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Re: Built-in open() with buffering > 1

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On 08/24/2012 06:35 AM, Marco wrote:
> Please, can anyone explain me the meaning of the
> "buffering > 1" in the built-in open()?
> The doc says: "...and an integer > 1 to indicate the size
> of a fixed-size chunk buffer."

Sorry, I get it:

 >>> f = open('myfile', 'w', buffering=2)
 >>> f._CHUNK_SIZE = 5
 >>> for i in range(6):
...     n = f.write(str(i))
...     print(i, open('myfile').read(), sep=':')
...
0:
1:
2:
3:
4:
5:012345

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Built-in open() with buffering > 1 Marco <marco_u@nsgmail.com> - 2012-08-24 06:35 +0200
  Re: Built-in open() with buffering > 1 Marco <marco_u@nsgmail.com> - 2012-08-24 07:21 +0200
    Re: Built-in open() with buffering > 1 Ramchandra Apte <maniandram01@gmail.com> - 2012-08-24 07:32 -0700
  Re: Built-in open() with buffering > 1 Hans Mulder <hansmu@xs4all.nl> - 2012-08-26 10:25 +0200
    Re: Built-in open() with buffering > 1 Marco <marco_u@nsgmail.com> - 2012-08-30 17:39 +0200

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