Generating Filenames from Feeds

Newsgroups	comp.lang.python
Date	2013-03-14 08:38 -0700
Message-ID	<a8aaf0a9-de8e-476f-9a34-e75694112802@googlegroups.com> (permalink)
Subject	Generating Filenames from Feeds
From	Chuck <galois271@gmail.com>

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HI all,

I am trying to write a podcast catcher for fun, and I am trying to come up with a way to generate a destination filename to use in the function urlretrieve(url, destination).  I  would like the destination filename to end in a .mp3 extension.  

My first attempts were parsing out the <pubdate> and stripping the whitespace characters, and joining with os.path.join.  I haven't been able to make that work for some reason.  Whenever I put the .mp3 in the os.path.join I get syntax errors.  I am wondering if there is a better way?

I was doing something like os.path.join('C:\\Users\\Me\\Music\\Podcasts\\', pubdate.mp3), where pubdate has been parsed and stripped of whitespace.  I keep getting an error around the .mp3.

Any ideas?

Thanks!!
Chuck

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Generating Filenames from Feeds Chuck <galois271@gmail.com> - 2013-03-14 08:38 -0700
  Re: Generating Filenames from Feeds Joel Goldstick <joel.goldstick@gmail.com> - 2013-03-14 12:05 -0400
    Re: Generating Filenames from Feeds Chuck <galois271@gmail.com> - 2013-03-14 11:19 -0700
      Re: Generating Filenames from Feeds Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2013-03-14 22:58 +0000
    Re: Generating Filenames from Feeds Chuck <galois271@gmail.com> - 2013-03-14 11:19 -0700
  Re: Generating Filenames from Feeds MRAB <python@mrabarnett.plus.com> - 2013-03-14 16:07 +0000

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