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Date: Tue, 11 Jun 2013 00:08:46 +0100
Subject: Re: Split a list into two parts based on a filter?
From: =?ISO-8859-1?Q?F=E1bio_Santos?= <fabiosantosart@gmail.com>
To: Roel Schroeven <roel@roelschroeven.net>
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Xref: csiph.com comp.lang.python:47616

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On 10 Jun 2013 23:54, "Roel Schroeven" <roel@roelschroeven.net> wrote:
>
> You could do something like:
>
> new_songs, old_songs = [], []
> [(new_songs if s.is_new() else old_songs).append(s) for s in songs]
>
> But I'm not sure that that's any better than the long version.

This is so beautiful!

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<p dir="ltr"><br>
On 10 Jun 2013 23:54, &quot;Roel Schroeven&quot; &lt;<a href="mailto:roel@roelschroeven.net">roel@roelschroeven.net</a>&gt; wrote:<br>
&gt;<br>
&gt; You could do something like:<br>
&gt;<br>
&gt; new_songs, old_songs = [], []<br>
&gt; [(new_songs if s.is_new() else old_songs).append(s) for s in songs]<br>
&gt;<br>
&gt; But I&#39;m not sure that that&#39;s any better than the long version.</p>
<p dir="ltr">This is so beautiful!</p>

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