, and joining with os.path.join. =C2=A0I haven&#39;t bee=
n able to make that work for some reason. </blockquote><div><br></div><div>
The reason is apparently a=C2=A0 syntax error.=C2=A0 <br><br></div><blockqu=
ote class=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;border-left:1px #ccc s=
olid;padding-left:1ex">Whenever I put the .mp3 in the os.path.join I get sy=
ntax errors. =C2=A0I am wondering if there is a better way?<br>
</blockquote><div><br></div><div>Yes, don&#39;t write code with syntax erro=
rs! <br></div><blockquote class=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;=
border-left:1px #ccc solid;padding-left:1ex">
<br>
I was doing something like os.path.join(&#39;C:\\Users\\Me\\Music\\Podcasts=
\\&#39;, pubdate.mp3), where pubdate has been parsed and stripped of whites=
pace. =C2=A0I keep getting an error around the .mp3.<br>
<br>
Any ideas?<br></blockquote><div><br></div><div>Seriously, if you don&#39;t =
post a minimal code example that shows the problem and with a full tracebac=
k you are asking strangers to do magic tricks for your pleasure. <br></div>
<blockquote class=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;border-left:1p=
x #ccc solid;padding-left:1ex">
<br>
Thanks!!<br>
<span class=3D"HOEnZb"><font color=3D"#888888">Chuck<br>
--<br>
<a href=3D"http://mail.python.org/mailman/listinfo/python-list" target=3D"_=
blank">http://mail.python.org/mailman/listinfo/python-list</a><br>
</font></span></blockquote></div><br><br clear=3D"all"><br>-- <br><div dir=
=3D"ltr"><div>Joel Goldstick<br></div><a href=3D"http://joelgoldstick.com" =
target=3D"_blank">http://joelgoldstick.com</a><br></div>
</div></div>

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