Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]

Groups > comp.lang.python > #47616

Re: Split a list into two parts based on a filter?

Path csiph.com!v102.xanadu-bbs.net!xanadu-bbs.net!feeder.erje.net!eu.feeder.erje.net!newsfeed.xs4all.nl!newsfeed1.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail
Return-Path <fabiosantosart@gmail.com>
X-Original-To python-list@python.org
Delivered-To python-list@mail.python.org
X-Spam-Status OK 0.016
X-Spam-Evidence '*H*': 0.97; '*S*': 0.00; 'subject:two': 0.07; '[],': 0.09; 'subject:into': 0.09; 'cc:addr:python-list': 0.11; 'subject:based': 0.16; 'wrote:': 0.18; 'version.': 0.19; 'cc:addr:python.org': 0.22; 'cc:2**0': 0.24; 'cc:no real name:2**0': 0.24; '&gt;': 0.26; 'header:In-Reply-To:1': 0.27; 'subject:list': 0.30; 'message-id:@mail.gmail.com': 0.30; "i'm": 0.30; 'could': 0.34; 'something': 0.35; 'but': 0.35; 'received:google.com': 0.35; 'subject:?': 0.36; 'skip:o 20': 0.38; 'sure': 0.39; '2013': 0.98
DKIM-Signature v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:in-reply-to:references:date:message-id:subject:from:to :cc:content-type; bh=unaMFcN2ECWmXUzOZiOIAczQA6HJMBRBZVfC23mF2DM=; b=DJQOAeppJnvT1jSxidDVcYMRVVSJPz45sKFO2sexb1YAolfgZ4slGsJfCe+vpg6FuS GARo38TSUjS5W2Mu8R4hilpyox0BSefK5PUeEqkFL5Kp+OhRXoZuHYHwjgQ39Ok1zgrH ZLe2H8/yRo8ybFNiNaf24Irj5vS69kXIQ+1eY0N1UuqxKugE8JSGszUs34nJWsB4xSq3 Ao2PVXWe/snMFFDbR0stlSqg3z04vHW9B8gLwfE/p2mFiTdKpMbMY4DopW0eS3/iwi2W 8569zroGpgbvp2qdFXCLrPVDZ7l0HS/lP4PHReLUIPlGwWliauXkf1ZYJFGuEybmgz/z mVHg==
MIME-Version 1.0
X-Received by 10.224.106.195 with SMTP id y3mr13886884qao.35.1370905726238; Mon, 10 Jun 2013 16:08:46 -0700 (PDT)
In-Reply-To <kp5l7h$2rp$1@ger.gmane.org>
References <kp5d9e$2hf$1@panix2.panix.com> <kp5l7h$2rp$1@ger.gmane.org>
Date Tue, 11 Jun 2013 00:08:46 +0100
Subject Re: Split a list into two parts based on a filter?
From Fábio Santos <fabiosantosart@gmail.com>
To Roel Schroeven <roel@roelschroeven.net>
Content-Type multipart/alternative; boundary=20cf3074b33ad547c804ded4dce5
Cc python-list@python.org
X-BeenThere python-list@python.org
X-Mailman-Version 2.1.15
Precedence list
List-Id General discussion list for the Python programming language <python-list.python.org>
List-Unsubscribe <http://mail.python.org/mailman/options/python-list>, <mailto:python-list-request@python.org?subject=unsubscribe>
List-Archive <http://mail.python.org/pipermail/python-list/>
List-Post <mailto:python-list@python.org>
List-Help <mailto:python-list-request@python.org?subject=help>
List-Subscribe <http://mail.python.org/mailman/listinfo/python-list>, <mailto:python-list-request@python.org?subject=subscribe>
Newsgroups comp.lang.python
Message-ID <mailman.2996.1370905734.3114.python-list@python.org> (permalink)
Lines 29
NNTP-Posting-Host 2001:888:2000:d::a6
X-Trace 1370905734 news.xs4all.nl 15975 [2001:888:2000:d::a6]:35318
X-Complaints-To abuse@xs4all.nl
Xref csiph.com comp.lang.python:47616

Show key headers only | View raw

[Multipart message — attachments visible in raw view] - view raw

On 10 Jun 2013 23:54, "Roel Schroeven" <roel@roelschroeven.net> wrote:
>
> You could do something like:
>
> new_songs, old_songs = [], []
> [(new_songs if s.is_new() else old_songs).append(s) for s in songs]
>
> But I'm not sure that that's any better than the long version.

