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Groups > comp.lang.python > #47661
| References | <kp5d9e$2hf$1@panix2.panix.com> <kp5l7h$2rp$1@ger.gmane.org> <CAA=1kxRWvN8rqTZ+HQb1y5jzWgL0gAu+GBqU8b=XYsQT4pGg2g@mail.gmail.com> <kp6gu4$q4r$1@ger.gmane.org> |
|---|---|
| Date | 2013-06-11 14:48 +0100 |
| Subject | Re: Split a list into two parts based on a filter? |
| From | Fábio Santos <fabiosantosart@gmail.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.3020.1370958503.3114.python-list@python.org> (permalink) |
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On 11 Jun 2013 07:47, "Peter Otten" <__peter__@web.de> wrote: > > Fábio Santos wrote: > > > On 10 Jun 2013 23:54, "Roel Schroeven" <roel@roelschroeven.net> wrote: > >> > >> You could do something like: > >> > >> new_songs, old_songs = [], [] > >> [(new_songs if s.is_new() else old_songs).append(s) for s in songs] > >> > >> But I'm not sure that that's any better than the long version. > > > > This is so beautiful! > > It makes me cringe. > > This code does spurious work to turn what is naturally written as a for loop > into a list comprehension that is thrown away immediately. I think I'd even > prefer this "gem" > > >>> evens = [] > >>> odds = [item for item in range(10) if item % 2 or evens.append(item)] > >>> evens, odds > ([0, 2, 4, 6, 8], [1, 3, 5, 7, 9]) > > but if I have my way every side effect in a list comprehension should be > punished with an extra hour of bug-hunting ;) > What I like so much about it is the .. if .. else .. Within the parenthesis and the append() call outside these parenthesis. I agree it would be best written as a for loop, to increase readability and avoid confusion. I always expect list comprehensions to be used as expressions, and its use as a (single-expression) statement is rather odd. On 11 Jun 2013 07:52, "Jonas Geiregat" <jonas@geiregat.org> wrote: > I must disagree , this is unreadable and in my honor opinion not Pythonic at all. > I've learned it's always better to be explicit then implicit, and this snippet of code does a lot in an implicit way. > (Read above)
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Split a list into two parts based on a filter? roy@panix.com (Roy Smith) - 2013-06-10 16:34 -0400
Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-11 08:50 +1000
Re: Split a list into two parts based on a filter? Roel Schroeven <roel@roelschroeven.net> - 2013-06-11 00:50 +0200
Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-11 00:11 -0400
Re: Split a list into two parts based on a filter? Serhiy Storchaka <storchaka@gmail.com> - 2013-06-11 18:27 +0300
Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-11 20:33 -0400
Re: Split a list into two parts based on a filter? Phil Connell <pconnell@gmail.com> - 2013-06-12 07:32 +0100
Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-12 07:39 -0400
Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-12 12:51 +0100
Re: Split a list into two parts based on a filter? Jussi Piitulainen <jpiitula@ling.helsinki.fi> - 2013-06-12 15:06 +0300
Re: Split a list into two parts based on a filter? Terry Reedy <tjreedy@udel.edu> - 2013-06-12 14:07 -0400
Re: Split a list into two parts based on a filter? Serhiy Storchaka <storchaka@gmail.com> - 2013-06-12 19:28 +0300
Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-12 17:57 +0100
Re: Split a list into two parts based on a filter? Terry Reedy <tjreedy@udel.edu> - 2013-06-12 14:47 -0400
Re: Split a list into two parts based on a filter? Oscar Benjamin <oscar.j.benjamin@gmail.com> - 2013-06-13 10:43 +0100
Re: Split a list into two parts based on a filter? Chris Rebert <clp2@rebertia.com> - 2013-06-10 16:03 -0700
Re: Split a list into two parts based on a filter? Tim Chase <python.list@tim.thechases.com> - 2013-06-10 18:10 -0500
Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 00:08 +0100
Re: Split a list into two parts based on a filter? alex23 <wuwei23@gmail.com> - 2013-06-11 17:44 -0700
Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-11 09:12 +1000
Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 02:11 +0200
Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 08:43 +0200
Re: Split a list into two parts based on a filter? Jonas Geiregat <jonas@geiregat.org> - 2013-06-11 08:47 +0200
Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 14:48 +0100
Re: Split a list into two parts based on a filter? rusi <rustompmody@gmail.com> - 2013-06-11 09:37 -0700
Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 18:05 +0100
Re: Split a list into two parts based on a filter? rusi <rustompmody@gmail.com> - 2013-06-11 10:23 -0700
Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-12 03:37 +1000
Re: Split a list into two parts based on a filter? rusi <rustompmody@gmail.com> - 2013-06-11 11:13 -0700
Re: Split a list into two parts based on a filter? Fábio Santos <fabiosantosart@gmail.com> - 2013-06-11 19:05 +0100
Re: Split a list into two parts based on a filter? Joshua Landau <joshua.landau.ws@gmail.com> - 2013-06-11 15:22 +0100
Re: Split a list into two parts based on a filter? Serhiy Storchaka <storchaka@gmail.com> - 2013-06-11 18:28 +0300
Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-12 03:28 +1000
Re: Split a list into two parts based on a filter? Roy Smith <roy@panix.com> - 2013-06-11 20:12 -0400
Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 20:13 +0200
Re: Split a list into two parts based on a filter? Peter Otten <__peter__@web.de> - 2013-06-11 20:18 +0200
Re: Split a list into two parts based on a filter? Chris Angelico <rosuav@gmail.com> - 2013-06-12 04:27 +1000
Re: Split a list into two parts based on a filter? Roel Schroeven <roel@roelschroeven.net> - 2013-06-11 22:22 +0200
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