This is so beautiful!

Back to comp.lang.python | Previous | Next — Previous in thread | Next in thread | Find similar | Unroll thread

Thread

Split a list into two parts based on a filter? roy@panix.com (Roy Smith) - 2013-06-10 16:34 -0400
  Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-11 08:50 +1000
  Re: Split a list into two parts based on a filter? Roel Schroeven <roel@roelschroeven.net> - 2013-06-11 00:50 +0200
    Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-11 00:11 -0400
      Re: Split a list into two parts based on a filter? Serhiy Storchaka <storchaka@gmail.com> - 2013-06-11 18:27 +0300
        Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-11 20:33 -0400
          Re: Split a list into two parts based on a filter? Phil Connell <pconnell@gmail.com> - 2013-06-12 07:32 +0100
            Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-12 07:39 -0400
              Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-12 12:51 +0100
              Re: Split a list into two parts based on a filter? Jussi Piitulainen <jpiitula@ling.helsinki.fi> - 2013-06-12 15:06 +0300
              Re: Split a list into two parts based on a filter? Terry Reedy <tjreedy@udel.edu> - 2013-06-12 14:07 -0400
          Re: Split a list into two parts based on a filter? Serhiy Storchaka <storchaka@gmail.com> - 2013-06-12 19:28 +0300
          Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-12 17:57 +0100
          Re: Split a list into two parts based on a filter? Terry Reedy <tjreedy@udel.edu> - 2013-06-12 14:47 -0400
          Re: Split a list into two parts based on a filter? Oscar Benjamin <oscar.j.benjamin@gmail.com> - 2013-06-13 10:43 +0100
  Re: Split a list into two parts based on a filter? Chris Rebert <clp2@rebertia.com> - 2013-06-10 16:03 -0700
  Re: Split a list into two parts based on a filter? Tim Chase <python.list@tim.thechases.com> - 2013-06-10 18:10 -0500
  Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 00:08 +0100
    Re: Split a list into two parts based on a filter? alex23 <wuwei23@gmail.com> - 2013-06-11 17:44 -0700
  Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-11 09:12 +1000
  Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 02:11 +0200
  Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 08:43 +0200
  Re: Split a list into two parts based on a filter? Jonas Geiregat <jonas@geiregat.org> - 2013-06-11 08:47 +0200
  Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 14:48 +0100
    Re: Split a list into two parts based on a filter? rusi <rustompmody@gmail.com> - 2013-06-11 09:37 -0700
      Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 18:05 +0100
        Re: Split a list into two parts based on a filter? rusi <rustompmody@gmail.com> - 2013-06-11 10:23 -0700
          Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-12 03:37 +1000
            Re: Split a list into two parts based on a filter? rusi <rustompmody@gmail.com> - 2013-06-11 11:13 -0700
          Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 19:05 +0100
  Re: Split a list into two parts based on a filter? Joshua Landau <joshua.landau.ws@gmail.com> - 2013-06-11 15:22 +0100
  Re: Split a list into two parts based on a filter? Serhiy Storchaka <storchaka@gmail.com> - 2013-06-11 18:28 +0300
  Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-12 03:28 +1000
    Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-11 20:12 -0400
  Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 20:13 +0200
  Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 20:18 +0200
  Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-12 04:27 +1000
  Re: Split a list into two parts based on a filter? Roel Schroeven <roel@roelschroeven.net> - 2013-06-11 22:22 +0200

csiph-web